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Hi Bobbym,
I actually just wanted help to do the equation my self, not have someone else do it for me but thank you very much!
And Bob I thank you too for your help!
Sent in the lesson and got 20/20.:cool:
I have a rectangle, with a length of 7 and a width of 4:
15. What is the perimeter? - Answer: E
A 31
B 26
C 58
D 35
E 22
F 59
16. What is the area? - Answer: A
A 28
B 65
C 79
D 13
E 10
F 19
This rectangle just became the base of a regular prism, with a height of 6:
17. What is the lateral area? - Answer: F
A 119
B 873
C 256
D 349
E 332
F 132
18. What is the total surface area? - Answer: D
A 119
B 873
C 256
D 188
E 332
F 132
19. What is the volume? - Answer: E
A 651
B 327
C 395
D 221
E 168
F 342
20. What is the area of the largest rectangular side? - Answer: D
A 65
B 32
C 36
D 42
E 16
F 34
Last 10 to go!
I have an isosceles triangle with a height of 4 and a base of 6:
11. What is the area? - Answer: C
A 19
B 35
C 12
D 16
E 22
F 54
This triangle just became the base of a regular prism, with a height of 8:
12. What is the lateral area? - Answer: D
A 105
B 28
C 35
D 128
E 56
F 12
13. What is the volume? **need help solving
A 95
B 54
C 32
D 23
E 96
F 10
14. What is the area of the largest rectangular side? - Answer: D
A 95
B 54
C 32
D 48
E 96
F 10
The shape is a pyramid with:
6. a rectangular base with a width of 4
A Lateral area: 120; Volume: 98
B Lateral area: 192; Volume: 76
C Lateral area: 240; Volume: 51
D Lateral area: 176; Volume: 33
E Lateral area: 288; Volume: 75
F Lateral area: 100; Volume: 64
Volume:
a = 6 x 4
a = 24
v = 1/3 x 24 x 8
v = 64
Lateral Area:
6 + 4 + 6 + 4 = 20
20 x .50 = 10
10 x 10 = 100
Answer: F
7. a square base
A Lateral area: 120; Volume: 96
B Lateral area: 90; Volume: 64
C Lateral area: 176; Volume: 144
D Lateral area: 192; Volume: 35
E Lateral area: 288; Volume: 288
F Lateral area: 240; Volume: 75
Volume:
a = 6 x 6
a = 36
v = 1/3 x 36 x 8
v = 96
Lateral Area:
6 + 6 + 6 + 6 = 24
24 x .50 = 12
12 x 10 = 120
Answer: A
8. a rectangular base with a width of 3
A Lateral area: 192; Volume: 144
B Lateral area: 90; Volume: 48
C Lateral area: 276; Volume: 64
D Lateral area: 176; Volume: 144
E Lateral area: 92; Volume: 96
F Lateral area: 62; Volume: 24
Volume:
a = 6 x 3
a = 18
v = 1/3 x 18 x 8
v = 48
Lateral Area:
3 + 6 + 3 + 6 = 18
18 x .50 = 9
9 x 10 = 90
Answer: B
9. a rectangular base with a width of 5
A Lateral area: 100; Volume: 48
B Lateral area: 240; Volume: 112
C Lateral area: 176; Volume: 96
D Lateral area: 110; Volume: 80
E Lateral area: 288; Volume: 144
F Lateral area: 90; Volume: 64
Volume:
a = 5 x 6
a = 30
v = 1/3 x 30 x 8
v = 80
Lateral Area:
6 + 5 + 6 + 5 = 22
22 x .50 = 11
11 x 10 = 110
Answer: D
10. a rectangular base with a width of 7
A Lateral area: 240; Volume: 64
B Lateral area: 188; Volume: 96
C Lateral area: 176; Volume: 144
D Lateral area: 130; Volume: 112
E Lateral area: 144; Volume: 215
F Lateral area: 100; Volume: 128
Volume:
a = 6 x 7
a = 42
v = 1/3 x 42 x 8
v = 112
Lateral Area:
7 + 6 + 7 + 6 = 26
26 x .50 = 13
13 x 10 = 130
Answer: D
It's interesting to see two math geniuses at work
The shape is a pyramid with:
6. a rectangular base with a width of 4
A Lateral area: 120; Volume: 98
B Lateral area: 192; Volume: 76
C Lateral area: 240; Volume: 51
D Lateral area: 176; Volume: 33
E Lateral area: 288; Volume: 75
F Lateral area: 100; Volume: 64
So this is what I did. First I got the area of the rectangle:
a = 6 x 4
a = 24
v = 1/3 x 24 x 8
v = 64
That's what I'm getting for the volume.
