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Hi I need help finding a point on the cuve y=x^3+2x+2
whose tangent line is parallel to the line 3x-y=2 ????
And is there more than one such point?
Please please, help me how to do it, and explain.
Thank you )
Wonderfull, Can you please explain how you got the answer.. please
What is the derivative of e^-x
I know that the derivative of e^x is just e^x
How to differentiate this equation:
2x-x²e^-x
Thank you all for your help.
First I found the derivative of the outside function Sin and Square root, by moving 1/2 to the front.. Then I did the derivatuve if the inside function 3x³+3x.
Isnt that how Chain rule should work?
f(x)= sin √ 3x³+3x (Note its a square root of full function 3x³+3x )
Thats how I solved it.
f'(x)= Cos(3x³+3x)^½
= Cos ½(3x³+3x)^-½ × (9x²+3)
= 9x²+3Cos½ (3x^³+3x)^-½
Did I derive it right??? because solution at the back show that the answer is:
9x^2+3/2 root (3x^2+3x) cos Root (3x^3+3x)
Please Tell me if mines is right or wrong?
I kind of understood it.)) Thankx
One more question, when I do derivatives do I always have to put d/dx, dx/dy or I can simply put f '(x) in front and do the derivative without d/dx or dy/dx
hmm, what about
Sinx Secx
Sin x will be u u'v+uv'
Sec x will be v Cos x (Sec x) + Sin x (Sec x Tanx)
After that I dont know how yo simplified to Tan x^2 +1 and got sec ^2 x
Hi,
I need to find a Derivative of a drigonometric function.
1. F(x)= sin x sec x
That how i did it: f'(x)= Cos x Sec x Sec x Tan x Sin
But the answer shows f'(x)= Sec² x
Question: Is mine wrong or is the answer wrong? Please explain how to do it.
Thank you)
Also, how to solve this type of derivative
1/Sec x Tan X
Can anybody solve it for me, please and explain.
Thank you
Thanks guys , appreciate your help....
Thanks x 2
If possible do you mind showing how you also got #3???
Thanks ^2
hmm, what about 2nd question, even though it is almost the same as the First one but you get √3/2√x ... can you please show me step by step how you got it. Please
Thanks)
Hi bobbym:
But after (2x)^(1/2) = (1/2)(2x)^(-1/2) all those steps... I get 1x^1/2, How do you put it in the form of 1/√2x ??
As I understand. for the # 1
You did. 2x^½
2(½)x^-½
1x^-½
----After that I am not sure what you did?
oo thank you
But, can you please explain how you got that?
Thankx)
What are Derivatives for
1. Square Root 2x ????
2. Square Root 3x ????
3. 2/Square root x ????
Please help me state state a derivative for each of them
Also help me to solve the following Equation using Product/Quotient Rule.
f(x)= 2x^2-3x-1/x^3
Thank you once again.
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