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CG#106: The ratio(k:1) is = 2:9.
Sp#609: 2sₙ -n(2a+(n-1)d) =0
The value of p = 1/3.
The other two vertices are = (1, 2) and (1, 2) respectively.
The value of k = ±2√(6).
Is it for beginners? and I'm not familiar with coding.
Ok, I want to learn linear algebra as a beginner so, where should I start learning?
#678: the value of p = ±2√(2).
CG#104 the center of the circle (h, k) = (3, -2)
The radius of the circle = 5 units
Equation of the circle
(x-3)^2 + ( y+2)^2 = 25.
A#87: the values of x = ( 3+√(3) )/2 , (3-√(3) )/2
Yeah
But I'm a 12th class student. How would I start learning linear algebra at a time?
(a ) for equal roots m = 6.
(b) for distinct roots m > 6.
(c) for imaginary roots m < 6.
CG#103: the area of quadrilateral is = 28 sq units.
A#86: the values of x = 2/√(3) , 2/√(3).
Hello pi³ .
I think he asked about how trigonometric angle identities got derived and where did it came ?
#676 : The two consecutive numbers are 13 and 14 respectively.
CG #102 the fourth vertex(D) = (7, 4)
The sides of an rectangle are
Length = 60metres
Breadth = 30 metres
Length of the diagonal = 90 metres.
Given:∆ABC with midpoints of sides through A being (2,-1) and (0,1)
A = (1,-4)
let the midpoints are E & F, where
E = (2, -1)
F = (0 ,1)
Let B = (x₂ , y₂)
Let C = (x₃, y₃)
Let midpoint of BC will be = G
According to the given conditions:
Midpoint of AB = E
Using midpoint formula (m) = ( (x₁+x₂)/2 , (y₁+y₂)/2 ) , we get
(2,-1) = ( (1+x₂)/2 , (-4+y₂)/2 )
Compairing corresponding Coefficients , we get
(1+x₂)/2 = 2 and (-4+y₂)/2 =-1
x₂+1=4 and y₂-4 =-2
x₂ = 3 and y₂ = 2
∴ B = (3,2) = (x₂,y₂)
similarly midpoint of AC = F
( (1+x₃)/2 , (-4+y₃) ) = ( 0,1)
( 1+x₃)/2 = 0 and (-4+y₃)/2 = 1
x₃ =-1 and y₃ = 6
∴ c = ( -1,6) = (x₃,y₃)
now, midpoint of BC = G
( (x₃+x₂)/2 , (y₂+y₃)/2 ) = ( (-1+3)/2 , (6+2)/2 )
(1,4) =G
∴ the midpoint of BC(g) = (1,4)
A#84 the roots of x = ( 3+√(13) )/(2) , ( 3-√(13 ) )/(2)
CG#100 : Let the points of the line segment will be AB, where
A = (5, -1)
B = ( 2 , y)
Let the point divides line segment will be C.
According to given conditions:
Point c divides line segment AB in the ratio 1:2
Coordinates of c (x, y) = (4,2)
Using section formula =
((m₁x₂+m₂x₁)/(m₁+m₂) , (m₁y₂+m₂y₁)/(m₁+m₂))
where, x=4, y=2 , x₁ = 5 , x₂ = 2 , y₁= -1, y₂ =y , m₁= 1 , m₂ =2
(4,2) = ( ( 2 +10) / (1+2) , (y-2)/(1+2) )
(4,2) = ( 4, ( y-2)/3)
comparing corresponding y coordinates ,we get
2 = ( y-2) /3
6 = y-2
y= 8
∴ the value of y = 8.
The values of x = (- √3)/2 , (- √3)/2
The length of the median through A = √65 units.