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#53 Re: Puzzles and Games » Drunken man with a gun... » 2011-07-21 23:56:44

Hi gAr,

For the answer in the first post..i just figured that to reach 50% probability, there is a more than 50% probability..like

1/8 is probability to hit, so 7/8 is probability to miss and also to increase chance to 2/8
so 7/8 * 6/8 * 5/8 would be probability to get 4/8.

I solved the following few equations for consecutive hits

1. two consecutive shots 1st and 2nd ->


2. two consecutive shots 2nd and 3rd ->

3.

4. the probability reaches a max here out of the six cases that i tested.

5.

6. the probability has already started falling...needless to put in the sixth case
7. Super Shot :

probability at Super Shot: 7/8 ----- (1)
to reach super shot probability
7/8 * 6/8 * 5/8 * 4/8 * 3/8 * 2/8 ----- (2)

Hence total probability = (1) * (2) = 0.0168

I would be grateful if any loopholes be pointed out..i think there are some..

Thanks in advance!

#55 Re: Puzzles and Games » Add 13 more and post it forever. » 2011-07-21 23:22:44

edit:oh! i forgot the mod sign or was it the absolute sign...sorry
Anyways...

17472


cool:cool:

Also,
17485


my legitimate turn..:D

#63 Puzzles and Games » Drunken man with a gun... » 2011-07-21 19:45:57

anandbrar
Replies: 17

Hi all,

I just thought up this problem involving probability..

"A drunken man with a gun in his hand has to shoot a thief. He has 7 shots with him; the thief dies if he gets hit with 2 shots. Presently the probability of the drunk scoring a hit is 1/8, but with every shot he gets more sober and the probability increases by 1/8.

Also at 7/8 probability, he has a Super Shot in which the thief will die in a single shot.

What is most likely to happen? - Death with 2 hits, A Super Shot or the thief survives???"

this is my guess..

what do you all think?:cool:

#65 Re: Puzzles and Games » The Egg-seller's eggs.. » 2011-07-21 06:52:46

hi bob bundy, anonimnystefy

Both your ans are correct.

#66 Puzzles and Games » The Egg-seller's eggs.. » 2011-07-21 06:36:12

anandbrar
Replies: 13

An egg-seller was on his way to a village. On his way, a fool collided with him and all his eggs broke. They both went to the village head-man. When the head-man asked how many eggs he had, the egg-seller told him,

"When counted in twos, 1 remains,
When counted in threes, 2 remain,
When counted in fours, 3 remain,
When counted in fives, 4 remain,
When counted in sixes, 5 remain,
When counted in sevens, none remain...
I had less than 150 eggs."

How many eggs did he have?
cool

#67 Re: Introductions » Hello from medical student » 2011-07-21 06:21:49

Thanks all! Posting the problem in a new topic..

#68 Re: Introductions » Hello from medical student » 2011-07-20 06:06:47

By the way....has anyone heard of the riddle in which an egg-seller's eggs break and he tells how many eggs he had as follows...

"If counted in 2s, 1 remain
If counted in 3s, 2 remain..."

or would anyone like me to put the problem?

#69 Introductions » Hello from medical student » 2011-07-20 06:04:27

anandbrar
Replies: 6

HI,
I am 19 male, studying for a medical degree in New Delhi, India.

I always had fun with mathematics problems, so i decided to join this forum.

Hope to have a good time in vacations..:D

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