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## #1 Help Me ! » taylor series expansion for a square root... » 2010-05-05 21:16:10

sousou
Replies: 1

Hello,

I need to find the taylor series expansion for a square root...

A = sqrt [C^2 + L^2 - 2*C*L cos (theta + phi)]

Where:    C = sqrt[L^2 + (X + Y)^2]
phi = atan[(X+Y)/L]

A = sqrt [L^2 + (X + Y)^2 + L^2 - 2*sqrt(L^2 + (X + Y)^2)*L cos (theta + phi)]

Thanks for your help...

## #2 Re: Help Me ! » I need your help to expand the following: » 2010-04-30 03:27:52

Thanks ....I wonder how you could write the symbols of maths? is it the same sythax as lateX?

## #3 Re: Help Me ! » I need your help to expand the following: » 2010-04-30 02:26:12

bobbym wrote:

Hi sousou;

There isn't anything to show just the 2 substitutions and a small cleanup. I didn't do very much here.

Make your substitutions:

Pull out a factor of 2L inside the radical:

Thanks lobby,

but all what you did is substitution

I am looking for further simplification, I wanna get rid of the square root :

A = sqrt [C^2 + L^2 - 2*C*L cos (theta + phi)] = A = [C^2 + L^2 - 2*C*L cos (theta + phi)]^1/2///

and then expand the polynomial...

## #4 Re: Help Me ! » I need your help to expand the following: » 2010-04-30 01:05:40

bobbym wrote:

Hi sousou;

This is the best I can do after 3 tries :

A little simpler:

Thanks Bobby,

could you please show the detailed workout o fthe three tries ...Thanks...

## #5 Help Me ! » I need your help to expand the following: » 2010-04-29 23:34:56

sousou
Replies: 8

Hello,

I need your help to expand the following:

A = sqrt [C^2 + L^2 - 2*C*L cos (theta + phi)]

Where:    C = sqrt[L^2 + (X + Y)^2]
phi = atan[(X+Y)/L]

L is a constant.

Thanks for your help and time.

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