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#276 Re: Exercises » Algebra -Subject » 2013-03-07 09:37:05
Yes, that's what I want, 'a' on the left of the formula.
#277 Re: Exercises » Algebra -Subject » 2013-03-07 09:29:58
I want 'a' to be the subject of the formula, I already did my way of doing, which is wrong, and would like to know wy it's wrong. Thanks
#278 Exercises » Algebra -Subject » 2013-03-07 09:14:55
- Al-Allo
- Replies: 39
Hi
s = ut +½at^2
So I want you to tell me why my way of doing is wrong : (a must be the subject)
-ut s = ut +½at^2 -ut
/ ½t^2 s-ut=½a^t2 / ½t^2 (This is how I think I should have done it, because we want only the a, so you divide all in one shot)
s-ut/ ½t^2=a ===> a=s-ut/ ½t^2
I Know this is the wrong answer, but explain me why my way of doing is wrong, because I have no idea why ! Thanks
#279 Re: Exercises » Evaluate algebraic expression » 2013-03-07 03:49:31
Nah, there isn't any. The b was for other equations.. ^^ Thank you for your help, I love this forum.!
#280 Re: Exercises » Evaluate algebraic expression » 2013-03-06 10:47:38
Yes, even when it's hard to admit we were wrong. Curiously, are you people mathematicians or proffesors ? If If it's okay with you to answer ...
#281 Re: Exercises » Evaluate algebraic expression » 2013-03-06 10:43:34
You are asked to evaluate c^2 (amongst other things of course ... but let's just concentrate on that bit)
So evaluate -5 squared
I put in the bracket to explain why that becomes +25.
Try this on a calculator.
Enter 5, switch it to negative with the +/- button, and store it.
Then do memory recall and press the square button.
Bob
Yes, It's ok. 
I understand that but it's just I had that memory which didn't seem to agree with you (Like you were distabilizing my foundations, but it's for my good 
)
#282 Re: Exercises » Evaluate algebraic expression » 2013-03-06 10:36:18
Ok...That's weird, I thought that it needed to be specified by parentheses so we could include the minus signs. Oh well, thanks for your help. Neither the exercise or me got it ^^
#283 Re: Exercises » Evaluate algebraic expression » 2013-03-06 10:26:41
Ok, I got the same answer as you but may you explain me something ?
Why do you put-5 in to parantheses ?
it doesn't have any, -5^2 = -(5X5)=-25
How is this wrong ?
#284 Re: Exercises » Evaluate algebraic expression » 2013-03-06 09:55:09
I found this website http://www.myalgebra.com/algebra_solver.aspx
And It gets also -64 And not -54 ....Any suggestions ?
#285 Re: Exercises » Evaluate algebraic expression » 2013-03-06 09:53:35
What is your answer ?
#286 Re: Exercises » Evaluate algebraic expression » 2013-03-06 09:48:14
Mux, the supposed answer is -54...
#287 Exercises » Evaluate algebraic expression » 2013-03-06 09:20:55
- Al-Allo
- Replies: 18
Hi
-a+3*(a-c)+c^2-a*c^2
a=-2
b=4
c=-5
i keep getting -64, would you agree with me or disagree ?
thanks
#288 Re: Help Me ! » Analytic Geometry » 2013-03-01 08:13:40
Hi;
Do you mean twice as close to R(8,2) as S(-1,2)?
That drawing looks backwards. Shouldn't S be to the left of R?
It means it's closer to R then it is to S. (twice closer)
There was no drawing in the problem, I just did it myself and added the letter in alphabetical order.
If there is something you don't understand in my text, tell me and I'll try to reformulate it. (
#289 Help Me ! » Analytic Geometry » 2013-02-27 14:01:09
- Al-Allo
- Replies: 4
Hi, need help with this problem, I have no idea how to even start it.
a)Determining the coordinates of the point N, situated twice near the end R (8.2) as the end S (-1.2) of RS.
Here
http://img72.imageshack.us/img72/954/segment.jpg
#290 Dark Discussions at Cafe Infinity » What does it take ... » 2013-02-07 13:02:00
- Al-Allo
- Replies: 1
I was just curious, what does it take to be a mathematician? And is there anyone who is one here ? thanks
#291 Re: Exercises » Average » 2013-02-04 13:13:50
Here the whole exercise : I have 8 number , the average is 60 , and the average difference(not sure how to name this in english) is 4... I have no idea on how to do this ?
