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And the addition table.
Here is pi (to 30 places after the decimal) shown
normally and pi in new Winter sytem.
I called it the Winter system because I like winter and
also you can remember that you get below zero temperatures
in the winter like the numbers used here.
3. 1 4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9
3. 1 4 2-4-1 3-4 5 4-4-1 0-2-1 3 2 4-2 5-4 3-4 4 3 4-2 3 3-2-1
You can obtain the above conversion just by working
from left to right or from right to left on the normal
number pi. If you go right to left, it is very easy.
Simply carry the 1 if a conversion to negative is made.
So starting at the end of the above pi, look at the 9.
Since 9 isn't allowed in the Winter system, you use need
to think ten minus one. Nine in the Winter system is a
two digit number and is written 1-1. A 1 in the ten's place
and a -1 in the one's place. So you take the -1 and write it
down below the 9. Then you carry the 1 from the ten's place.
Now we convert the next digit to the left seen above
and it is a seven. Since we had carried a one, we add it to
the seven and get eight. Then we convert eight to the Winter
system and think "eight is not allowed because it is above 5,
so eight is ten minus two". So "8" is "1-2". So write down
the -2 and carry the 1. If you run across a case where you
carry a one onto a 9, then you think okay, ten, and ten is
still 10 in Winter system, so write down zero and carry the
one. So that's my explanation of going from right to left
and converting from normal numbers to the Winter system.
If you go left to right you have to look ahead a few digits
to see what's coming next. The explanation of that is
more complicated than going right to left, but all I think
I should say is the following and let you work it out for
yourself if you want to do it that way.
A "0" digit may remain "0" or may change to "1".
A "1" digit may remain "1" or may change to "2".
A "2" digit may remain "2" or may change to "3".
A "3" digit may remain "3" or may change to "4".
A "4" digit may remain "4" or may change to "5".
A "5" digit may remain "5" or may change to "-4".
A "6" digit will change to "-3" or "-4".
A "7" digit will change to "-2" or "-3".
A "8" digit will change to "-1" or "-2".
A "9" digit will change to " 0" or "-1".
Good luck playing around with the new Winter number
system. If you have any questions, just ask!
1/7 is normally 0.142857 repeating. Now it is 0.143-1-4-3 repeating! I wonder what I'll find next?
I went to bed and then I had a great idea so I got back up and worked on this through the night.
I hope you like it as much as I do. Imagine the possibilities!
Here is an example comparing our number system to the new Winter number system.
285
x64
-------
18240
or in this new Winter number system we have
3-2 5
x 1-4 4
----------
1 1 4 0
-1-1-4 0
3-2 5
-------------
2-2 2 4 0
Hey, this is really neat! Good idea.
I guess 1/18 chance if they can't both be the same chess square.
I thought some elementary school teacher might like this.
It's kind of nice I think.
But it's not about changing your mind, it's what they have done. They chose not to open the curtain with
the car for suspense. See what I mean. I don't know the math behind what I'm saying though.
I think that you should switch because they didn't open the goat curtain at random, they may have specifically
have chosen the goat, not the car behind the other curtain. I think I heard this long ago, some question
analogous to this one.
I just thought this up. Use base-10 but limit yourself to the digits negative
four to positive five. In the left column below I am counting from 1 to 20.
In the right column I show the square of the number.
1 1
2 4
3 1-1
4 2-4
5 2 5
1-4 4-4
1-3 5-1
1-2 1-4 4
1-1 1-2 1
1 0 1 0 0
1 1 1 2 1
1 2 1 4 4
1 3 2-3-1
1 4 2 0-4
1 5 2 2 5
2-4 3-4-4
2-3 3-1-1
2-2 3 2 4
2-1 4-4 1
2 0 4 0 0
When I was learning about angles of atoms in crystals in Chem 1 at WPI in Worcester, Massachusetts in 1986, the
tetrahedron was one of the 3-d configurations. I don't remember why, but they wanted us to figure out the
angle from the center of the tetrahedron to any two of the vertices. So I spent all weekend on that
and used complicated navigation formulas to get an answer. Then I tried to figure out if this number
for the answer could be expressed simpler, and finally I found out the easy way.
I'll post the answer sometime later to give folks a chance to try it out themselves. So to restate the problem, it
is the same as the angle between any legs on a tripod, if the tripod and a vertical rod form a tetrahedron.
Remember all four sides of a tetrahedron are equilateral triangles.
If you graph the four points given, one could assume it might be a parabola opening downward.
If so, then y = ax² + bx + c.
I worked it out and in fact it can be a parabola. So start substituting the points into x and y in y = ax² + bx + c.
Then you have four linear equations with variables a, b, and c.
Play around with those and you get the answer. y=-7x² + 43x - 41 Have fun working it out. If you need more help, just ask!
I get the same result as nvidura. There are five views: top view (easy), south, west, north, and east views (harder).
So to calculate the south view vertical number of blocks:
You combine the bottom row with the top row making 101 blocks. Then you combine the 2nd row with 2nd row from the top, this also is 101 blocks (99 + 2). So I drew a small one that started out with three, but it was odd, and it wasn't analogous to 100 on the bottom. Then I redrew four on bottom and realized the number of pairs of 101 would be 50. So that's how it goes.
To compute the top surface area:
If you walk up the pyramid, each step is half a block forward from the next; they overlap. But you don't need to worry about
that if you just look at the whole pyramid from an airplane, and just compute the area of the overall square.
Units:
and you can use 0.63 meters and 0.97 meters right off the bat to make things a little easier.
Welcome to the forum. I've only been here a few days, myself!
Does anyone have a name for
a number system where the
digits can be values larger
than the base? Here is an
example using base-2 places
but filling them with digits
up to 9. Each four digit
number shown below has a
value of 68 in base-10.
8's 4's 2's 1's place
7 3 0 0
6 3 4 0
4 5 7 2
1 9 9 6
8 1 0 0
1 9 8 8
I would be interested in knowing how to solve this directly, however, without iterating the possibilities and choosing the
easy ones: 3 black or 3 red
Or another example would be to convert one foot into 12 inches.
(1 foot/1) multiplied by (12 inches/foot)
The foot in the numerator cancels with the foot in the denominator, so the units of the answer is inches.
B = black, R= red
BBB .1176470588 Find this one first: (26/52) * (25/51) * (24/50)
BBR
RRB
RRR .1176470588
Then All four combinations must be 100% so double .1176470588, subtract it from 1, and cut it in half!