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I'm for "passerby"!!!
Can I write A as a relation of K, L, M, N, Q, P, S, without B, C, D or not?
Yes (When it's possible in terms of the parameters). This is obvios, because B,C,D are unknowns.
But sometimes one of the unknowns may have more of one values, and then the other unknowns will be expressed in terms of it.
For example, if you have the equation:
x=y, then x can be every number, but y MUST BE EQUAL to x (not any)
And in this system you can't have division by 0.
I'm talking about something like:
0=0+const;
0-const=10;
Get it now?
Sorry, I'll dissapoint you.
I've taught that becuse this numbers are interesting, they should have been investigated.
And I've founded them in the OEIS:
http://www.research.att.com/~njas/sequences/A016106
We can call them "Passerby" numbers...
krassi_holmz wrote:I'm in eighth.
So you are ... 14?
No I'm 16.
Ricky wrote:I can't even begin to see how constructing such a proof would be possible.
We should give these numbers a name, then we can make a conjecture, then in 100 years someone can get the Fields Medal by proving our conjecture.
That's good. But it will be better if we find some connection with the Riemann's hypothesis.
IT CAN BE SOLVED!
in sertain cases it may not have a solution, but the absence of solution is a solution...
if you understand...
Up to 10^6 I have founded one more (with mathematica):
798644:637832238736
I'll try bigger.
I've written a nice program in Mathematica, but it's incredibly... slow .
I'll try with C program.
I'm in eighth.
Such proofs involve fermat's little theorem and euler's theorem (for modulus).
And all the proves I have seen are constructive.
If we find a pattern for this numbers it will be easier.
There are infinite number of numbers that can be made witn 4 4s.
Prove this!
And it's easy to handle all the negatihe numbers to -100, if you use the fact:
-(a)=-a!!!
Now devz, do you understand why people search only positive solutions?
hA
The existence of a solution depends on the known values.
If P=S-Q,M=P+Q-N,L=P-N, there for every D C=D+L and B=N-D and A=M-C, so in this case we haxe infinitly many solutions.
There are other cases, in which we won't have solutions.
It can be solved fully, but the solution will be very long because you have 7 parameters.
Devante (sorry but I can't put ' over yours e) is right.
The best way to understand and learn something is to...
ASK!
So I've helped!
VVV
o_O
LLLJ
I knew it!
I'm from Bulgaria.
my jelly beans!!!
For this you will need a definition of module over the reals.
For example:
A recycle bin for nothing is a good deal!
I have always thinking that there's something wrong in the free products, but what wrong there can be in a becycle bin!
Interesting...
i think it is very necessary for many members who are not familiar with complicated English terms in Maths
I agree. And I'm not familiar with all of them too. We can't know everything. That's why there're google, wikipedia and wolfram's mathworld and many other !
I have heard of it once-i have played a game made with it...
A quest, I think.
But I can't remember its name...
And... espeon, good luck.
I can be a beta-tester
Just add some saturation to everything. May not do a lot of good, but still fun to play around with.
Good
But...
Why not?
I don't know...
There is a telling in our country -
Free lunch doesn't exist. (in Bulgarian it sounds better )
When programming in Java, or really any high level language, it's not so much important to understand how things work. That only starts to make sense when you get down to the assembly level.
I don't agree. If you have some very big messy program, for example, and if it uses many modulus in it, and if it doesn't do what it's supposed to do, then you should know what's happening around the %, because the mistake may be there. If you don't know, you might pass the error, without noticyng it and this can cost you a big headache.
It's too late now. I'll try tommorow.