You are not logged in.
Yeah the fraction was really confusing for me. Thank you very much for helping me out on this Maburo!
Awesome! Thank you very much for the help! It's definitely much easier for me now.
For 16, I got the answer 'C' [(2r + 3)(3r + 2) ].
For 18:
18. 5n^2 + 19n - 4
A (n + 4)(5n - 1)
B (5n - 4)(n + 1)
C (5n - 4)(n - 1)
D (n - 4)(5n + 1)
E (n - 2)(5n + 2)
F cannot be factored
I choose 'F' because there is nothing I can think of that will add up to 4 when times together and add up to 19 when added together.
19:
19. m^2 + (5/12)m - (1/6)
A (m - 6)(m + 1)
B (m - 2/3)(m - 1/4)
C cannot be factored
D (m - 1/4)(m + 2/3)
E (m/12 + 2)(m/12 - 3)
F (m - 1/4)(m - 1/3)
I was having trouble trying to find the factors for these, I'm not too great with fractions.
20:
20. a^2 + 4a + 21
A (a + 7)(a - 3)
B a(a + 4) + 21
C (a + 21)(a - 1)
D (a + 3)(a - 7)
E (a + 7)(a + 3)
F cannot be factored
Answer is 'F.'
Hello everyone I'm back after a pretty long time
I haven't done math in quite a while so I'm going to need help with this. Basically I just need help to understand how to go through the equations step-by-step and then tell me if I'm right or wrong. Here they are:
12. 2x^2 + 23x - 12
A (2x - 6)(x + 2)
B(2x - 3)(x + 4)
C(2x + 12)(x - 1)
D(2x - 1)(x + 12)
E (x - 6)(x + 2)
F (2x - 1)(x - 12)
Answer:
2x^2 + 23x - 12
-1 and 24 are the common factors so:
2x^2 - x + 24x - 12
(2x^2 - x) + (24x - 12)
Factor Out:
x(2x - 1)+12(2x - 1)
The '(2x - 1)' is a common factor so we factor it out, being left with:
(2x - 1)(x + 12)
Final Answer Being D
Now from here on out I'm going to be needing some help.
13. a^2 + 4ab - 3b^2
A (a - 3b)(a - b)
B(a - b)(a + 3b)
C cannot be factored
D(a + b)(a + 3b)
E a(a + 4b) -3(-b)
F (a + b)(a - 3b)
I'm not sure how to get the answer using the equation problem. I do know how to work the factor answers backwards and came with the idea that the answer might be 'F.' I want to be sure if I am right and even if I am, I still want to understand how I can find the factors for this. I find it quite confusing mostly because of the double variables it has.
When we are done with the first two we can move on to the rest.
14. 9k^2 + 30kn + 25n^2
A (9k + 5n)(k + n)
B(3k - 5n)(3k + 5n)
C(3k - 5)(3k - 5)
D(3k + 5n)2
E (9k + 25)(k + 1)
F (9k - 5)(9k - 5)
15. 2a^2-32
A 2(a^2 - 18)
B 2(a - 4)2
C (2a - 16)(a + 2)
D 2(a^2 - 16)
E 2(a - 4)(a + 4)
F cannot be factored
16. 6r^2 + 13r + 6
A 6(r^2 + 1) + 13
B(6r + 6)(r + 1)
C(2r + 3)(3r + 2)
D(2r + 2)(3r + 3)
E (6r + 1)(r + 6)
F cannot be factored
17. 4m^4 - p^2
A (4m2 - p)(m + p)
Bcannot be factored
C(2m^2 + p2)^2
D(2m^2 - p2)^2
E (4m + p)(m3 - p)
F (2m^2-p)(2m^2+p)
18. 5n^2 + 19n - 4
A (n + 4)(5n - 1)
B(5n - 4)(n + 1)
C(5n - 4)(n - 1)
D(n - 4)(5n + 1)
E (n - 2)(5n + 2)
F cannot be factored
19. m^2 + (5/12)m - (1/6)
A (m - 6)(m + 1)
B(m - 2/3)(m - 1/4)
Ccannot be factored
D(m - 1/4)(m + 2/3)
E (m/12 + 2)(m/12 - 3)
F (m - 1/4)(m - 1/3)
20. a^2 + 4a + 21
A (a + 7)(a - 3)
Ba(a + 4) + 21
C(a + 21)(a - 1)
D(a + 3)(a - 7)
E (a + 7)(a + 3)
F cannot be factored
Hi bobbym and anonimnystefy , thank you very much!
And Bob, from what I have heard, AFTER I am done with my high schooling program, I am going to have to take a SAT test which basically is there to help any college I am trying to get into understand what points I may be weak in (points as in subjects such as math, English, history, etc.). Now I was also recommended by the school to take certain courses from my local community college which would add to my credits and will allow me to get into a better college (not exactly sure how it may be in the UK, but in the US you need 22 credits to get into a college, each course will give you different amounts of credits, any where from 0.5 - 1.00).
So my plan is to get as many credits I can which could help me get into a good college. I have had two colleges in mind that are not too far from where I am and I know some people who have gone there, so from what they have said these colleges seem to be pretty good.
As for contacting K12, I have already done so some few weeks ago and am waiting for their reply to see if I qualify for their schooling program.
Once again, I just really want to thank you all for your help! It would have been super hard for me to finish my Algebra and Geometry but, with you guys, it's been a smooth road!
