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#1 Re: Introductions » Hi Maths Guru I need assistance to the differential below » 2010-08-24 03:17:06

Akpolome

solution of Y' =sinX

Bob


integrate both side of the equation the result will be


Y=-cosX + K

where K is constant of integration

#2 Introductions » Hi Maths Guru I need assistance to the differential below » 2010-08-24 01:51:39

Akpolome
Replies: 3

solve the differential equation y ' = (1/2) sin(2x)

#3 Re: Help Me ! » Naturual Logarithms » 2010-08-24 01:50:13

Akpolome

ò y ' dx = ò (1/2) sin(2x) dx

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