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#1 Re: Help Me ! » Calculus: some problem with limits... » 2007-06-02 12:56:09

Thanks mathsyperson smile ...just btw what are power laws? Maybe I know but perhaps the translation differs in my language from english so I dont know what it should be exactly.

Can I do it also this way(?):

according to the rule that [x^a * x^r = x^{a+r}] so that our example will be like [2^x * 2^3]/[2^x * 2^-1] and that this way the [2^x] will cancel each other out and we will get [2^3]/[2^-1] which equals eventually [16] ...

#2 Help Me ! » Calculus: some problem with limits... » 2007-06-02 01:25:40

nox_populi
Replies: 6

Hi,
I have this little problem. It has been bugging me a while. I still at high school so its nothing advanced. I tried l'Hopital rule, log, differentiation, etc. and nothing of it worked. Here it is:

Limit[(2^{x + 3} + 4)/(2^{x - 1} + 1), x -> Infinity]

The problem is that it has this wierd exponent. Anyone has any ideas? smile
Cheers,
Dan

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