As for the lateral area, would I have to do:
2 x 6 x 8
2 x 4 x 8
Get the answers for these, add them together to get the perimeter and then move on?
Well this is what my lesson says and shows:
"Regular Pyramid Area Theorem
The area L of any regular pyramid with a base that has perimeter P and with slant height l is equal to one-half the product of the perimeter and the slant height.
Formula: L = (1/2)(P)l"
"A pyramid is a polyhedron with a single base and lateral faces that are all triangular. All lateral edges of a pyramid meet at a single point, or vertex. A regular pyramid is a pyramid that has a base that is a regular polygon and with lateral faces that are all congruent isosceles triangles.
At any rate, the equations for area and volume are just like all the others we've done--just plug in the numbers.
If a regular pyramid has a square base with a length and width of 3, and slant height of 5, and a height of 4 then what is the area of the pyramid, and what is the pyramid's volume.
L = (1/2)(P)l
L = (1/2)(12)5
L = 30
V = (1/3)Bh
V = (1/3)9(4)
V = 12
"
So I guess the Slant Height is used for finding the Lateral Area. I have a question though, is the Perimeter the same thing as the area of the Base?
And I would try to do #6 my self but I am visiting my grandparents at the moment so it will have to wait for now
Math is my only weakest subject I'm not too good at it. It takes me time to understand how to do things : /
so if h = 1.5 {sqrt 15}, then
a = 1/2 x 3 x 1.5 {sqrt 15}
a = 2.25 {sqrt 15}
v = 8 x 2.25 {sqrt 15}
v = 18 {sqrt 15} FINALLY. first 5 done and another 15 to go o_O
So now for the second set of 5 questions:
!we should keep in mind!
For 1 through 10, what is the area and volume of the given shape, if the length of one side of the base is 6, the height is 8, and the slant height is 10? (Not all shapes will require all three numbers.)
~~~
It seems as if the slant height was meant for these pyramid shapes.
The shape is a pyramid with:
6. a rectangular base with a width of 4
A Lateral area: 120; Volume: 98
B Lateral area: 192; Volume: 76
C Lateral area: 240; Volume: 51
D Lateral area: 176; Volume: 33
E Lateral area: 288; Volume: 75
F Lateral area: 100; Volume: 64
7. a square base
A Lateral area: 120; Volume: 96
B Lateral area: 90; Volume: 64
C Lateral area: 176; Volume: 144
D Lateral area: 192; Volume: 35
E Lateral area: 288; Volume: 288
F Lateral area: 240; Volume: 75
8. a rectangular base with a width of 3
A Lateral area: 192; Volume: 144
BLateral area: 90; Volume: 48
CLateral area: 276; Volume: 64
DLateral area: 176; Volume: 144
E Lateral area: 92; Volume: 96
F Lateral area: 62; Volume: 24
9. a rectangular base with a width of 5
A Lateral area: 100; Volume: 48
B Lateral area: 240; Volume: 112
C Lateral area: 176; Volume: 96
D Lateral area: 110; Volume: 80
E Lateral area: 288; Volume: 144
F Lateral area: 90; Volume: 64
10. a rectangular base with a width of 7
A Lateral area: 240; Volume: 64
B Lateral area: 188; Volume: 96
C Lateral area: 176; Volume: 144
D Lateral area: 130; Volume: 112
E Lateral area: 144; Volume: 215
F Lateral area: 100; Volume: 128
h^2 + 1.5^2 = 4^2 x 1.5^2
h^2 + 1.5 = 16 x 1.5
I am really confused I have no idea what I'm doing.
