Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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#56051 Re: Help Me ! » Percentages » 2009-04-16 09:32:38

Hi smiyc86;

   True, I didn't want to confuse him with any tricks, so I tried to be plain. If he comes back maybe you can explain it better than I can.

bobbym

#56052 Re: Maths Is Fun - Suggestions and Comments » Scrolling Number Line » 2009-04-16 09:19:58

Programming is an art and a good program is a work of art. It looks nifty to me.

bobbym

#56053 Re: Help Me ! » simple random walks » 2009-04-16 08:53:43

Hi EMPhillips;

If you mean that the reflective barrier bumps you back to 3 then this is the transition matrix.

This is how I would set that random walk up.

#56054 Re: Dark Discussions at Cafe Infinity » String Theory gets a Boost » 2009-04-15 21:35:02

Hi Jane;

   I'm there right now, so try it.

#56055 Re: Help Me ! » Percentages » 2009-04-15 21:07:01

Hi Shmeeztut;

The cost of the concert in 2004 is 385 dollars, since the cost in 2005 is 10% less  we can say that the cost of the concert in 2005 is 90% of  $385. (Remember 100% - 10% = 90%). Now just do 385 times by .9 (90%/100% = ,9) and this equals $346.50 This is the cost of the concert in 2005. This makes sense because we knew it had to be less.

The cost in 2004 was 10% greater than in 2003 that means it was 100% + 10% more or 110% this is just 110/100 or 1.1 (this is how you convert any percent to a decimal so you can calculate with it). We now divide the $385 by 1.1 and get $35. This how much more the concert in 2004 is. Just do 385 - 35 = $350 this is what the concert in 2003 costs. This again makes sense because it had to be less.

See if this makes anything clearer for you. Work a few more problems like this one and it might become a little bit easier. Also ask the teacher to help you out a little. If none of that helps, its not the end of the world, just repost here.

bobbym

#56056 Re: Exercises » Logarithms » 2009-04-15 18:34:38

Hi ganesh;

This is my answer to for problem 2

We can change the original problem to read:

So x = 8

Is this OK?

bobbym

#56057 Re: Puzzles and Games » Divide set of numbers into 2 sets so diff of their sums is min. » 2009-04-15 17:26:34

Hi mathsyperson,

  The method I suggested would yield a good solution but not necessarily the optimal one. He should use your method to refine that solution, whether both of our ideas would yield the optimal solution in every case, I can't say.

   Looking at mathsypersons improvement, it might be wiser to alternately form the two lists biggest element and smallest in the first list. Then next biggest and next smallest in the second list and to alternate like this until the original list is exhausted.

bobbym

#56058 Re: Dark Discussions at Cafe Infinity » String Theory gets a Boost » 2009-04-15 06:35:09

Hi Jane;


    Good article, with much praise of Ed Witten and M-theory, I have to agree with Sheldon Glashow it appears that the M is just an inverted W for Witten. Guess I am an old dog at heart and that places me in the Glashow camp. Where do you stand on this?

#56059 Re: Dark Discussions at Cafe Infinity » String Theory gets a Boost » 2009-04-15 06:24:58

Hi Mathsisfun;

   If those results are correct about a nearly perfect liquid then they appear to have the first experimental evidence supporting the existence of strings. A serious slap in the face of Sheldon Glashow and the rest of the Ed Witten detractors.

bobbym

#56060 Re: Puzzles and Games » Divide set of numbers into 2 sets so diff of their sums is min. » 2009-04-15 06:07:17

Hi mathmagic;

   Just from looking at your example if I were programming this I would first sort the list. Then I would make the first list by taking out the largest and smallest elements of the original list. After taking out half the elements by pairing them in this way I would form the second set using the rest of the elements in the original list. Still pairing the largest with the smallest. This should have the effect of balancing the differences of the sums of the list. If this does not produce the best answer it should always provide something close to it. This would be my first try.

bobbym

#56061 Re: This is Cool » Issac Newton and windows/heart beat » 2009-04-15 05:49:10

Hi nubemet;

   I have only heard of Galileo doing this type of experiment. I believe it was done from the leaning tower off Pisa (but this may just be a legend).

bobbym

#56062 Re: This is Cool » Inside the mind of an autistic savant » 2009-04-15 05:15:16

Hi Jane;

    Nifty comments (bottom of the page) relating to genius and insanity and using magnetic fields and brain overload.

bobbym

#56063 Re: Introductions » Hi to everyone » 2009-04-15 04:57:52

Brilliant idea. If I remove my shoes and procure a hammer, I would be quite capable at hexadecimal.