#292 Exercises » Average » 2013-02-04 13:03:47
- Al-Allo
- Replies: 4
Quick question, how can someone find the numbers composing an average ?
Ex : I have ---
x = 480
___ = 60
8
I want to find the 8 numbers composing the average ? How is that done ? thanks
#293 Re: Exercises » Proportion » 2013-02-02 07:28:41
If you multiply by 7 you are going to get:
x = 56 / 9 which is the same thing.
ok, I understood. Thanks
#294 Re: Exercises » Proportion » 2013-02-02 06:30:18
But I mean not canceling the 9 but multiplying it by 7, it's not a right thing to do ? Thanks
#295 Exercises » Proportion » 2013-02-02 05:16:57
- Al-Allo
- Replies: 5
I just have a little problem :
X 8
_= _
7 9
If I would want to solve for X, I would multiply by 7 for each side. Leaving x=56
___
9
But what I did is x=56
__
63
Could somebody explain me why it's wrong ?
Thanks
#296 Re: Help Me ! » Just to be sure.... (problem) » 2013-01-29 13:39:13
Aaron reads 3 times faster than Shad and Patrick reads 4 times faster than Aaron. If Patrick reads 4 pages in 1 hour, how many pages reads each of his two comrades?
Answer :
Pat= 12x so 4 pages
Aaron= 3X so 1 page
Shad=x so 1/3 page
The value of X is 1/3
Now, everything should be correct, (I don't know why I inversed the names, inattention, I guess.)
#297 Re: Help Me ! » Just to be sure.... (problem) » 2013-01-28 12:56:09
Omg, I just saw the error. I didn't write correctly the problem.. Aaron reads 3 times faster then shad and patrick reads 4 times faster then Aaron.
Sorry again, could you recheck with that new statement if you get the same equations ? thanks
#298 Re: Help Me ! » Just to be sure.... (problem) » 2013-01-28 12:13:21
hi Al-Allo
As long as you keep track of each person's formula it doesn't really matter what you call 'x' here.
eg. Patrick x
Aaron 3x
Shad 12xx = 4 => Aaron = 12 and Shad = 48
or Shad = x
Aaron = 1/4 x
Patrick = 1/3 of 1/4 x1/3 of 1/4 x = 4 => 1/4 x = 12 and x = 48
Same answers but maybe the fractions make it harder ??
I was taught to make x the thing you are trying to find but here you are asked for more than one thing so I don't think it should matter.
Bob
Ok, but I under the logic behind that one persone is slower than an other but your answers are wrong and This I what I got :
Aaron: 1 page Shad: 1/3 page (Yes I know, this isn't realist, but these are the answers.)
What gives, why are you going in the opposite direction than the problem is saying. (Dividing because they are slower ?)
#299 Re: Help Me ! » Just to be sure.... (problem) » 2013-01-28 12:08:43
Hi Al-Allo. Your equations are wrong. They should be as follows
Al-Allo wrote:Aaron reads 3 times faster than Patrick and Shad reads 4 times faster than Aaron. If Patrick reads 4 pages in 1 hour, how many pages reads each of his two comrades? I know how to resolve the problem, but I just wanna be sure I resolved it in the right way.
X: Number of pages Shad read
X/4: Number of pages Aaron read. (4 times slower than the numbers of pages Shad read.)
X/12: Number of pages Patrick read. (12 times slower than the numbers of pages Shad read.)
Now, I resolve : X/12=4 (pages read by Patrick)
How come ? I got the answer perfectly with them ...
#300 Re: Help Me ! » Just to be sure.... (problem) » 2013-01-28 12:01:37
Hi Al-Allo!
Try x for Patrick, 3x for Aaron 4(3x)=12x for Shad. (Patrick is the slowest reader, Aaron next and
Shad the fastest.) So if Patrick reads 4pages in 1hr, then ...Can you get it from there?
Sorry, I confused the names, thanks for the correction. But what I'm asking is X represent the number of pages read by Patrick, right ?
THanks