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#27 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-09 03:46:35

Thanks for the help bob bundy, makes sense now and yeah I know how to get the asymptotes.

I need to know the steps to these before the test.. If when available and whichever you can, please do these (not much time left so I just need to quickly know the steps to questions like these textbook questions..

Sketch each of the following, clearly showing the position of the asymptotes and the intercepts with the axes (correct to 1 decimal place where appropriate).
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Sketch the graphs of each of the following.
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Thank you

#28 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-09 01:28:56

Yeah but... as in....
What does 2 - √6 /2 actually mean? I know it's strange but... I don't know where to plot it even though I've got that answer... It reads 2 take away √6 which is divided by 2? How will we know where that is in the graph?

#30 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-09 01:08:42

later bob bundy wink

so i followed the steps and got

2 - (√6/-2)

Right? smile

I still don't know what this means though...

#32 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-09 00:49:12

Yes it becomes 2

bob bundy;
Yeah I found the y int. need help with the x axis

#33 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-09 00:41:04

Yeah I'm online smile The questions to the worksheet you gave is kind of different to what we are studying. It has tan etc. We are also doing cubic function, hyperbola, truncus, square root, absolute value.. More of transformations like dilation reflection etc, finding aymptotes and axis' and domain + range + Sketching them accordingly to what is being asked.

Hey bobbym;

You're right, I'm mostly comfortable with what is being asked but when it gets to fractions, I'm really bad at it. That's cause I don't know the steps to do these things as I havent practice them for a long time. I really don't know what to do next to get the solution...

#34 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-09 00:19:24

Hey bobbym;

so what did we find here? Are they the x intercepts? If so.. I don't understand what that means... As in how will we know to where we are going to plot it? -8...+2...Square root of 6... and divided by -4..??

#35 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-09 00:09:56

You're left with

-8 2√6
---------
-4

-2 2√6 ???

Hey Bob Bundy;
they are excellent tutorials, thanks for that! I'm doing Maths Methods in high school (Australia) so I don't know what C3 is?

#36 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-08 22:40:53

Okay but... How do we end up having 2 -+ √3/2

Hey bob bundy;
It's for a functions test.. (without calculator) but there's going to be one with calculator for matrices later.

#38 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-08 21:12:22

Solving the quadratic...
-8 +- √ 8^2 - 4(-2)(-5)
--------------------------
-4


-8 +- √ 64 - 40
-----------------
-4


-8 +- √ 24
------------
-4

I don't know how to do what is in the square root.? So 2x3x2x2 = 24... Do we use them in some way?

#39 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-08 20:40:59

Could you explain it the same way to get 2+-√ 3/2 (x intercepts) for the same question please.

#40 Re: Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-08 20:17:47

Hey;

No I meant 4b) I don't know how to sketch that. I can find the domain and range... + asymptotes... but I don't know how to do it when x equals zero... I don't know how to re arrange it to get (-1(-1/4) and also when the f(x) equals zero... to get 2+√ 3/2 . I'm really not good at getting the x intercepts for things like that.. How do we get to the solution? I don't know the steps. This can be basic algebra but please if you have the time to...

Last question... How do we do this? Getting the x intercepts for the absolute value?

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#41 Help Me ! » Revision [Question and Answers Provided] Need help understanding ASAP » 2011-03-08 12:56:52

Alive
Replies: 43

Do we use binomial theorem for this?
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I understand a and b.. But for c) how do you get (-5,-16) ? Also for e) The question for the revision paper wasn't printed out properly, but I've seen the teacher do lots of things like this, what do you think the question would be or if you could do another example that looks like it?
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I know how to do all of them except:
For 3b) What does linear factors mean? and how did the answer become x^3 + 2x^2 -5x - 6? Did they use long division?
For 4b) How do we sketch this? How do we know it has a shape like that?

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I also have one more question but don't have the time to upload, I can't stress enough how important these questions are so please if you can answer them with detailed answers... I know how to do all except the ones that I pointed out above. Thank you very much smile

#42 Re: Help Me ! » Help (Images provided) » 2011-03-07 22:58:28

Wait... the answer is the same..

4x - 1
------
x-2

No need of dividing anymore... I guess they did do it the long way, Thanks for the help!

#43 Re: Help Me ! » Help (Images provided) » 2011-03-07 22:26:56

For the third one...

4 - (1/x)
---------
1-2(1/x)

We times by x both..

4x - 1
-----
x - 2

Now we have to divide?? When do we know to divide or times..??
The rest is pretty straightforward.. But when do we know to divide or times..

#44 Help Me ! » Help (Images provided) » 2011-03-07 21:50:59

Alive
Replies: 5

These are 3 separate questions. How do you get the first few parts of the solution. i.e: 1/(1/a)-1... = 1/(1/a)-(a/a) = 1/(1-a)/a and the rest? What rules are there to learn to master these type of questions?

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#45 Help Me ! » Inverse functions » 2011-03-06 14:09:34

Alive
Replies: 1

Could you give basic and advanced examples of inverse functions.. one to one functions etc..

#46 Re: Help Me ! » Functions and Transformations.. one step at a time.. » 2011-03-02 02:03:57

Thanks for the effort guys, it all makes sense to me now smile

#47 Re: Help Me ! » Functions and Transformations.. one step at a time.. » 2011-03-02 01:38:13

We were working on (Truncus)

The actual question has 4 at the end as -4... I typed it wrong from my textbook.... which won't matter in this case? Cause there may be questions like these lying around?

#48 Re: Help Me ! » Please help! » 2011-03-02 01:35:54

Hey bob bundy,
It's alright lol smile Yeah I'm looking forward to it as well big_smile

#50 Re: Help Me ! » Please help! » 2011-03-02 01:21:39

Hey bob bundy,
I was just answering Kenny's question which obviously is just a combination to use.

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