Math Is Fun Forum

Why there is DDAD and AAAD
I want everyweek to still same like six days and sixs nights continuously how to do that

Also your schedule has a small mistake there is eight A it has to be 6 A then OFF
And is there general equation for that

Also the employees are security officers in airport
I Can't just do it with 28 days
They have to work the whole month I don't want the airport be empty from the officers every morning i need and officer at list and everynight and afternoon the other 225 are security inspectors also i need at least 70 of them at daylight and 70 at afternoon and 60 of them at night
No problem with night can be lesser because night is not important there is less passengers traveling at night

the second problem I got as you will see in the next photo..

the first photo I show to you was in month May
in the second photo it's the next month which is June schedule

in the May the day1 start at Monday until  Day5 which is Friday which is the OFF day of X1 employee
so I started to fill and trying and tests thier schedules according to this
but at Day31 of May it was Wed and it was (D) shift for the X1 employee the end of the month
then at June the sixth Month it most continue in (D) shift until his Friday OFF
so I can't save the pattern inside my mind and apply it for each month because it has to be a specific calculations for each months
because some month also start for example at Sunday which is the OFF of the X3 employee
I just want to make a schedule  so I make sure I don't make any mistakes
and I want to know how to customize it for example I want to change few things like I want in Day5 2 employee at afternoon shifts instead of them at Daylight shift

EPSILON = 1E-14;
r = sqrt(2.0)

if  abs(r * r - 2.0) < EPSILON
output :-
sqrt(2.0) squared is approximately 2.0

this when I use java but when I use Microsoft calculator it said false! the condition would be false not true as you can see in this picture :-

also as you can see in this example :-

double x = 9.999999999999999;
if (Math.abs(x- 10.0) < EPSILON)
{
System.out.println("the number is approximately 10"); 
    }
}
}

when I minus the 9.999999999999999 to 9.99 for example the condition will be false!

in short I just want to solve this question :-

Explain why it is more difficult to compare floating-point numbers than integers.
Write Java code to test whether an integer n equals 10 and whether a floating-point
number x is approximately equal to 10

So we record that in the answer space as not 4 subtracts but 0.4 subtracts because we shifted the carriage one place.

I mean we made 15 become 1.5 the number is changed who gives the right to do such a thing is that legal in math and clearly understandable? is there explaintion for that ..
I mean we chose a different number it's 1.5
I can't imagine that is there interactive example like 6 apples iver 16 people

I am now completely understand how we get f and g
my problem was I tried to start to solve it row by row not the column f first then column g so sorry
now I remamber and completely understand