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#552 Re: Help Me ! » correct formula » 2016-05-05 03:49:20

Equally painful! I wonder what the 'correct' answer is.

835 solutions! Getting close to "infinitely many"!

5oWggOZ.jpg

#553 Re: Help Me ! » correct formula » 2016-05-05 03:31:51

That's the formula in post #14 by Relentless.

#554 Re: Help Me ! » correct formula » 2016-05-05 03:09:11

Congratz! up

But how did you manage to win with an incorrect formula? faint

#555 Re: Help Me ! » correct formula » 2016-05-05 02:54:36

oranghijau wrote:

plus all digits by 4 times (-D1 + D2 - D3+ D4 - D5 + D6 - D7 + D8)..
its like this??

That is very different from what I did, and gives a very wrong answer.

My method uses several sets, because, although they're not exactly spelt out to the letter, I understood the rules to be these:
(a) only full sets can be used in the calculation;
(b) the numbers must retain their original sequence;
(c) no out-of-sequence numbers can be used (even though that number may be one that appears in the set);
(d) no new numbers (ie, numbers not in the set) can be introduced.

In your format, my formula looks like this:

4(D1+D2+D3+D4+D5+D6+D7+D8)-(D1-D2+D3-D4+D5-D6+D7-D8)

The second set looks different from that in post #12 because of the effect of parentheses on the minus signs.

I use the set more than once - which is not allowed - and so Relentless's method in post #14, in which the set appears only once, suits better.

#556 Re: Help Me ! » correct formula » 2016-05-05 01:43:08

oranghijau wrote:

if calculate one by one using normal calculator (not copy and paste)...it still get 210.
is there any other way?

This one, which is the one in my post, yields 162: 3+4+5+6+7+8+9+0+3+4+5+6+7+8+9+0+3+4+5+6+7+8+9+0+3+4+5+6+7+8+9+0-3+4-5+6-7+8-9+0

This one yields 210: 3+4+5+6+7+8+9+0+3+4+5+6+7+8+9+0+3+4+5+6+7+8+9+0+3+4+5+6+7+8+9+0+3+4+5+6+7+8+9+0

Did you use all "+" signs, as in the second one, and overlook the four "-" signs that are in the first one?

#557 Re: Help Me ! » correct formula » 2016-05-05 01:36:14

Hi Relentless;

Yes, I can see that.

Your previous post's formula works perfectly well. up

I usually don't mind puzzles like this and have a reasonable success rate with them, but trying to find a solution can sometimes be as exasperating as determining the value of the next term in a series. You can either see it or not, and the greatest klutz can surprise.

I tend to call it a day after my brain has switched off and I've headbutted the keyboard...but then, after a good night's sleep, sometimes light dawns at dawn's light...or in the middle of the night.

I may try this puzzle once more, again.....or not.

#558 Re: Help Me ! » correct formula » 2016-05-05 01:11:31

Hi oranghijau;

Answer for number 3 is 210 if using that formula..

210 is incorrect, so I suppose you made an input error.

There are a number of easy ways to check the answers of the sums in my post that avoid input errors. Just copy the whole line before the "=" sign and paste it into a software or online calculator on your computer that accepts such input. Many do.

eg, Mathsisfun: here, or WolframAlpha here.

You can even use the address bar in Google Chrome and Microsoft Edge...just don't press Enter, otherwise you'll get an error message because of the large input size.

You'll find that the answers I posted are correct.

#559 Re: Help Me ! » correct formula » 2016-05-04 11:22:40

Hi guys;

I have a solution based on parts of posts #2 and #8, but it involves what I'd say is trickery.

#560 Re: Help Me ! » More handshakes » 2016-05-03 10:06:46

I wonder if the minimum number of "4"s is 16. But I won't look any further.

thickhead wrote:

Now it is more picturesque than before.

I used Excel's 'Conditional Formatting' on the whole 32 x 32 grid to automatically apply the different colours according to which number I entered into a cell. Very quick and easy. It helps me keep track visually of what I'm doing, and makes the end result easy to understand.

The colouring also helped confirm that the last two grids were error-free...which I hadn't done properly at first, hence my earlier errors.

Well, the rain has finally stopped, but the builders next door have started...and so has their noise! So I may as well go outside and see if my noise can beat theirs: my 9" angle grinder and petrol-driven posthole digger versus their generator, pneumatic nailing guns and rap 'music'! It's war!! smile

#561 Re: Help Me ! » More handshakes » 2016-05-02 22:39:13

Definitely a team effort! smile

I'd still be poking away at it in the dark if it wasn't for the insight of the other team members.

#562 Re: Help Me ! » More handshakes » 2016-05-02 22:18:11

Hi;

I found another answer, but still for X = 4.

It uses 12 less "4"s than in my previous solution.

I tried for X = 3 again, but can't find a solution for it.

#563 Re: Help Me ! » More handshakes » 2016-05-02 18:06:32

Raining outside...can't dig holes in the mud! sad

This is the best I've got so far:

X = 4.

#564 Re: Help Me ! » More handshakes » 2016-05-02 16:09:23

Sorry, thickhead, but I have to rush off now for a few hours and can't spend time on your post until this evening.

I'd logged on again to edit my post #34, which I finished just a few minutes ago.

Catch you later...

Quick edit before I go: Just had a thought and checked my images. There's a critical error! Grumble! Back to the drawing board!!

#565 Re: Help Me ! » More handshakes » 2016-05-02 09:43:18

Hi Anna;

You should compare columns with columns and rows with rows, not columns with rows. The 'x' diagonal only goes in one direction (NW to SE), which throws the expected balance out, but there is another way of looking at this that shows we have the balance we need.

