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#726 Jokes » More Jokes... » 2008-07-03 12:47:03
- ZHero
- Replies: 10
A mathematician, along with his engineer friend, attends to a guest lecture on geometry in fifteen dimensions!
After they're through with it...
Mathematician: Wasn't that brilliant!?
Engineer: Yuck! My head's spinning! How do you develop any intuition for a fifteen dimensional space?
Mathematician: Well.. Its easy. I visualize the situation into an arbitrary N-dimensional space and then put N=15 !!!
#727 Re: Jokes » Complex joke.. » 2008-07-03 12:12:23
Here's a brand new one...
There are THREE kinda people on earth..
Those who are BELOW AVERAGE & those who are ABOVE AVERAGE!!
#728 Re: Jokes » Complex joke.. » 2008-07-03 11:03:41
???
???
#729 Re: Jokes » Complex joke.. » 2008-07-03 10:48:29
Didn't get the 'dinner' one but second one was really nice!!
#730 Jokes » Complex joke.. » 2008-07-03 10:07:57
- ZHero
- Replies: 12
Q: Why people don't laugh at a Complex Joke?
A: Because the JOKE PART is IMAGINARY!!:lol:
#731 Help Me ! » Complex... » 2008-07-03 10:04:43
- ZHero
- Replies: 2
Can anyone please give me a PRACTICAL EXAMPLE (apart from core maths, in daily life calculations etc.) where one finds use of COMPLEX NUMBERS??
#732 Re: Puzzles and Games » Points of intersection » 2008-07-03 06:12:27
Yo man..
1+2+3+...+(n-1)
= (n-1)n/2
= n(n-1)(n-2)(n-3)...(1)/[2(n-2)(n-3)...(1)]
= n!/[2!(n-)!]
= nC2 !!
And you know that an extra line contributes to one extra point of intersection to the previous no. of points of intersection!!
#733 Re: Puzzles and Games » Points of intersection » 2008-07-03 05:04:29
Total number of points of intersection is nC2
i.e. n!/[2!(n-2)!]
#734 Help Me ! » Any puzzles? » 2008-07-03 04:02:17
- ZHero
- Replies: 6
From the time i've joined the forum, i've not seen any new puzzles being put in any of the Puzzle sections...
Seems like the threads are dead!!
Guys, i'm crazy about puzzles (even though i'm not so good at solving them but i love their beauty... They've got a thrill!) so mind getting some puzzles please...!
#735 Re: Help Me ! » Can't log out » 2008-07-03 03:54:04
Even i'm facing the same problem with my mobile but i think its a bit +ve for me as i visit the site several times a day & guess what, i never need to type my user name & password!!
Though its a fault but its always the way you take it!
After all, nothing in the world is ABSOLUTE but is rather RELATIVE!
What's GOOD for one may be BAD for others and vice versa...!
#736 Jokes » Handwriting! » 2008-07-02 04:31:07
- ZHero
- Replies: 2
This is one of the funniest jokes i've ever come across..
A maths teacher was going through the test paper of one his students with a terrible handwriting...
Teacher: boy, your handwriting is so bad? See, your 6 looks like a 5 !
Student: but sir, this IS a 5 !
Teacher: oh! But why then does it look like a 6??
#737 Re: Help Me ! » Rate Combination problem » 2008-07-02 03:58:12
Mmmm.. Not exactly 'integer'!
Divide the work in the ratios of the amount of work each one does!
That is 3 : 4 : 5!
So.. Jonathan types 5 pages, Susan types 6.666 pages out of the remaining 15 pages and Jack types the remaining 8.333 pages..
You see, they can work simultaneously but on different parts of the same work and will all finish right after 10 minutes together!:cool:
#738 Re: Puzzles and Games » Solve in positive integers the cubic » 2008-07-02 02:07:19
The solution (obviously) is 13 but you know how Dirty n Untidy n Ugly the cubic equations are to solve!!
If anyone's got a Good way to solve the above, please let me know!!:cool:
#739 Re: Help Me ! » Colour blind respondents » 2008-06-30 02:37:49
Required number is 1/6 times 1721 ...
i.e. 1721x1/6 = 286.686
so, an approx 287 Respondents are colorblind!:D
#740 Re: Puzzles and Games » Hands of the clock.. » 2008-06-29 09:43:22
Wow! So may there be other such SPECIFIC positions that CANNOT occur amidst the three hands of a clock! I wonder if there be a GENERAL RULE stating which angles are really formed and which never!!?
Its getting pretty interesting (for your statement to be true mathsy)!!
#741 Help Me ! » Shortcuts? » 2008-06-29 07:33:40
- ZHero
- Replies: 0
I'm preparing for some entrance exam and am desperately looking for shortcuts for multiplication/division, square/cube roots, reciprocals, averages etc.
Is there any RESOURCE wherein i can learn most of these....?
#742 Re: Puzzles and Games » Hands of the clock.. » 2008-06-29 07:26:27
Well.. After a bit of easy calculations, all i can figure out is that after 240/11 (i.e. 21+9/11) minutes, the hour & minute hands will be at 120` & so an APPROXIMATE answer would be somewhere around 12:21....!
But i just can't figure out the EXACT answer!?
#743 Puzzles and Games » Hands of the clock.. » 2008-06-29 02:27:02
- ZHero
- Replies: 3
I've been pounding my head on this but in vain..
At what time (exact or approximate), after noon, the three hands of a clock are at equal angles to each other?:D
#744 Re: Help Me ! » Maths Problem - Weights » 2008-06-24 12:09:23
In simpler words..
Numbers from 1 to 3280 can also be represented in powers of 2, 4 or 5!
Then why 3 here?
(I'm really afraid if this is a silly question to ask!)
#745 Re: Help Me ! » Maths Problem - Weights » 2008-06-24 12:02:50
Mind not if i didn't understand the question well but i think that every number has a unique representation in different bases!
Means, all numbers from 1 to 3280 can be represented in base-2 and in base-4 too.. right?
Then why only base-3 is chosen here??
#746 Re: Help Me ! » 0! » 2008-06-21 10:41:19
Oh! That was such a beautiful explanation 'mathsyperson'! I bet i could not have known this from anywhere else!
This definitely makes Great Sense!
Many a Thanks!!
#747 Help Me ! » 0! » 2008-06-21 08:36:32
- ZHero
- Replies: 4
All of us know that 0! is 1 but i just am eager enough to know "how"? Also, does 0! really "EXIST"? Means, if it does then why not the factorials of -ve numbers?
How can one "DEFINE" it??
#748 Re: Puzzles and Games » Solve in R.. » 2008-06-17 01:41:24
mmm... actually what i real was trying to do was the same thing!
Means..
I was trying to solve the cubic equation x^3+5x-11=0.
I wrote x^3+5x-11=(x-a)(x-b)(x-c)=0
upon equating the coefficients i get the above system of equations which i really can't solve...
Any suggestions or ways?
#749 Puzzles and Games » Solve in R.. » 2008-06-17 01:18:58
- ZHero
- Replies: 3
(A, B, C) € R
A + B + C = 5
AB + BC + CA = 0
ABC = -11
How to find A, B, C?
#750 Re: Help Me ! » i cannot understand! » 2008-06-15 12:12:30
Even then, it means the same as mathsyperson said..
It actually means 3/4 times x which is 3x/4
Hope u got it!!