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Hi, nice to meet you. I'm new to this stuff.
for #1, we have n=1005, and hence we should have : dim(A_3/2)=n=1005 ??
Hello, nice to meet you.
we have :
=> : Rcos(a)=P=mg => R=mg/cos(a)
and T=Rsin(a)=mg*tan(a)
m=46kg, g~9.81 kg*m/s^2, a=38°
Hallo, nice to meet you. I'm new in here.
let g be the acceleration of gravity, (i.e ~9.81m/s^2)
i) the tension is the sum of forces acting on a point of the string, hence : (0.7-0.3)g kg*m/s^2
ii) on the pulley act a force of (0.3+0.7)g=1g kg*m/s^2 (vertical)
Hope this is in some way right.
c ya.
Hallo,
I wanted to ask how to erase the account ? I considered that my exam to this was failed, and then useless to continue.
Hello, nice to meet you. I'm for the first time on this forum.
It was late, in fact the answer is no from the onset, because of unit incohence. (this I saw afterwards).
But I did the calculation
Since a long time that I haven't made this calculation, I did like :
then I squared the operators :
which gave :
It's not the same, but I don't know if an error went inside..sorry.
It was nice to meet you, but this failed. Bye.