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#51 Help Me ! » Proof » 2012-12-12 00:06:57
- zee-f
- Replies: 26
Hi,
I really need help seeing if I answered the following correct:
I'll give you an assumption, and ask you to provide proof for the assumption. If there is no proof for the assumption, the answer is "unfounded."
I choose A
1. If I have two coplanar lines, I must have a plane.
A-unfounded
B-Definition of a point
C-Definition of a plane
D-Given
E -Definition of a line
F -Definition of radius
#52 Re: Help Me ! » Transformations » 2012-12-10 08:18:03
I choose B and it was incorrect but why doesn't the angle change because the size is getting bigger.
1. An angle changes in size as it undergoes a dilation.
A False
BTrue
#53 Re: Help Me ! » Transformations » 2012-12-10 03:26:16
I rotated the paper 270 clock wise so 3 times clockwise and I got
#54 Help Me ! » Transformations » 2012-12-09 09:13:24
- zee-f
- Replies: 7
Hi,
I am really stuck on how to rotate the following
Rotate the triangle 270 clockwise around (0,0).
#55 Re: Help Me ! » The Cartesian Coordinate System and the Distance Formula » 2012-12-06 07:22:17
And I really appreciate the time your giving me to help ! 
#56 Re: Help Me ! » The Cartesian Coordinate System and the Distance Formula » 2012-12-06 07:04:08
Thanks 
#57 Re: Help Me ! » The Cartesian Coordinate System and the Distance Formula » 2012-12-06 06:45:49
Hi,
#5- (A- rectangle)
#8- (A- parallelogram)
Thank you
#58 Help Me ! » The Cartesian Coordinate System and the Distance Formula » 2012-12-05 12:31:26
- zee-f
- Replies: 7
Hi,
I was wondering if my answers look correct
1- C
1. Draw a Cartesian Coordinate system for yourself, and then determine whether these sets of points form triangles
Set 1: (0,0), (1,1), (0,1)
Set 2: (-1, 0), (1,1), (3,2)
Set 3: (0,0), (5,0), (3,5)
A set 1 line segment, set 2 Triangle, set 3 line segment
Bset 1 Triangle, set 2 Triangle, set 3 line segment
Cset 1 Triangle, set 2 line segment, set 3 Triangle
Dset 1 line segment, set 2 line segment, set 3 line segment
E set 1 Triangle, set 2 line segment, set 3 line segment
F set 1 line segment, set 2 Triangle, set 3 Triangle
2-B
2. I have placed a square that is 2 units long on each side so that its sides are parallel to
the x- or y-axis, but it's center is right on the origin. What are the coordinates of the corners?
A (-1,-1), (1,-1), (-1,-1), (1,-1)
B(1,1), (1,-1), (-1,1), (-1,-1)
C(-1,-1), (-1,-1), (1,-1), (1,-1)
D(1,-1), (-1,1), (-1,-1), (-1,1)
E (-1,1), (-1,1), (-1,-1), (-1,-1)
F (1,1), (1,1), (1,1), (1,1)
3- E
3. What shape do these four points make? (Draw from one to the next in the order given,
and then draw from the last back to the first).
(0,-1), (1,1), (0,3), (-1,1)
A A pentagon
BAn octagon
C A triangle
DA square
E A rhombus
F A cube
4. D
4. Now do the same with this list, and describe the shape.
(0,-1), (0,3), (1,1), (-1,1)
A A square
BTwo acute angles that meet at the acute angles
CA triangle
DTwo right triangles that meet at the right angles
E A rhombus
F Two obtuse triangles that meet at the hypotenuse
What shape is created by the following points? (Do not connect these in order, just connect around the outside of the shape.)
5. C
5. (-1, 0), (2, 0), (2, 4), and (-1, 4)
A a rectangle
Ba square
Ca parallelogram
Da rhombus
E a triangle
F a line segment
6.F
6. (-2, 1), (-6, 1), (-7, 6), and (-3, 6)
A a line segment
Ba trapezoid
Ca square
Da rhombus
E a triangle
F a parallelogram
7. B
7. (1, 1), (1, -3), (9, 1), and (5, -3)
A a line segment
Ba trapezoid
Ca square
Da rhombus
E a triangle
F a parallelogram
8.F
8. (8, 5), (2, -3), (5, -3), and (5, 5)
A a parallelogram
Ba trapezoid
Ca square
Da rhombus
E a triangle
F a rectangle
9.A
9. (-5, 1), (2, 1), (2, -4), and (-13, -4)
A a trapezoid
B a line segment
C a square
D a rhombus
E a triangle
F a parallelogram
10.D
10. (-7, 9), (-3, 13), and (-11, 13)
A a rhombus
B a trapezoid
C a square
D a right triangle
E a circle
F a line segment
#59 Re: Help Me ! » area review » 2012-12-02 08:28:13
ok since (C=pD) I would divide the circumference by PI to get D then divide it by 2 to get R
#60 Re: Help Me ! » area review » 2012-12-02 04:44:10
Volume = π × r2 × (h/3)
#61 Re: Help Me ! » area review » 2012-12-02 04:43:03
I would measure the height using a tape measure then half the height I would draw a line around the circle and measure the height across and divide it by 2 and use that as a radius
#62 Re: Help Me ! » area review » 2012-12-01 03:59:43
This is the last question am stuck on
7. Come up with a way to find the area and volume of a football. Include in your answer a way to acquire any necessary measurements without cutting or otherwise destroying the football. Also include all necessary formulas to implement your idea. (You don't need to find actual numbers, just outline the method in step by step detail--think of all the measurements you'll need to acquire and how you'll get them.)
