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#6926 Re: Help Me ! » Think » 2005-02-22 17:08:11

... that almost makes sense

#6927 Re: Help Me ! » Maths!!!! » 2005-02-21 20:12:07

Well, by using the "absolute value" function abs(), you can use:

abs(x) - x^2   (absolute-value-of-x minus x-squared)

When I tried this on our graph plotter, I found it looked best using 2*abs(x)-x^2

#6928 Re: Help Me ! » calculation » 2005-02-21 10:02:27

The subject is "Permutations and Combinations".

With Permutations you count how many different ways something can be arranged, such as abc, acb, bac ... etc. But the lottery doesn't care what order the numbers come out.

Combinations looks at how many different ways things can be chosen without concern for order - just right for lotteries

The classic formula for combinations is:
           
n_C_k =  n! /  k!(n - k)!

The "!" means "factorial". We sometimes call n_C_k "n choose k", or in your case "49 choose 6"

(Now, I give this formula without explanation because it takes a long time to explain ! You may have to look up your text book here.)

But, anyway, we should be able to work it out for the lottery:

49_C_6 = 49!  /  (6! x (49-6)!) = 13983816 (using my calculator)

So, the odds are nearly one in 14 Million. Ouch.

#6929 Re: Help Me ! » Maths!!!! » 2005-02-21 00:05:03

Correct, amber, and we have some examples of reflex angles here

#6930 Re: Help Me ! » population problem » 2005-02-18 08:20:48

Good one, Saz000! The original problem said half the OTHERS, whereas I assumed half of all did. So it is saying that EVERY one-legged person wears sandals, so you are right.

#6931 Re: Help Me ! » Maths!!!! » 2005-02-17 13:14:55

Well, we do have some simple explanations of fractions starting at Equivalent Fractions - look for the links at the bottom of the page for lots more about fractions.

Likewise you can check out Percentages and also do a short Percentage Test

#6932 Re: Guestbook » Cool » 2005-02-16 21:42:51

That makes us feel great, thank you.

#6933 Re: Help Me ! » Fibonacci » 2005-02-16 17:45:53

OK, I believe we can look at the problem like this: we want to know the difference between two successive n-values for any w (this difference will be the "D" value mentioned in your questiom)

First let's expand out the function: 1+4w(1+w+n) = 1+4w+4w^2+4wn

Let us see what the difference between two n-values is (call them n_1 and n_2)

   1+4w+4w^2+4wn_1
- 1+4w+4w^2+4wn_2
= 0+  0+       0+4w(n_2-n_1)

= 4w(n_2-n_1)   

So, that would be the solution for one difference "D" (remember the D_n = D_(n-1) + D_(n-2) formula?)

Let us try to "plug this into" that the D_n = D_(n-1) + D_(n-2) formula. For ease of writing this on the screen I will use actual numbers, but you can substitute (n-1), etc:

4w(n_3-n_2) = 4w(n_2-n_1) + 4w(n_1-n_0)

simplifying:
n_3-n_2 = (n_2-n_1) + (n_1-n_0)
n_3-n_2 = n_2-n_0

And that last formula is indeed a Fibonacci sequence which we can prove by playing with it:

substitute n_2 for n_2=n_1+n_0

n_3-n_2 = (n_1+n_0)-n_0

Simplifying:

n_3-n_2 = n_1

or
n_3 = n_2 + n_1

So, I have "shown" how this can be proved. You just need to neaten it up a little before calling it a proof, OK?

#6934 Re: Help Me ! » Fibonacci » 2005-02-16 15:43:16

Patience, visualbenjie, I have had many things to deal with today, and will need time to sit and think the proof (jeez, you could give me an easy one I could answer directly!)

#6935 Re: Help Me ! » Please help me » 2005-02-16 15:40:13

Hi Rabid, is the language Visual Basic?

Perhaps the problem is that the value is text, not numeric. Try converting it first. In VB you could use CDbl().

Also try showing the numbers before and after the calculation (debug.print or msgbox or whatver works to show them on the screen) to see what is going on.

It is also possible that when dividing by 100 it is thinking "this is a whole number, so the answer should be a whole number".

Try this:

MinDeposit = cdbl(txtPriceOfProperty.Text) * 0.05
if (Deposit >= MinDeposit) then
...
end if

Let's know how you get on

#6936 Re: Maths Is Fun - Suggestions and Comments » Our New Forum » 2005-02-15 11:00:46

hrock and Hyperbelt7, you are both right, but don't tell anyone smile

#6937 Re: Help Me ! » Fibonacci » 2005-02-15 09:37:42

The Fibonacci sequence follows the simple rule of adding the previous two numbers to get the next.

0,1,1,2,3,5,8,13,21,34, etc

That is stated in your problem as D_n = D_(n-1) + D_(n-2) (for example, 21=13+8)

Now, trying to decipher the problem, I believe it is saying that when calculating the formula 1 + 4w(1 + w + n), where n follows a fibonacci sequence, the difference between each successive answer also follows the fibonacci sequence.

Let's plug in some real numbers to get an idea of this.

Let us try w=3:

n    T_n   Difference
0      49    
1      61    12
1      61     0
2      73    12
3      85    12
5    109    24
8    145    36
13   205    60
21   301    96
34   457   156
 
So, we have n following the Fibonacci sequence, we have calculated 1 + 4w(1 + w + n) for w=3 and different values of n, and we have calculated the difference. Interestingly, the difference also follows the rule that the previous two numbers add up to make the next. (12+0=12) (12+12=24) etc


If you believe I have stated the problem correctly, please let me know, and we can then work on the proof.

#6938 Re: Help Me ! » Algebra help bad » 2005-02-14 22:21:34

I started the forum to give people a chance to discuss math problems, say good (or bad) things, share discoveries and generally express themselves. It is just good fun to help.