Ok, so:
h^2 + 1.5^2 = 4^2 x 1.5^2
h^2 + 1.5^2 = 16 x 1.5^2
h^2 + 1.5^2 = 24^2
is that right so far?
Ok I will use Pythagorean theorem to find the height.
h^2 + 1.5^2 = 6^2
h^2 + 2.25 = 36
h^2 = 33.75
h = 5.80
v = 1.5 x 5.80 x 8
v = 69.6
I still don't know what's going wrong. Could you give me an example of how to find the area of this triangle?
Also, I had an idea for getting the lateral area:
2 x 6 x 8 = 96
1 x 3 x 8 = 24
96 + 24 = 120
L = 120
5. the base is an isosceles triangle with a height of 8 and a base of 3 (sides of 6)
A Lateral area: 120; Volume: 18*sqrt(15)
B Lateral area: 100; Volume: 96
C Lateral area: 192; Volume: 144
D Lateral area: 176; Volume: 18*sqrt(15)
E Lateral area: 288; Volume: 288
F Lateral area: 240; Volume: 64
Now for #1 I was using the base and half the base (which was 6 & 3) so I am assuming I do the same here. So it would be:
h = sqrt{3^2 - 1.5^2}
h = sqrt{9 - 2.25}
h = sqrt{6.75}
h = .45 {sqrt 15}
a = 1/2 x 3 x .45 {sqrt 15}
a = 0.675
v = 0.675 x 8 = 5.4 {sqrt 15}
And that looks terribly wrong...
Lateral Area:
3 x 8 = 24
3 x 24 = 72
This is what I created for #5. Am I correct with this image?
Sorry if it's so huge I'm trying to figure out how to work this image upload thing
(literally same as #2)
4. a rectangular base with a width of 5
A Lateral area: 288; Volume: 96
BLateral area: 120; Volume: 248
CLateral area: 240; Volume: 144
D Lateral area: 192; Volume: 48
E Lateral area: 176; Volume: 240
F Lateral area: 100; Volume: 64
Volume:
A = 5 x 6
A = 30
V = 30 x 8
V = 240
Lateral Area:
2 x 6 x 8 = 96
2 x 5 x 8 = 80
96 + 80 = 176
Answer: E
5. the base is an isosceles triangle with a height of 8 and a base of 3 (sides of 6)
A Lateral area: 120; Volume: 18*sqrt(15)
B Lateral area: 100; Volume: 96
C Lateral area: 192; Volume: 144
D Lateral area: 176; Volume: 18*sqrt(15)
E Lateral area: 288; Volume: 288
F Lateral area: 240; Volume: 64
Would I be using the same method as #1 to get the volume & lateral area for this?
2. a rectangular base with a width of 3
A Lateral area: 192; Volume: 144 sqrt(3)
B Lateral area: 144; Volume: 144
C Lateral area: 90; Volume: 240
D Lateral area: 120; Volume: 288
E Lateral area: 192; Volume: 64
F Lateral area: 144; Volume: 18*sqrt(15)
So the base of the rectangle has sides of 3 and 6. So:
Volume:
A = 3 x 6 This is the area of the end rectangle (18). Pythagoras and square roots are unnecessary as you have the area at this point.
A = 18
V = 18 x 8= 144
Lateral Area:
So would it be:
2 x 6 x 8 = 96
2 x 3 x 8= 48
96 + 48 = 144 again... which means answer should be B?
3. a square base
A Lateral area: 176; Volume: 240
BLateral area: 90; Volume: 64
CLateral area: 120; Volume: 144
DLateral area: 288; Volume: 144 sqrt(3)
E Lateral area: 144; Volume: 18*sqrt(15)
F Lateral area: 192; Volume: 288
Since it's a square base, all sides are equal, which means all sides measure 6. So:
Volume:
A = 6 x 6 = 36
V = 36 x 8 = 288
Lateral Area: (there are FOUR lateral faces for a square )
6 x 8 = 48
4 x 48 = 192.
