Math Is Fun Forum

I think I figured it out. I will post it when I write it out.

The same as Nehushtan did.

What do you not understand? I just rearranged the result a bit and got the answer.

Sure!

FullSimplify[Sin[b + c - a] + Sin[a + b - c] == 2 Sin[a + c - b]]

2 Cos[a] Cos[c] Sin[b] == Cos[b] Sin[a + c]

Well, the inverse transformation is T'(A)=BAB^-1

True, but the problem in post #1 says they are placed one behind the other, so {7/3}'s solution applies there.

What I said in post #18 is true.

It is not a typo. It is a misunderstanding of meaning of the intended meaning of the exclamation mark.

I will try working on it a bit more.

I see B has learned.

Yes, the problem is not well-defined. We should wait for the OP to clarify, if he's able to.

Did you divide your two numbers?

What do you get? And what do you get when they're different players.