Here are two coloured images from my spreadsheet to help demonstrate. All green cells contain "2" and all blue cells "3".

In this version, if you draw a line through the centre to two cells opposite to, and equidistant from, each other, you'll find that one of them will contain a "2" and the other a "3". Always. In the following examples of this, the first letter denotes the row and the second the column.

Ae ("2") is opposite fB ("3").
OR ("3") is opposite RO ("2")

And so forth, and so fifth...etc.

There are an equal number of each colour/number, distributed equally in a balanced pattern about the 'x' diagonal.

This version comprises two diagonally-cut halves (with the NE sector rotated 180°) alongside each other for comparison. You'll see that all "2"s and "3"s in the right-way-up image align exactly with their respective "3"s and "2"s counterparts in the 180°-rotated image. That pattern applies throughout, which could not happen without 100% balance.

Brimming with balance! smile

Just had a thought and checked my images. There's a critical error! Grumble! Back to the drawing board!! Maybe you're right. Have to go out now for a few hours, and will look at this again this evening.

#566 Re: Help Me ! » More handshakes » 2016-05-02 09:05:28

The table is perfectly symmetrical about the 'x' diagonal.

eg,
Row "A" has 1 @ "x", then 30 @ "2", then 1 @ "3", and row "f" has 1 @ "2", then 30 @ "3", then 1 @ "x";
Column "A" has 1 @ "x", then 31 @ "2", and column "f" has 31 @ "3" then 1 @ "x".

Also, starting with column A = 62, the A.P. of +1 requires the following handshake totals:
A=62, B=63, C=64...d=91, e=92, f=93.

And the total for column "f" can only be 93 by 31*3 and 1 @ "x".

Also, a Countif search of the table finds 32 @ "x", 496 @ "2" and 496 @ "3".

#567 Re: Help Me ! » More handshakes » 2016-05-02 02:56:38

Ah...yes! Exactly, thickhead. up

X = 3.

And thanks for spotting the flaws in my table. smile

thickhead wrote:

"e" will have 2*2+29*3=91
"f" will have 2+30*3=92

I've got the following for those:
e = 2 + 30*3 = 92;
f = 31*3 = 93

Because f is the 31st term from A, and A = 62, then f = 62 + 31 = 93...and e is 1 less.

#568 Re: Help Me ! » More handshakes » 2016-05-02 01:03:53

Hi;

I think I agree with thickhead's answer in post #6.

#569 Re: Puzzles and Games » The missing dollar (& the 2 extra dollars) » 2016-05-02 00:01:19

Hi Relentless;

Both correct! smile

My HP 32SII (below), working 'perfectly well' again! I must've walked off with it, and the refund! I'll have to 'pay' the shop a visit...

1LOm8ZX.jpg

#570 Re: Help Me ! » Riddle Puzzle sort of » 2016-05-01 20:28:10

You're welcome! smile

At the end of my previous post I'd included a link to a similar puzzle that I posted in 2009, but then deleted it because when I read the thread I thought I'd made a critical error in one of the posts.

However, I checked it again just now and all seems to be ok, so here's the link again if you'd like to have a look at it: The missing dollar (& the 2 extra dollars).

#571 Re: Help Me ! » Riddle Puzzle sort of » 2016-05-01 15:33:27

math9maniac wrote:

Now you owe your mum $49 and your Dad $49 so 49+49=98 plus the $1 with u is $99.

Yes, that is $1 less than $100...which is the initial amount of Mum and Dad's loan.

However, the above quote should read: Now you owe your mum $49 and your Dad $49 so 49+49=98 less the $1 with u is $97...which is the cost of the shirt.

Adding, instead of subtracting, the $1 only seems to be going in the right direction with it because of the close proximity of $99 to $100. If the $100 were some other figure - like $1,000,000 - it would be obvious that something was up, even though one figure is just as (ir)relevant as the other. 

The correct sum for arriving at $100 is this:
$49 + $49 + the $2 already returned to Mum and Dad = $100...which is the initial amount of Mum and Dad's loan.

#572 Re: Help Me ! » More handshakes » 2016-04-30 22:18:15

H0QquvX.jpg

There is a list of BBCodes here...or, when you are logged in, you can get there by clicking on the BBCode button near the bottom of the thread page, on the left-hand side. The code tags are near the bottom of the list.

Also, again when you are logged in, you can click on the 'Quote' button in the bottom right-hand corner of my previous post to see how I used it.

#573 Re: Help Me ! » More handshakes » 2016-04-30 21:29:34

thickhead wrote:

The chart looks warped because of single and double digit numbers.

Here's the same chart in 'code' tags.

If you want to align the single-digit numbers with the right digit of the double-digit numbers, you'd have to include spaces where needed...but this is the simple solution.

#574 Re: Help Me ! » Handshakes » 2016-04-28 01:40:17

Those equations work, but they also work for smaller values of r.

Is there a notation that could be incorporated in the equation to indicate that maximum r is required, or should that be worded somehow with the answer, or don't we worry about putting it in the answer because it's in the question?

Also, is there some way of arriving at a solution without testing several values of r to find out which is the maximum? I suppose you could solve for r where the rhs = 500, and round the answer down to the nearest even integer. Btw, my little HP 32SII calculator's Solve function gives the answer r = 18.1617121098.

In my previous post I had this equation:

That came from this:

I should have included the inequality:

#575 Re: Help Me ! » Handshakes » 2016-04-27 12:28:43

Ok, thanks. I think I have the picture now.

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