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  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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#376 Re: Dark Discussions at Cafe Infinity » Whats my line? » 2014-09-24 05:03:20

He is cpnnected to science, but as John Daly would say, I have to give you a qualified yes, his work is somewhat connected to science, but it is not his career's focus.

No, he hasn't been dead yet (assuming you do not believe in reincarnations).

#377 Re: Dark Discussions at Cafe Infinity » Whats my line? » 2014-09-24 04:54:55

Not likely, but it is possible.

I watched a few episodes of the original show and I was amazed when I saw Dali! His responses were so funny.

Also, your statement in the OP is incorrect, that show is not the longest running one.

#379 Re: Dark Discussions at Cafe Infinity » Whats my line? » 2014-09-24 04:47:24

As far as I know he has not anything to do with snails, has not been committed to a hospital for mental illnesses, is not a Kabbobly Doist (whatever that might be) and does not have a personal connection to me.

And, bobbym, shame on you for trying!

#380 Re: Guestbook » Please tell me » 2014-09-23 20:19:32

That's no a Latex problem, it's me not checking. It should go from i=1 and is the answer for the incorrect problem.

Yes, I know.

#381 Re: Guestbook » Please tell me » 2014-09-23 20:02:25

Is this a Brilliant problem?

#383 Re: Guestbook » Please tell me » 2014-09-23 19:33:55

What's wrong with my LaTeX?

What's my line?

#384 Re: Guestbook » Please tell me » 2014-09-23 19:06:45

Ah, yes, that is correct. I was thinking of the x term.

Have you seen the thread that emerged? smile

#385 Re: Guestbook » Please tell me » 2014-09-23 18:56:48

Yes, it is, I have edited it accordingly.

If I am not mistaken, the x^99 term should be

#386 Re: Guestbook » Please tell me » 2014-09-23 18:49:45

Hi Bob

It's M syntax. I'll try to run it, he basically wants the x^99 term of

#388 Re: Dark Discussions at Cafe Infinity » Whats my line? » 2014-09-23 13:48:21

No, he is not a criminal, nor has he, I believe, ever been designated as one.

#391 Re: Dark Discussions at Cafe Infinity » Whats my line? » 2014-09-23 12:34:24

Hello everyone

What's my line?

DkcKMeQ.jpg

(I hope there won't be any image Googling this time.)

#393 Re: Help Me ! » Sin,Cos, Tan, Sec, Csc, Cot. » 2014-09-23 03:01:40

Hi cyerra

Welcome to the forum! smile

Yes, those answers all correct. Nice work!

#395 Re: Exercises » Bitter snails » 2014-09-23 01:18:47

Okay, so, we think, how can we group the n snails into k groups, given a smaller grouping with n-1 snails. The first case is if we group the n-1 snails. If we do that, the last snail goes into a group of its own, and that group can be put in between any two other in k ways, so that would be k*a(n-1,k-1).

The other case is when the n-1 snails are already grouped into k groups. There we just have to put the last snails into one of those groups, which we can also do in k ways, so the total number of ways for this case is k*a(n-1,k). Just add the two, and there you have it.

#396 Re: Exercises » Bitter snails » 2014-09-23 00:45:34

n is the number of snails, k the number of people.

#397 Re: Exercises » Bitter snails » 2014-09-22 03:51:54

anonimnystefy wrote:

You look at what happens when you bring in another snail. You can either put it in a group with other snails or put it in a group of its own.

#398 Re: Exercises » Bitter snails » 2014-09-22 03:04:53

Either way, I do not see a reason to use that command here.

#399 Re: Exercises » Bitter snails » 2014-09-22 02:36:17

Won't it just take longer?

#400 Re: Exercises » Bitter snails » 2014-09-22 02:31:42

Hi

a[1, 1] = 1;
a[1, k_] := 0;
a[n_, 1] := 1;
a[n_, k_] := k (a[n - 1, k - 1] + a[n - 1, k]);
a[15, 4]

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