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#26 Re: Help Me ! » Equation Involving Radicals » 2012-07-29 19:47:11

Hi bob bundy!

An average of 20 storms and/or typhoons per year enters the Philippines usually from July through October.

By the way, I'm now moving on to solving problems about inequalities then 2 dimensional coordinate system.
Glad I could ask problems I can't solve here! smile

#27 Re: Help Me ! » Equation Involving Radicals » 2012-07-29 15:23:18

It's now 11:24 in the morning here.  Last night, something went wrong with the internet connection due to the typhoon so only now was I able to see the other replies.

anonimnystefy and bob bundy: I tried to solve the problem following your ideas. I got it now.

Thanks again anonimnystefy,bob bundy and bobbym!
Till next time!:)

#28 Re: Help Me ! » Equation Involving Radicals » 2012-07-29 03:56:23

Thank you for the reply. I forgot to tell you that I'm from the Philippines. Until next time! Have a nice day!:)

#29 Re: Help Me ! » Equation Involving Radicals » 2012-07-29 03:35:11

Thank you anonimnystefy! smile

Just curious, what is now the time in your place? By the way, it's now 11:38 pm here.:)

#30 Re: Help Me ! » Equation Involving Radicals » 2012-07-29 02:32:07

I'll follow your advice. smile
Thanks again!

#33 Help Me ! » Equation Involving Radicals » 2012-07-29 01:57:25

295Ja
Replies: 32

Hello! I'm here again. Please teach me how to solve equation like this one:
    sqrt(2x+3)-sqrt(x-2)=sqrt(x+1)                          * Note: sqrt- Square root of

What makes it hard for me to solve the above equation is that it has 3 terms with radical expression.
If it only has one or two radical expression I could easily eliminate the radicals from the equation after isolating it
then go on with solving the equation that arise.
But suppose I have more than 2 terms having radical expression(like on my given problem), how could I eliminate the radicals?

Thank you in advance!:)

#34 Re: Help Me ! » Quadratic Equation » 2012-07-29 00:34:03

bob bundy thank you very much for being kind enough to explain further. I really appreciate it and I could say that I now understand it better.
smile

#35 Re: Help Me ! » Quadratic Equation » 2012-07-29 00:30:19

bobbym I can't help it but to admire you more. big_smile

#36 Re: Help Me ! » Quadratic Equation » 2012-07-28 22:07:52

Whooh! I admire you for being awake this time around knowing that it's an early morning thereup.

#37 Re: Help Me ! » Quadratic Equation » 2012-07-28 21:52:50

Thank you for clarifying that to me! smile

I'm just curious, what is now the time at your place? By the way, I'm from the Philippines and its now 5:55 pm here.:D

#38 Re: Help Me ! » Quadratic Equation » 2012-07-28 21:15:28

Bob thank you for helping! I hope you won't mind if I'll visit this forum more often and post problems I'll find confusing in the future.  big_smile

May I just ask for one clarification? I remember my teacher told us that we must avoid doing cross multiplication
when there is a variable involve. But I just noticed that  to arrive on the answer to my question, x must be cross multiply to -3±√ 17.  If I'll just state on my solution that x≠0, will it be allright to do a cross-multiplication?

#39 Help Me ! » Quadratic Equation » 2012-07-28 18:25:45

295Ja
Replies: 13

Hello everyone! Please help me to continue solving this equation:
-7((1/x)-1)=4+2((1/x)-1)^2

Here's what I did:

I let w= (1/x)-1

So I have:

-7w=4+2w^2
2w^2+7w+4=0

Then I  factored it using quadratic equation so I've got:

w= (-7±√17)/4   *Note: √17 is square root of 17.

Since w= (1/x)-1

(1/x)-1= (-7+√17)/4  and (1/x)-1= (-7-√17)/4

I find it hard  to evaluate the value of x from the 2 equations I've got. Maybe I've done something wrong in simplifying these 2 or much worse,my entire solution is wrong.So please help me find the way out. I'm also looking for other way to solve it. If someone out there know it, kindly  share it to me. I would be very grateful for someone who'd help. I'd be waiting for replies then! Have a nice day!:D

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