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Ok. Thanks, I didn't know that.
100,000/q^3=0
Solve q. Thanks.
All your answers are correct but may I ask a few questions. I am very weak in maths.
A.
1. y' = 4x³ + 2e^x
I understand that 4x^3 is from 4 * x ^4-1 but what about 2e^x? How did you get 2e^x? In the future whenever I see e what do I do with it?
B.
1. How do you get d(x)/dx = 1 and d(ex)/dx = ex? I understood how 5 differentiates to 0 because 5 = 5x^0.
I am vague especially when it comes to e and ln. How am I to derive them?
C.
2. How is it that ln and the e cancel each other out?
I totally do not get question 3 and 4.
Here is how I did my question 3 and 4 which I am stucked at the moment.
3. y=10 / (1-5e^0.2x)
y=10 * (1-5e^0.2x)^-1
u = 10 * (1-5e^0.2x)
y = u^-1
du/dx = -5e^0.2x dy/dx = -1u^-2
dy/dx = dy/du * du/dx
= ( -1u^-2) (-5e^0.2x)
= -1 (10) (1-5e^0.2x)^-2 * ( -5e^0.2x)
After this step, I am lost as to how to continue on.
4.
y = 100-5e^-0.3x
u= 100-5e^-0.3x
y= u^-0.3
du/dx = -5e^-0.3x dy/dx = -0.3u^-1.3
dx/dy = dy/du * du/dx
=-0.3u^-1.3 * -5e^-0.3x
= -0.3 ( 100 - 5e^-0.3x)^-1.3 * -5e^-0.3x
And if I to continue on my answer will be completely different from yours.
Please advise. Thank you
Please help me with the following questions. Thank you very much.
A. Find the derivative for each of the following function.
1. y=x^4 + 2e^x
2. y=10lnx
3. y= (1.08)^x + 10
B. Use the product rule or the quotient rule to find the derivative of each of the following functions.
1. y=5 + xe^x
2. y=x^2e^x + xlnx
3. y=5e^x lnx
4. y=x^5/6 e^x
C. Find the derivative of each of the following functions using chain or function of a function' rule.
1. y= (4+lnx^2)^-1
2. y=10x + e^lnx
3. y=10 / (1-5e^0.2x)
4. y=100 - 5e^-0.3x
And please show me the workings too so that I can revise better. Thank you.
Thank you guys. Much appreciated.
5. Do you mean Q=K^(0,8)*L^(0,4) or Q=K^(0,8(L)^(0,4)) or something else?
The question in my book states Q=K^0.8L^0.4 when Q=2000 state the change that will take place in K when L is increased by 1%.
The answer given is if L increases 1%, then K decreases 0.5% but without any workings. I don't understand at all.
Btw thanks for your earlier answers.
1. 25=10x
2. 40+10e^x=200
3. x^0.3=12
4. e^lnx=8
AND
5. Using the production function Q=K^0.8L^0.4 when Q=2000, state the change that will take place in K when L is increased by 1%.
Thanks guys/gals and most important me please guide me with the answer as well as the workings. Thank you.
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