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#26 Re: Help Me ! » Equations of Motion » 2007-09-12 09:36:42

I'm trying learn to apply Neuton rules directly, and I've solved it this way:





S is maximal, then S' is 0, so:


When the rock goes back to earth, S(t) = 0, solving:

#27 Re: Help Me ! » Simplify the series » 2007-09-12 09:16:54

Ricky wrote:

As with any finite addition sequence, all addition is associative:

Absolutely right! That reminds me of this:
as your sum, but goes to infinity:

doesn't converge:

Why do we get different answers?
Because, as ricky pointed, addition is not nessesarly associative with infinite sequences. smile

#28 Re: Euler Avenue » Special numbers » 2007-09-09 06:21:25

Another counting system without null:
1-1
2-11
3-111
4-1111
ect.
tongue

#29 Re: Help Me ! » How do you calculate how many spheres can fit in a larger sphere? » 2007-09-07 22:18:32

Actually your question is very famous and hard. Such questins are known as spere-packing problems.
Here's a start:
http://en.wikipedia.org/wiki/Sphere_packing
If you want more information, i'm sure google will help.

#30 Re: Help Me ! » 1+x+x^2+x^3+... » 2007-09-07 07:30:58

If you use it very fraquently, you can write in the beginning "S(x) stands for..." and then use it.
I've seen a notebook with properties of the arctangens function, written 'A' for short.

#31 Re: Help Me ! » 1+x+x^2+x^3+... » 2007-09-07 05:06:08

We don't need a special function, because it's

when convergant.

#32 Re: Help Me ! » 1+x+x^2+x^3+... » 2007-09-06 19:18:36

What is "set variable"?

For the series to be convergent, is't nessesary x to be in the unary complex circle: Abs(x)<1.

#36 Re: Help Me ! » Sequences » 2007-09-06 05:14:19

Daniel123 wrote:

Why are recurrence relationships written in the form, for example:

?

Thanks.

That's not true. You can write it as you like. The difference is only in the domain for n-s. For example, if you're specifying the Fibonnaci sequence, you may write:


or:

#37 Re: This is Cool » implicit function renderer c++ » 2007-09-06 02:29:11

oh!
That's fascinating!
after you go around it, try going inside!
It's like moving in cheese!
smile

#40 Re: Help Me ! » solve » 2007-09-04 18:50:45

It's the only solution. Look at a plot of the above function to see it's strictly increasing for x>1 and x<-1.

#42 Re: Help Me ! » Diophantine Equation » 2007-08-28 19:09:09

And here is the plot - all points lie on a same plane!

#43 Re: Help Me ! » Number Theory » 2007-08-06 19:48:03

OK.
First, assuming you want only integer answers...
There are many ways, but I use this:
(it's long...)


,
so
should be integer. Call it w:


, so
should be integer, name it q:

, and (q-1)/2 should be integer.



Now:


, so
must be integer - m:


Now, returninig up:

and upper:

So solution is:
for r,m integers.
But there are other ways for expressing this, as:
ect.

#44 Re: Help Me ! » Absolutely "don't knowing what's going on"! Please have a look... » 2007-08-06 19:17:23

Ricky wrote:

Negative numbers under radicals aren't negative, they are complex.  And when you have nested radicals, the complex parts can cancel each other out leaving a real number.

You're right, but it's tricky that no complex numbers will occour in the nested radicals!
If you look at the first convergent:

,
you'll see that under the radical there is preciesly positive number, so we'll not have complex numbers at this stage.
But this happens with the second convergent too and with the others... - the last term always eliminates the root-of-negative thing!
So, even paradoxal at first sight, we can't even speak of complex numbers inside the radicals! sad
Or, in other words, every "sub-radical" is real, and it's bigger enough not to give negative answer when we substract its negative-fellow.

#45 Re: Help Me ! » Absolutely "don't knowing what's going on"! Please have a look... » 2007-08-06 17:46:39

George,Y wrote:

But the last is infinity if you allow infinite radicals.

Yes, it will be infinity (informal)
But the point is that (I hope you'll understand) the last term doesn't matter, because it's infinitely nested, so you "will never get up with it". So when we go to infinity, the last term "dissapears" and leaves only this "odd" negative numbers!

#46 Re: Help Me ! » Absolutely "don't knowing what's going on"! Please have a look... » 2007-08-06 17:38:56

I posted this, because there are identities, extracted by the exactly same way:
A simular nested radical is discovered by Ramanujan:


And this is true! But the last term here is infinity too.
Why this method works in some cases, in others - not?
And indeed, infinity is weird, so this may be true.
I'm maybe not sure the result will be one, but I'm pretty sure that this is not a divergent process!

#47 Help Me ! » Absolutely "don't knowing what's going on"! Please have a look... » 2007-08-06 01:32:08

krassi_holmz
Replies: 8

OK. Something pretty strange is going on here...
It's FACT that for positive integer k, we have:


OK?
Noww..., we can write this in this way: (k is positive)

Now, because k is positive integer, such is:

So we can write it as we can write k:

and...

Plugging this into the expression for k:

Now we do the same thing, but for
:


Plugging again:

As we continue infinitely many times, wa have:

So we got nice representation of k as nested radicals.
For example, put k=1:


BUT 1 IS POSITIVE, AND ALL THE NUMBERS IN THE RADICALS (EXCEPT THE LAST, WHICH IS INFINITLY DEEP) ARE NEGATIVE!!!!

#49 Re: Help Me ! » Tough one... » 2007-08-03 08:17:03

mpthomas wrote:

So close...but so far away...

What do you mean?

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