Math Is Fun Forum
You are not logged in.
- Topics: Active | Unanswered
#26 Re: Help Me ! » centroids » 2012-12-11 00:43:04
Hello bob;
i know how to locate the centroids of those individual figures...........
if u want i can give it myself but 'm having trouble locating the area of that shaded portion..........
#27 Re: Help Me ! » centroids » 2012-12-10 01:13:48
yup bob ....
that's it .....
how can the centroid of that shaded area be located.......
#28 Re: Help Me ! » centroids » 2012-12-10 01:07:29
Hello bob bundy.....
that's not very much of a boomerang .....
but the centroid of the area that looks like a boomerang is required.......
#29 Re: Help Me ! » centroids » 2012-12-10 00:55:19
Hello;
'm actually trying it in a theoretical way............
here's the problem.........
consider a square with its side equal to 200 units
from both the ends of the base two quarter circle of radii 200 units are inscribed inside the square and a semi circle with a radius of 100 units is drawn joining the sides of the base.....
#30 Help Me ! » centroids » 2012-12-09 16:55:35
- Maiya
- Replies: 44
Hello guys;
i was wondering if anyone would help me find the centroid of a boomerang.......
???
#31 Re: Help Me ! » Itegrals » 2012-01-23 20:15:14
why has j=sqrt cotx been considered ..............
#32 Re: Help Me ! » Itegrals » 2012-01-19 23:32:47
thank you guys that was a great help.......!!!!
thank u juantheron ; but isn't it supposed to be root 2 in the first part where u got the answer as
i+j=sin inverse of sinx-cosx
#33 Re: Help Me ! » Itegrals » 2012-01-17 19:45:43
plz help
#34 Help Me ! » Itegrals » 2012-01-17 19:44:41
- Maiya
- Replies: 6
what is the integral of square root of tanx dx,..............??
#35 Re: Jai Ganesh's Puzzles » Trigonometry » 2011-11-28 23:40:51
Hello Ganesh;
#36 Re: Jai Ganesh's Puzzles » Trigonometry » 2011-11-27 23:56:35
Hello Ganesh;
#37 Re: Jai Ganesh's Puzzles » Trigonometry » 2011-11-25 20:38:23
Hello Ganesh;
#38 Re: Help Me ! » Equations » 2011-11-22 23:45:49
thank u and what is cardan's method for solving cubic equations
#39 Re: Help Me ! » Equations » 2011-11-21 21:38:01
hmmm great....
#40 Re: Help Me ! » Equations » 2011-11-21 21:32:35
#41 Re: Help Me ! » Equations » 2011-11-21 21:30:17
thats what (y-3)(y+4)=0
#42 Re: Help Me ! » Equations » 2011-11-21 21:26:55
ya the roots are 3 & -4
#43 Re: Help Me ! » Equations » 2011-11-21 21:22:50
so thats all about it........
#44 Re: Help Me ! » Equations » 2011-11-21 21:18:01
so now equation 1 is y^2+y-12=0
#45 Re: Help Me ! » Equations » 2011-11-21 21:08:00
ya so biquadratic equations have only even powers..
is that so???
#46 Re: Help Me ! » Equations » 2011-11-21 20:55:48
ya thats what
i couldn't get that plus or minus properly
#47 Re: Help Me ! » Equations » 2011-11-21 20:42:40
this it right???
#48 Re: Help Me ! » Equations » 2011-11-21 20:37:08
ya it can be reduced to (x+1)^2
#49 Re: Help Me ! » Equations » 2011-11-21 20:30:27
Hello Bobbym;
as i'm a beginner no equations........:-(
any general forms???
#50 Re: Help Me ! » Equations » 2011-11-21 20:17:51
no no that's okay bobbym;
is there any method to solve biquadrtic equations