#56064 Re: This is Cool » Inside the mind of an autistic savant » 2009-04-15 03:22:09

Hi;

  A really fascinating guy. These abilities are not as rare as most people believe. I have encountered it several times. I knew a guy that learned to program in a single night before he had ever seen a computer. He went through the giant C++ book ( by Herbert Schildt) in about 3 hours, became a super programmer and now cannot remember any of it. He discovered he had the skill to beat fairly strong chess players blindfolded and then lost it. He suddenly had the urge to draw and produced a large amount of good drawings and now can't draw at all. We don't exactly live in a world that is actively engaged in finding or encouraging these people, so mostly they remain buried.

bobbym

#56065 Re: This is Cool » Lockhart's Lament » 2009-04-15 02:05:06

Hi random_fruit;

   Take heart, it is much worse over here, where a high school senior math teacher just told me that none of his students were capable of making change from a cash register. None were able to compute a 15% tip even though they are being taught AP Calculus. Something called "Teaching to the test". Part of the new philosophy that it is cool to be stupid and uncool to be a nerd.

bobbym

#56067 Re: Exercises » Jane’s exercises » 2009-04-15 01:13:54

Hi Jane;

   I discovered that about 10 years ago but didn't notice your method of combining them and promptly forgot about the whole idea. So I guess its yours and I will always remember it as Jane's lemma.

bobbym

#56068 Re: Introductions » Hi to everyone » 2009-04-15 01:02:07

Hi Mathsisfun;

  Yes, it is. I lost both of my thumbs in a duel over who was the better mathematician and have trouble reaching the spacebar.

bobbym

#56069 Re: Exercises » Jane’s exercises » 2009-04-14 11:33:25

Hi Jane;

   You say you are not  very familiar with methods of solving difference equations but yet you came up with the idea of splitting the sequence into 2 coupled difference equations, each handling every other term. I salute you.


bobbym

#56070 Re: Dark Discussions at Cafe Infinity » Reaction of alkali metals with water » 2009-04-14 11:11:38

Hi John;

  I hope that is just a coincidence! I couldn't deal with it otherwise.

bobbym

#56071 Re: Dark Discussions at Cafe Infinity » Reaction of alkali metals with water » 2009-04-14 02:23:57

Hi Jane;

All of them react with water like this typical reaction for Sodium:

2 Na + 2H20 -> H2 + 2 NaOH

They form a strong base( NaOH - Sodium Hydroxide or lye) and release hydrogen gas. Magnesium which is not quite as active will still slowly release hydrogen if it is immersed in hot water. Thanks for finding this video because I had never seen Rubidium or Cesium when I was in class.

bobbym

#56072 Re: Exercises » Jane’s exercises » 2009-04-14 01:30:59

Hi Jane;

   Thanks for showing me yours, I am not that happy with mine, what justification do I have for the first step? I haven't proven that a(n+3)=a(n+2)+a(n+1)-a(n) is the recursion for that sequence. Can you provide some rigor to my arguments?

bobbym

#56073 Re: Puzzles and Games » positive integers » 2009-04-14 01:08:46

Hi Tony;

  I also only found (3,1) and (5,3) and I searched up until 3^3211 + 5. Have no proof yet that these are the only ones.

bobbym

#56074 Re: Exercises » Jane’s exercises » 2009-04-14 00:08:05

Hi Jane;

Answer for #21

Don't suppose anyone will ever see this but here goes:

The recurrence formula for your set of numbers is.

this has a characteristic equation of

x^3-x^2-x+1=0 which has roots of {-1,1,1}

This then is the general form of the solution:

we need to determine c1,c2, and c3 from the initial conditions

So the general solution is:

This agrees with your general solution at the bottom of problem 21

#56075 Re: Jai Ganesh's Puzzles » Level of Difficulty - III Questions. » 2009-04-13 06:25:37

Hi Ganesh;
For #9

Solve for x and y in terms of m to understand how x and y behave when m varies:

After a lot of algebraic thrashing and some trial and error:

These values of m satisfy the constraints x>0 and y>0

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