Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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#276 Re: Dark Discussions at Cafe Infinity » album » 2006-10-06 01:11:39

he will go back to pakistan and realease his first album. inshallah
he just sent me his songs taht he had..with him.

#277 Re: Dark Discussions at Cafe Infinity » album » 2006-10-06 01:09:51

ok well he just started.....bilal
can you put attachments here? tehn i can post it
if u wat to hear it i can send u ? what you say

#278 Dark Discussions at Cafe Infinity » album » 2006-10-05 12:38:14

unique
Replies: 31

hey all you know my cousin he is making an album.
he has done 5 songs already . cool or what. and i encourged him. he said wht you think is my voice great. i said offcourse. and no i didnt lie .
so you wnat to hear his song?
its in urdu....
if anyone hear understand urdu
tell and i will put it on try to put it on......
i don tknow if i can but i'll try

#279 Re: Help Me ! » convert » 2006-10-05 07:28:10

but i still dont get it

#280 Re: Help Me ! » convert » 2006-10-05 06:36:10

r = sqrt34.0301
small angle = -0.6871 right?
now we haev to measure countercloakwise and cloakwise from the positive x axis to get the polar angle

#281 Re: Help Me ! » convert » 2006-10-05 06:15:48

yes with polar coordinates..
ok how to solve that...
put it in teh calculator
tan^-1 (3.7/-4.51)
tan3.7 divide by tan-4.51
rigght?

#282 Re: Introductions » hello » 2006-10-05 06:04:31

here in Ny is different
from kindergraden to 4th grade its elementary
from 5th to 8th is mmiddle
and from 9th to 12th is hiighschool
after that you go to college

#283 Help Me ! » convert » 2006-10-05 03:11:28

unique
Replies: 9

convert
-4.51^i + 3.7^j to polar coordinates.

^ this is on top of the letters.

ok this is what i did...not sure if i am right or wrong

r^2 = 4.51^2 + 3.7^2 = 34.0301
r = sqrt34.0301
tan 0 = 4.51/3.7

and next i dont know
HELPdunno

#284 Re: Introductions » hello » 2006-10-05 02:24:20

thanks all for the welcome
and no not in college yet next year hopefully i will be.
liek i said i am finishing up highschool.

#286 Re: Introductions » hello » 2006-10-04 07:21:28

last year of highschool...meaning in 12th

#289 Re: Introductions » hello » 2006-10-04 04:05:02

http://www.avatarmaker.in/free-avatar/icons/217.bmp

click here ..i mean copy paste. i want to make this an avatar..but too much kb

#290 Re: Introductions » hello » 2006-10-04 04:03:29

Thanks for the welcome
umm sure ok..why not.

#291 Re: Introductions » hello » 2006-10-04 03:33:32

lover of math...well not that much of a lover. but still math is ok...sometimes i get  a headache when i am stuck on a problem which i don't get.
i guess its love.

love can sometimes get on ur nerves and sometimes it gives u ease am i right smile

#293 Re: Help Me ! » triangle » 2006-10-04 03:10:37

yeah my bad. you know the signs on the topic of page .which have * + - and etc. and draged the sqrt sign but i guess it didnt show up.
yes that is a sqrt sign.

#294 Re: Help Me ! » finding X » 2006-10-04 03:07:59

Just copy and paste on url....

#295 Help Me ! » finding X » 2006-10-04 03:06:59

unique
Replies: 2

tell me if u see this problem on the site?

http://img150.imageshack.us/img150/991/findingxkg9.jpg

#297 Re: Help Me ! » triangle » 2006-10-04 03:00:32

Thank You so very much.
i would of never guessed that.

#298 Help Me ! » triangle » 2006-10-04 01:58:58

unique
Replies: 7

draw the necessary reference triangle and evaluate

2?3 cos60°

? this is sqrt right? square root?

#299 Introductions » hello » 2006-10-04 01:56:04

unique
Replies: 33

hi i'm new here? how is everyone? give me the heads up of what's going around here?
mainly i need help in math. and ALOT of it.
this is my last year of highschool....so i want to study very hard. and work very hard..but i would need your help also. can you help?
ok tehn see you takecarewave

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