You are not logged in.
Hey guys,
Having finished matrices I've moved on to complex numbers. It's been going well but I got stuck on one question
Show that there is only one value of a for which
,And find this value.
I believe that
However, I get the argument of this to be:
Which is equal to:
But if I equate that to
I can only get:
Which, of course, has two solutions.
Am I missing something?
Hi again Bobbym, sorry it's been a while, thanks for the link, it's very nicely illustrated.
Ahhh thanks!:)
Hehehe .
Well the answer book agrees with you .
Well a new term means a new set of mechanics questions and this one has me completely stumped, because it's nothing like anything I've seen before:
Particles of mass 2 kg, 3 kg and p kg are placed at points whose coordinates are (1,3), (4,6) and (7,-8) respectively. Given that the centre of mass of these particles lies on the x-axis, find p.
I've done centres of mass of laminae, centres of mass of wire shapes, centre of mass of hanging objects and centre of mass of laminae and wire shapes with weights on various ends, but I don't understand, is this a wire shape? And if so, perhaps a little jog of my memory would help me here
Ah, okay, so let's say
And I think we have it, thank you so much
Well, we only need one other vector, so we may as well do BC
So we now do a dot product between one vector in the plane and 'n' and set it equal to zero. Do again for the second vector.
Now if I can choose any value for a then I may as well go with 1, which gets us:
Okay so let's choose:
Now, at this point the most sensible thing to do would seem to be to multiply n by 10, but I happen to know that the book's answer actually requires me to multiply by -10. Now, unless I'm very much mistaken, the values of n make no difference at all, but it'd be nice to get the book's value of n, just to tie it off nicely. So we have:
Which leaves me with something of a problem, because the correct answer should be 120
Wow what an explanation thank you so much.
So, firstly we begin by picking three points, presumably from
So we could say let
Which of course gives
Respectively, unless I'm very much mistaken. Now, if I have understood correctly so far we must now transform these points with T, which, I believe, gives:
But at this point I don't fully understand AB = AO - OB etc.
Of course, I'm perfectly happy to wait, especially for answers as instructive as yours. However, I'm surprised to here about the weather, it's very cloudy here on (presumably) the other side of Essex.
Ooooh thanks ever so much for all of your tribulations Bob. I suppose that either method would suit me fine, I'm just not entirely sure I'm clear on your method, I don't suppose you could provide an example, or further instruction to clarify? (I'm sorry to request further tribulations). Otherwise the book method is perfectly fine, but I don't really see how to move from the book's finding the vector equation to finding an equation in the form
Oh and yes I'd meant to say, the screen is much wider than normal, it may have been to do with my using the LaTeX text environment, which does not drop lines automatically. I tried to fix it, but it doesn't seem to have made much of a difference I'm afraid.
Oh, whoops, sorry, no I didn't I copied and pasted the matrix template for simplicity and forgot to change the entries! Sorry for the confusion, it should be the same as the last line of the preceding post, I'll just change it.
I don't know if that will help but that's the book's angle, I can't find any further clarification in the book I'm afraid. I'd be happy to have a go at getting my own figures, except I'm not entirely sure I understand what to do.
Hmmmm it's a tricky one, I copied out the question exactly as it stands in the book, but if it helps I can copy out the book's example of a problem which is similar to these questions, but not quite the same, perhaps that would shed some light:
Ahhhhhhh I see, thanks!!!
Ooooh thanks very much for all of your hard work Bob, I think I've genuinely got it now, the only thing I don't think I quite follow, ironically, is the first step which, I assume, is the easier step, where did you get those vectors from?
Ooooh that is, indeed, very nice, I must say, it is very clear and well-done. It is good to see it explained this way - of course I've come across it many times - but it was originally explained to me arguably less well.
Ah, thank you. I haven't covered dot product, but I have looked at it before and I'm fairly sure that I know what it does and how to use it.
Hmmm such an explanation may indeed be helpful - the reason why I've moved so far in so short a time is that my textbook assumes knowledge of chapters I haven't yet covered. Also, I'm sorry to hear that you're out of bandwidth but I would be happy to have a look, I don't quite know where you mean by 'teaching resources' however?
That's very nice . I think I get what the equation means now, thanks!!!
. I am, however, stumped by a new, but similar form of question, I have a worked example, but as I've alluded to this is the last chapter of a unit which is way ahead of anything I've done and I don't really understand some of the ideas, perhaps someone could explain what to do and why?
The transformation
Is represented by the matrix T, where
.The plane
is transformed by T to the plane
.The plane
Has Cartesian equation
Find a Cartesian equation of
.Hi Bobbym, I agree, instructive and well laid out, good quality as well - sometimes they can be difficult to read - thanks
Certainly I shall, if only out of interest, I was especially interested in whether my layout was appropriate. Thanks, once again
Hmmm thanks Bobby, so could I then say:
Oh hi Bob Bundy, I didn't see your reply there, you replied just as I was, thanks a lot
Hi,
I'm not sure how to do a question which I have on vector equations - vectors have never been my strong point .
The points A and B have position vectors
And
Respectively. The points A and B are transformed by the linear transformation T to the points A' and B' respectively.
The transformation T is represented by the matrix T, where
.a) Find the position vectors of A' and B'.
I was able to work out that:
.And
.b) Hence find a vector equation of the line A'B'.
Here is where I'm completely stuck . I haven't done any of the vector units which precede this one.
Hi Bob, thanks again. Well the A-level mathematics examinations have changed a little in recent times, but the Edexcel board currently offers these units:
Core mathematics: C1, C2, C3 & C4
Further Pure mathematics: FP1, FP2 & FP3
Mechanics: M1, M2, M3, M4 & M5
Statistics: S1, S2, S3 & S4
Decision mathematics: D1 & D2
I'm not sure as to the number of possible combinations, but my school offers single maths: C1, C2, C3 & C4, along with either M1 & M2, or S1 & S2 (or, rarely, M1 & S1) depending upon the teacher and other subjects (i.e. those taking subjects such as physics would do mechanics and those taking subjects such as economics would do statistics, but this is not exact) and further maths: C1, C2, C3, C4, FP1, FP2, FP3, M1, M2, M3, S1 & S2 (and possibly S3, I'm not really sure). Anyway, last year I opted for single maths, however, matrices aren't covered until FP1 and FP3, but I wished to study them for their interest and use in mathematics and physics, as well as in order to understand another book, in which some key concepts are explained through matrices. So, I asked my teacher for help and he gave me a quick overview and the FP1 & FP3 textbooks, which I have since been working through - I'm hoping to begin linear transformations in 3-dimensions today, so no doubt I'll have plenty more questions for you . But yes, the eventual answer to your question is that I personally won't be taking an exam at the end (although one could) it is merely an academic curiosity.