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Ok, so, with the euler angles you supply the position and orientation of the ship and you need to calculate the velocity vector's end point. Git it, I think. I will have to look into the Euler angles a bit more though. That seems to be the toughest part.
Yes, if L' (length of the bird) is 0, it is an infinite number of times. If not, then it gets a bit more complicated. All I can say for that case is that after t=(L-L')/(2V) time, L' starts monotonically decreasing. ![]()
Hi Isomorph
What does that have to do with why there is an associative law?
It needs to be a formal rule because there non-associative operations.
The commutative law does not allow omitting parentheses.
Yes, sorry.
I think they can be drawn.
That one isn't solvable, I'd say. At least in terms of elementary functions.
What I am doing is just taking
For that, it would be
Well, an ellipse isn't exactly a function, but, it can be done, I'd say. It would be very complicated in some cases.
Hi Maburo
The equation you are looking for is:
Well, as I said, I don't think it is necessary to fill up the whole table. It is enough to see in how many ways the table below can be filled up with k white and 32-k black pawns.

Well, I think I need enlightenment myself. Your best bet is to wait for Bob, but I will try doing it in the mean time.
Actually, I just looked at the info on wikipedia a bit. You are right, you don't need 4 angles. Three is enough.
No, no. You will need angles gamma and delta for the rotation of the ship.
Okay, I think I see the problem here. But, if I'm not mistaken, and I might be, you would need two more angles for the rotation of the rocket.
Well, I do not see why it is easy. I just know it was easy for me.
Well, he clarifies that "radius" refers to the velocity vector.
Also, I think you missed the word play in the last sentence of my last post.
Those coordinates make sense because that's the way the vector can be decomposed in 3D.
I don't think it's around a world axis. It seems to be a rotation of the ship, but neither affect any coordinates, so I'm not sure what that's about.
Yes, I did miss the pun. I quite like it, unlike most people. ![]()
Ah, okay. Post #67 is confusing.
Hi Bob
Are you sure it is moving on the surface of the sphere?
I am also stuck with the point of view. The only reference frame that makes sense is the world, but it doesn't seem to be so... ![]()
I did not understand what you meant. You got the same answer?
Hi DeadBeef
I'm not sure what you are asking. What I understood is that you are trying to get the x, y and z component of the velocity vector. Is that correct?
I already posted my answer in post #54.
Are you getting what I got?