Answer is F.
2. a rectangular base with a width of 3
A Lateral area: 192; Volume: 144 sqrt(3)
B Lateral area: 144; Volume: 144
C Lateral area: 90; Volume: 240
D Lateral area: 120; Volume: 288
E Lateral area: 192; Volume: 64
F Lateral area: 144; Volume: 18*sqrt(15)
So the base of the rectangle has sides of 3 and 6. So:
Volume:
H = 3 x 6
H = 18
H = sqrt {6 x 3}
H = 6 {sqrt 3}
A = 1/2 x 6 x 6 {sqrt 3}
A = 18 {sqrt 3}
V = 18 {sqrt 3} x 8= 144 {sqrt 3}
Lateral Area:
6 x 8 = 48
3 x 48 = 144
3. a square base
A Lateral area: 176; Volume: 240
BLateral area: 90; Volume: 64
CLateral area: 120; Volume: 144
DLateral area: 288; Volume: 144 sqrt(3)
E Lateral area: 144; Volume: 18*sqrt(15)
F Lateral area: 192; Volume: 288
Since it's a square base, all sides are equal, which means all sides measure 6. So:
Volume:
A = 6 x 6 = 36
V = 36 x 8 = 288
Lateral Area:
6 x 8 = 48
3 x 48 = 144.
Not sure what I'm doing wrong.
Ok let me try it.
Volume:
h = sqrt{6^2 - 3^2}
h = sqrt{27}
h = sqrt{9 x 3}
h = 3 {sqrt 3}
area = 1/2 x (6) x 3 {sqrt 3} = 9 {sqrt 3}
volume = 9 {sqrt 3} x 8 = 72 {sqrt 3}
I think I got it this time
Lateral Area:
6 x 8 = 48
3 x 48 = 144
Now for #1, I am looking at D as my answer.
Just a quick questions, how does the first part (answer for the height) work out? I mean how did you get
2\sqrt{3}
in the end?
Also, isn't this another way to get the volume?
area of the front triangle x the height?
I've done some further researching and I think I am understanding it more now. First I need to get the area of the triangle shape. I believe that would be:
6 x 3 = 18.
Now:
V = A x H
V = 18 x 8 | v = 288
Is that correct?
I'm really confused now. I'm not sure which numbers to use in which equations to get the height & area.
I would really appreciate you explaining it briefly and if you could, you can do like the previous lesson, create a similar problem and solve it while explaining.
a^2 + b^2 = c^2
6^2 + 8^2 = c^2
36 + 64 = c^2
100 = c^2
c = 10
A = (1/2)bh
A = (1/2)(6)(8)
A = (1/2)48
A = 24
10 x 24 = 240. Is that the volume? \(^o^)/
What equation exactly would I be using exactly? would it be the
a^2 x b^2 = c^2
or would it be
A = (1/2)bh
Ok, from the link I understood how to get the area. So the base they give me is 6 as the base and the height is 8. So i have done:
A = .50 x 6 x 8 = 24
So now I have the area, I times it with height to get: V = 24 x 8 = 192
Now I'm not sure if I'm doing it EXACTLY right. I'm trying to figure out the answer for #1. To me it seems as if I got the lateral area which I feel is wrong:
The shape is a right prism with:
1. an equilateral triangle as the base
A Lateral area: 90; Volume: 288
B Lateral area: 192; Volume: 64
C Lateral area: 120; Volume: 240
D Lateral area: 144; Volume: 72 sqrt(3)
E Lateral area: 176; Volume: 18*sqrt(15)
F Lateral area: 100; Volume: 288
I need help with a lot of these math problems. Not sure exactly how to get them. Just want help understanding how to get the answer:
For 1 through 10, what is the area and volume of the given shape, if the length of one side of the base is 6, the height is 8, and the slant height is 10? (Not all shapes will require all three numbers.)