So, how are you getting on with your math? Give us another problem.

#6939 Re: Help Me ! » Algebra help bad » 2005-02-14 11:46:29

That is a great avatar, eurasiangurl.

I used to teach at Uni. I can't give you one-on-one help, but feel free to post any questions and I or another member can respond. That way other people get to the chance to see questions and answers, or perhaps to correct me if I am wrong!

#6940 Re: Help Me ! » maths » 2005-02-12 10:47:43

Percentages just mean "per 100" so 20% means "20 per 100"

Your particular problem MAY be as simple as calculating 20% of 3500, (which is 20/100 x 3500 = 20 x 3500/100 =  20 x 35 = $700)

But perhaps they mean "there was a price, Joe got 20% of that, and the total is $3500"

In that case it is a little harder.

You would figure it this way: you know that $3500 = "The Unknown Price" + 20% of  "The Unknown Price" =  120% of the unknow price.

And 120% is 120/100, which is really just 1.2

So, "The Unknown Price" x 1.2 = 3500

Dividing both sides by 1.2 gets:

"The Unknown Price" x 1.2 / 1.2  = 3500 / 1.2

"The Unknown Price" = 3500 / 1.2

"The Unknown Price" = 2916.67

And Joes 20% would be 20/100 * 2916.67 = 583.33

(Confirming this: 2916.67 + 583.33 = 3500)

Was that a help?

#6941 Re: Help Me ! » maths » 2005-02-10 08:38:56

A 3D cube is just a simple box. So it has a top and a bottom, a front and back and a left and right side. In othe words just 6 sides. But if you count the edges, there are 12.

You can find out more here: Platonic Solids

#6942 Re: Help Me ! » maths » 2005-02-09 21:11:01

Well, we like this website! (Of course)

We have some pages here that tell you how to deal with fractions. Adding, subtracting multiplying and dividing.

For example, to multiply 1/4 by 2/3 you just multiply the top bits by the bottom bits:

1/4 x 2/3 = 1x2 / 4x3  = 2/12.

2/12 can be simplified to 1/6

You can read more about this at Multiply Fractions

#6943 Re: Help Me ! » want to restart math studies » 2005-02-09 10:30:21

Hi Deepak.

Most of what you want is available on the internet at different locations, but if you could buy a book or two that would really help, because you can study the book, and then use the internet for further research.

This is only a suggestion, but I think you could narrow down your studies, instead of learning all of 12th standard, try to dicsover what specific areas you need to know more about, and focus on those.

#6944 Re: Help Me ! » volumes » 2005-02-08 10:33:13

Well, how about converting the lengths into metres first (1ft = 0.305m):

Using my trusty calculator:
15ft = 4.575m
16ft = 4.88m

So, the Area is 4.575m by 4.88m, multiplying these together gets: 22.3 m2 (metres squared)

#6945 Re: Help Me ! » Algebra help bad » 2005-02-07 18:35:39

Not a problem, eurasiangurl, here is another:

To solve algebra, you just have to move things around until it works out. A bit like a puzzle:

Let's try Problem No 56:
y(y+11)=0

Let's expand it out a little:
y times (y+11) =0 can be turned into:
y times y + y times 11 =0
or:
yy + y11 =0   , this is NOT the right way to write it down! so we will correct it to:

y^2 + 11y =0  (where y^2 means y-squared, or simply y times y)

Now, subtract 11y from both sides to get:
y^2 + 11y - 11y = 0 -11y
simplify it:
y^2 = -11y

Now, divide both sides by y:
y^2 /y = -11y /y
simplify:
y = -11

TA DA!

Just to be safe, let's check it:
y(y+11)=0
substitute "-11" for "y":
-11 times (-11 + 11) = 0
-11 times (0) = 0
0=0

Great, we got it

If there was a part of this you didn't follow, let me know.

#6946 Re: Help Me ! » Algebra help bad » 2005-02-07 00:09:58

A bit of a long question - but I can start helping you.

1. 27 is not a prime number, because it can be divided by 9 and 3. It is, however 3x3x3, or 3 cubed, so it is a cubic number.

3.  66 can't be a square number: 8x8=64, and 9x9=81, so 64 and 81 ARE, but 66 ISN'T

12. If it isn't prime it is composite (ignoring 1 which is a special case). 33 can be divided by 11 and 3, so ISN'T prime, so is COMPOSITE

14. 301 can be evenly divided by 7, so must be .....

18. GCF for 12, 18, 40: 12=2x2x3, 18=2x3x3, 40=2x2x2x5. They all have 2 in common, so GCF=2. (Can't get any better than 6,9,20)

20. 16MRT,30M SMALL2 - by "SMALL2" I imagine you are having difficulty writing "squared" - how about I write it as ^2, so rephrase that as:
16MRT, 30M^2. Well, the GCF of 16 and 30 is 2, and we can also see that one "M" is common. So the answer is 2M.

That is all I have time for at the moment, maybe someone else can do a bit?

#6947 Re: Guestbook » maths » 2005-02-05 08:38:20

tell us what you are having trouble with - long division? algebra?

#6949 Re: Maths Is Fun - Suggestions and Comments » Our New Forum » 2005-02-02 08:25:23

It took me ages, too ! And 3 goes, and lots of paper.

I found that writing their names in the right order (left to right) helped, so Lucy is first because it says she is on the left, and Georgina is last, and I could figure that Hannah is in the middle because she likes Dairy Milk and Dairy Milk is in the middle. That gave me a good start.

#6950 Re: Guestbook » Maths Today » 2005-02-02 00:19:59

Welcome, and I hope you find some good things here.

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