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I don't know if my answer was wrong yet, but I got .28. Above the mean is + and below is -. I will check the chart in my book for your answer.
Yes, that's exactly it.
Sorry it's supposed to be 451 g. and the other number is :
no more than 453 g
my error
Here's a good one for Sat.
A box of cereal contains 452 g with a standard deviation of 10.2 g. Find the probability
that a box contains more than 460 g. Assume a normal distribution. Use a x-score rounded to 2 decimal places.
Thanks.
I will post a problem in a new topic. I have been getting a few right this morning, so there is light at the end of the road. haha
Correction above the mean and below it.
Hello, and good morning. I don't remember since i typed it in and it was correct last night. The table was very helpful, if I can read it accurately.
How do I differentiate between below the mean and below it. I know to the left is negative and right positive.
I am working on more math. So many things to ask. I have a quiz on this stuff than another test online.
Thank you so much. Everything helps push me along. Test next week on this stuff.
So this is a bit of Trig. and Algebra combined or what is it? And the chart is great, but how do i find my way around it, mean, stand. dev., percentage. etc? I don't mean to sound stupid.
yes, i want to know how they are solved. I have a test on five chapters next Friday.
z = -1.6 and z = - 0.8 is ____%.
How do you do this? Can u explain it for me. Thanks.
Hello, it took 13. Thank you so very much.
I don't know why but it's not taking that answer. The online homework site is picky about how it wants the answer.
It just said to round to the nearest integar.
Thanks, it showed 18%. It rounded it up. It gave me another one when I missed it.
z= - 1.4 and z = - 0.8 is ___%.
yes. Can this one be solved from the graph you posted yesterday?
Find the per cent of the total area under the standard normal curve between the following z-scores.
z= -1.4 and z = -0.65
The per cent of the total area between z= -1.4 and z = -.65 is _____%.
Thanks.
I have been here a short time. Bobbym seems like a professor or a retired one.
Then again, he could be in college and just very good at math.
I didn't know how to use the graph you posted, so I just kept plugging away with the calculator. Thanks so much.
Don't know. I will go in as a junior so will have to see.
The first one, .4 i think it was .0155, later i had a problem with .8 that was 29%.
I am only taking these 3 last units of math because it is required. I grad. with associate of fine arts degree in about four wks. Then onto a four yr. university where my major will be Creative writing/Journalism. They did not have a major in Journalism here, which is my thing.
I put all required math till last, so this is basically why i am against the wall. I passed Algebra last semester. Then the last required 3 this semester should do me in. I get by with it and may come out with a B, but that will be the best I can pull off in one of them.
The answer was 29%. I still don't understand it. I get half the problem right and there at the last part do something wrong.
Oh wow! I will have to look at this one to see how it's solved. I don't know how you did that.
Thanks much.
Okay, I reworked that one and understand it better; I think. Both sides are being multiplied then divided by five.
Thank you in advance!
Find the percentage of area under the standard normal curve that is specified:
Between z=0 and z = -04.
The percentage of area under the standard normal curve is_______%
Second problem:
Find the percentage of area under a normal curve between the mean and -0.08 deviations from the mean.
Percentage from the area under the normal curve between the mean and -.08 standard deviations from the mean is ____%
Third problem:
Find the percentage of the total area under the standard normal curve between the following z scores:
z= - 1.4 and z = -0.65 is ____%.
It's the correct answer for sure.
Truthfully, i don't know if i understand it or not. I am going to post more problems. I wish I had found this forum last semester when I had Algebra. It's a wonderful forum with genius mathematicians.