7. ok So a football looks like two cones attached So I can uses the same formula I use for a cone right?
#63 Re: Help Me ! » area review » 2012-12-01 03:58:30
Thank you guys
#64 Re: Help Me ! » area review » 2012-11-30 13:25:52
s= 10.39226354
#65 Re: Help Me ! » area review » 2012-11-30 09:11:21
5. OK I need to find the area to get the length of each side . If H is 18 that means the apothem equals 9 So that means the area = A^2 * N * tan * (180/n)
area= 9^2 * 6 * tan * (180/6) = 280.59
3 (√3 /2) * S² = 280.59 ======> s² = 280.59 * 2 / 3 * √3 = 107.9991414
#66 Re: Help Me ! » area review » 2012-11-30 03:53:11
Thank you so so much....
Ok I solved the following using formulas I know and the formula you used :
3. If a hexagon has a radius (center to point of angle) of 6, what is the side of the hexagon?
3. Ok I need to find the area to get the side. So I know that if I have the radius I can find the area by doing the following : A = r² * N * sin(360/n) / 2
A= 6² * 6 * sin(360/6) / 2 = 93.53074361
I know that area = 3 sqrt(3) / 2 * side² So S= 93.53074361 / 3sqrt(3)/2 which equales 36 So the side of the hexogon = 36
4. If a hexagon has a radius (center to point of angle) of 6, what is the area of the hexagon?
4. A = r² * N * sin(360/n) / 2
A= 6² * 6 * sin(360/6) / 2 = 93.53074361
So the area of the hexagon = 93.53074361
5. If a hexagon is resting on a flat side, and has a total height of 18, what is the length of each side of the hexagon?
5. Ok I need to find the area to get the length of each side . If H is 18 that means the apothem equales 9 So that means the area = A^2 * N * tan * (180/n)
area= 9^2 * 6 * tan * (180/6) = 280.59
So I know that the area for a regular hexagon = 3SQRT(3) / 2 multipliyed by S^2
280.59 = 3SQRT(3) /2 * S^2
S^2 = 280.59 / 3SQRT (3) = 81
So the length of each side of the hexagon = 81
6. If a hexagon is resting on a flat side, and has a total height of 18, what is the area of the hexagon?
6- If H is 18 that means the apothem equales 9 So that means the area = A^2 * N * tan * (180/n)
area= 9^2 * 6 * tan * (180/6) = 280.59
#67 Re: Help Me ! » area review » 2012-11-29 11:05:31
yeah am stuck on where to start
#68 Re: Help Me ! » area review » 2012-11-29 10:34:45
Thank you
Ok am stuck on this one
If a hexagon has an area of 100 units, what is the length of one side?
So the equation would be : 100= 3√3 / 2 * s² right?
#69 Help Me ! » area review » 2012-11-29 08:25:18
- zee-f
- Replies: 19
Hi,
I really need help seeing if I answered correctly:
1. If a hexagon has a side of 3 units, what is the area of the hexagon?
#1- 3² * 6 / 4* Tan(180/6) = 27√3/2 = 23.38
#70 Re: Help Me ! » Area and Volume of Prisms and Pyramids » 2012-11-28 06:35:35
Thank you!! )
#71 Re: Help Me ! » Area and Volume of Prisms and Pyramids » 2012-11-28 03:03:53
#12-
4²+3²=c²
16+9=25
√25=5
5*2+6=16
16*8=128
So #12- D
#13- Longest side is 6 So 6*8= 48
So I got the 8 by multiplying 4 *2 right?
#72 Re: Help Me ! » Area and Volume of Prisms and Pyramids » 2012-11-28 01:50:54
So now I have to get the area of the base and multiply it by the height of the prism to get the volume right?
half base = 3
height = 3√15 / 2
So 1/2 * 3 * 3√15 / 2 = 9√15/4
9√15/4 * 8 = 18√15
#73 Re: Help Me ! » Area and Volume of Prisms and Pyramids » 2012-11-27 12:26:03
ok So number #5-
p=15
LA= 15*8=120
V=BH
But when I used the Pythagoras theorem I got
a²+b²=c²
1.5²+b²=6²
2.25+b²=36
b²= 15/4
b= 3√15 / 2
#74 Help Me ! » Area and Volume of Prisms and Pyramids » 2012-11-27 03:08:14
- zee-f
- Replies: 7
Hi,
I got the following incorrect I really need help
For 1 through 10,#5 what is the area and volume of the given shape, if the length of one side of the base is 6, the height is 8, and the slant height is 10?
5.C
5. the base is an isosceles triangle with a height of 8 and a base of 3 (sides of 6)
A Lateral area: 120; Volume: 18*sqrt(15)
BLateral area: 100; Volume: 96
CLateral area: 192; Volume: 144
DLateral area: 176; Volume: 18*sqrt(15)
E Lateral area: 288; Volume: 288
F Lateral area: 240; Volume: 64
I have an isosceles triangle with a height of 4 and a base of 6:
11- C (this was correct)
11. What is the area?
A 19
B 35
C 12
D 16
E 22
F 54
This triangle just became the base of a regular prism, with a height of 8:
12-F
12. What is the lateral area?
A 105
B 28
C 35
D 128
E 56
F 12
13-C
13. What is the area of the largest rectangular side?
A 95
B 54
C 32
D 48
E 96
F 10
#75 Re: Help Me ! » area » 2012-11-24 08:21:32
Thank you