The shape is a right prism with:
1. an equilateral triangle as the base
A Lateral area: 90; Volume: 288
BLateral area: 192; Volume: 64
CLateral area: 120; Volume: 240
DLateral area: 144; Volume: 72 sqrt(3)
E Lateral area: 176; Volume: 18*sqrt(15)
F Lateral area: 100; Volume: 288
2. a rectangular base with a width of 3
A Lateral area: 192; Volume: 144 sqrt(3)
BLateral area: 144; Volume: 144
CLateral area: 90; Volume: 240
DLateral area: 120; Volume: 288
E Lateral area: 192; Volume: 64
F Lateral area: 144; Volume: 18*sqrt(15)
3. a square base
A Lateral area: 176; Volume: 240
BLateral area: 90; Volume: 64
CLateral area: 120; Volume: 144
DLateral area: 288; Volume: 144 sqrt(3)
E Lateral area: 144; Volume: 18*sqrt(15)
F Lateral area: 192; Volume: 288
4. a rectangular base with a width of 5
A Lateral area: 288; Volume: 96
BLateral area: 120; Volume: 248
CLateral area: 240; Volume: 144
D Lateral area: 192; Volume: 48
E Lateral area: 176; Volume: 240
F Lateral area: 100; Volume: 64
5. the base is an isosceles triangle with a height of 8 and a base of 3 (sides of 6)
A Lateral area: 120; Volume: 18*sqrt(15)
BLateral area: 100; Volume: 96
CLateral area: 192; Volume: 144
DLateral area: 176; Volume: 18*sqrt(15)
E Lateral area: 288; Volume: 288
F Lateral area: 240; Volume: 64
The shape is a pyramid with:
6. a rectangular base with a width of 4
A Lateral area: 120; Volume: 98
B Lateral area: 192; Volume: 76
C Lateral area: 240; Volume: 51
DLateral area: 176; Volume: 33
E Lateral area: 288; Volume: 75
F Lateral area: 100; Volume: 64
7. a square base
A Lateral area: 120; Volume: 96
BLateral area: 90; Volume: 64
CLateral area: 176; Volume: 144
DLateral area: 192; Volume: 35
E Lateral area: 288; Volume: 288
F Lateral area: 240; Volume: 75
8. a rectangular base with a width of 3
A Lateral area: 192; Volume: 144
BLateral area: 90; Volume: 48
CLateral area: 276; Volume: 64
DLateral area: 176; Volume: 144
E Lateral area: 92; Volume: 96
F Lateral area: 62; Volume: 24
9. a rectangular base with a width of 5
A Lateral area: 100; Volume: 48
BLateral area: 240; Volume: 112
CLateral area: 176; Volume: 96
DLateral area: 110; Volume: 80
E Lateral area: 288; Volume: 144
F Lateral area: 90; Volume: 64
10. a rectangular base with a width of 7
A Lateral area: 240; Volume: 64
BLateral area: 188; Volume: 96
CLateral area: 176; Volume: 144
DLateral area: 130; Volume: 112
E Lateral area: 144; Volume: 215
F Lateral area: 100; Volume: 128
I want to try and do the first 10 and once done, there is a second 10.
Sent them in, 20/20. I thank you VERY much Mr. Bob for your help!
5. A regular heptagon with a side of 7 inches.
A 178.06 sq in
B 294.16 sq in
C 169.21 sq in
D 358.91 sq in
E 157.36 sq in
F 277.91 sq in
Took me a second to figure out how to do it but i got the answer of A - 178.06 sq. in.
---
17. What is the area of a regular octagon with a side of 6 cm?
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 23 cm^2
E 173.82 cm^2
F 510 cm^2
360/8 = 45/2 = 22.5
8 x 0.5 x 6 x 3/tan(22.5) = 173.82 cm^2
So the answer is E
THANK YOU!!!