Thank you very much for looking into this Bob! I've heard and read a lot of great things about K12. One of my friends who was in K12 did not finish the high school program. Instead, he transferred to another private school which was supposed to be better.
After some web surfing, I came upon this page on K12:
http://www.k12.com/take-a-peek/college-acceptances#.UlC1koZmiSo
It's a list of the many colleges/universities that students who graduated from K12 were accepted into. I am familiar with on of the colleges, B.U. (Boston University). I know someone who had gone there and it's supposed to be one of the top colleges in the U.S. So from this page, I guess students do graduate with some kind of certificate or diploma!
Well I might be enrolling into K12 (http://www.k12.com/). I have heard quite a few great things about it and I know a few friends who have been doing K12. It seems pretty good since I will be able to actually talk to my teachers if I need help or have any questions.
Well I might be switching schools. But if I do need help, I will surely be back here! This is an awesome place with awesome people!
I sent in the revision and 'D' was correct. Got a 10.000 on the lesson and now my Geometry course is finished. I would love to thank you, Bobbym and anonimnystefy for your help. It was and still is highly appreciated!
Wow... that was so simple. Thank you for your help! I submitted the lesson and got ONE wrong. It was #8. Let me bring it up again:
After some time we agreed that measure B was greater than measure A, so the answer would be 'B'. But it was marked wrong. I know angle A is NOT bigger than angle B, and they are both definitely no equal, so I thought maybe the correct answer would be 'D'?
I decided to go with your second opinion. I used 'B':
144 - 18 (sqrt 3)
144 - 31.1769
112.8230
That's the closest I got. Am I doing the equation correctly?
#17 - I got 16.01. Squared it to get 4.00. So answer is 'A'.
#18 - So 5.04 is the answer, I would have to round it up to 5 to get 'A'?
---
#20 - So 144 - 30.96 = 113.04. Where would I move on from here?
#17 - so it would be 3 x volume DEVIDED by what pie x height equals?
#18 - So it would be 12 x .42 = 5.04
Assuming that A means area, how would I use the area to get the height?
---
#20 - Area of the entire square is 144. The inner triangle I used this equation I found online. Tell me if it's right or wrong (or maybe if I am doing it wrong):
A = 1/2 x (a) x (b) x sin(C)
A = 1/2 x (12) x (6) x sin(60)
A = 1/2 x (72) x sin(60)
A = 36 x sin(60)
A = 36 x .86
A = 30.96
Not sure why the above picture hasn't appeared, but here is another hopefully it will work:
Little confusing, but I'm understanding it more. Thanks!
Here are the final 5 Geometry problems:
[img]ttp://imageshack.us/a/img845/3231/ht1p.png[/img]
#16 - 'A'
#17 - They want me to round it up to the nearest whole number. The radius is 6.5. Am I supposed to go upward to get answer 'C' - 8 OR downwards to get answer 'B' - 5?
#18 - **need help how to solve
#19 - 'C'
#20 - **not entirely sure how to solve this one.
It's starting to make more sense. I'm looking between 'B' and 'C' but, I think I will go with 'B'.
Not entirely. Could you explain?
Alright.Here is the next :
#11 - I go with 'D'
#12 - 'C'
#13 - 'C'
#14 - 'A'
#15 - 'C'
So measure B is greater than measure A.
#8 - So 6.32 would be the answer for the third side correct? If so, would I be using the method shown on this webpage to find my angles:
http://www.mathsisfun.com/algebra/trig-solving-sss-triangles.html
#10 - I see it now! KQ is 28, KN is 16. They want NQ. So KQ - KN which is 28 - 16 = 12!
#3 - I see now it makes MUCH more sense. AC and CE make up the entire line. D is the midpoint of CE. So if DE = 5, then CE = 10. And since AC = CE, AC also equals 10. We want to find out length of AB. So what we do is AC - BC which is 10 - 2 = 8!
---
#8 -
I go an answer of 6.32. Is that correct so far?
#10 - 16 x 14/8 = 28, which is 'A'
No I haven't. I was hoping you would help explain to me then we can start on the next 5.
#4 - so answer is 'C'! Now if the angles were on the opposite side, would it be considered complementary?
As we go through that, here are the next 5:
#6 - answer 'C'
#7 - answer 'C' (lots of answers being 'C' so far!)
#8 - i go with 'A'
#9 - 'B'
#10 - **not sure how I would get the measusements for that. i know that the top triangle has sides of 16 - 16 - 8. The shape on the bottom has a base of 14 and if you would say a "top" of 8.
#1 - I see now, I just had the two final steps (diving by two then adding to 35) missing from my calculations. So the true answers will be 'C'
#4 - i'm not sure exactly what I would be searching to find out more about this problem. What would this be called?
#1 - how would I do this? I thought complimentary angles added up to 90 degrees and so that is why I chose 'B', 55 degrees.
#3 - so C is the answer, but in the future if I ever come across anything like this, how would I do the work to get my answer?
#4 - would prefer help understanding how to solve this.
This is my final test. If you help me with this, then you have officially helped me finish geometry! I will be posting 5 at a time. In this lesson, there are quite a few pictures or math symbols i am not sure how to make. So I just took an image of the page with the first 5 questions and will post it here to view.
#1 - my answer is 'B'
#2 - my answer is 'B'
#3 - *need help understanding how to solve
#4 - i think 'A' would be the answer
#5 'D'