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i got
2x + 4ln(2 + (4x +2y - 1)^1/2) - 2(4x +2y - 1)^1/2 + c = 0
Can someone confirm this?
And also show me a method to doing it. I did it a very complicated way , thats why i believe it is wrong
dy/dx = (4x + 2y - 1)^1/2
Can someone please solve this?
question 2)
dy/dt= f(t,x) = (tx)^1/2 with the conidition that x(0) = 1
i)solve the given initial problem exactly for t>0, x>0.
ii) Set up picard's iteration scheme for the solution of that equation and find the first three picards approximations
X0(t), X1(t), X2(t)
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