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#1 Help Me ! » did i do it right? » 2006-11-25 08:23:30

girlnamedfreak
Replies: 1

when trying to get x alone is b^2-c^2+2cx = a^2 --> a^2-b^2+c^2/2c = x ?


is (a^2-b^2+c^2/2c)^2 = -2a^2b^2+2a^2c^2-2b^2c^2+a^4+b^4+c^4 ?

#3 Help Me ! » Simplifying » 2006-11-24 10:16:04

girlnamedfreak
Replies: 4

can -b^2+c^2-2cx+x^2+a^2 be simplfied?

#4 Re: Help Me ! » Angles » 2006-11-19 06:59:45

Thanks guys! Youre very helpful and get it now. The answers I got were correct because all the angles added up equal 180.

#5 Help Me ! » Angles » 2006-11-19 03:35:46

girlnamedfreak
Replies: 5

how do you find the other two angles of a right triangle when you are given all the side lengths?

#6 Re: Help Me ! » two trig questions » 2006-11-12 14:56:24

the exact question on my homework is: Estimate sinA and tanB in the given triangle ABC

then theres a picture of a right triangle thats labeled with A, B, and C and the 90 degree angle is shown

thats all it says and we never went over anything like this in class so I have no clue what to do

#7 Help Me ! » two trig questions » 2006-11-12 11:38:31

girlnamedfreak
Replies: 4

how can i estimate the sine or tangent in a given triangle




and why is the sine of the 30 degrees equal to .5?






thanks

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