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#1 Re: Help Me ! » Remainder in Fraction » 2017-03-09 15:01:18

Bob Bundy keep it simple. 

What did you multiple 9 by to get 60; break it down ?

#2 Re: Help Me ! » Remainder in Fraction » 2017-03-07 09:44:49

@Bob Bundy - You're confusing me by quoting other fraction posts.

What I want to know is, how can you find the numerator for the second fraction when nothing will multiple into

to get the denominator which is
?

#3 Re: Help Me ! » Remainder in Fraction » 2017-03-07 03:13:05

bob bundy wrote:

There is always a value that will change number x into number y (unless x=0).  Form the multiplier thus

So for 12 ---> 60  use 60/12 = 5 and for 9 ---> 60 use 60/9  = 20/3

Bob

I know I may be missing something.  You strictly took the

and instead of finding a number which multiples into it, to make
you did
?

#4 Re: Help Me ! » Remainder in Fraction » 2017-03-06 14:48:57

bob bundy wrote:

Ok, I'll make up a similar example and do it completely:

There is nothing which

or
will multiple by to get
? How do you get the numerator for the second fraction ? What do you do if you can multiple anything into the number to get the denominator ?

#5 Re: Help Me ! » Remainder in Fraction » 2017-03-06 04:53:27

method 1.  Start by adding the fractions using the usual rules.  This leads to something/96.  Simplify to something/24.

To change /24 into /60 you need to multiply top and bottom by 2.5  This gives a fraction with a denominator of 60.  Split off 5/60 and whatever numerator is left is the required answer.

Without giving the answer, I didn't understand your explanation ?

#6 Re: Help Me ! » Remainder in Fraction » 2017-03-05 07:17:52

Without giving the answer.  Look at this fraction

There is nothing that will multiple into

to get
?

#7 Re: Help Me ! » Remainder in Fraction » 2017-03-04 13:12:33

Therefore the answer is the following;

 
Good ?
smile

#8 Re: Help Me ! » Remainder in Fraction » 2017-03-02 12:13:12

What I don't understand is, there is no number that will multiple into

to get
besides
.  You have to use the same number you multiplied the denominator by with the numerator which is 5 that is what I was informed ?

Unless this is correct ?

#9 Re: Help Me ! » Remainder in Fraction » 2017-03-01 05:52:20

Correct me if this is wrong, this is what I read;

You can find the lowest common denominator by finding what 3 and 7 will multiple by evenly ?


That leaves a remainder, since nothing will multiple by

to get
.  Therefore one can't use
as the lowest common denominator, one must use
, correct ?

#10 Re: Help Me ! » Remainder in Fraction » 2017-02-28 16:13:33

You didn't tell me if my question on how to solve fractions when the denominator is different as in post #5 was correct ?

#11 Re: Help Me ! » Remainder in Fraction » 2017-02-28 01:53:23

In other words, when you have found the lowest common denominator and you know the number which you used to find the lowest common denominator. You then simply multiple the numerator (and denominator) of the number you used to find the lowest common denominator for the first fraction, correct ?

Then you use the result of the answer for the numerator as in the case for the three over thirty-five for the first fraction ?

#12 Re: Help Me ! » Remainder in Fraction » 2017-02-27 11:44:43

For the first fraction you have to multiple the numerator and the dominator by what you got to get 35.  Before I go any further into adding the fraction by making the lowest common denominator; here is the fixed fraction.


I assume I put the result of 3x7=21 for the first fraction ?

#13 Help Me ! » Remainder in Fraction » 2017-02-26 14:09:00

SuperLynx
Replies: 29

I'm curious since their is a remainder for adding these fractions ? Considering 3x12 = 36 for the numerator, rather then 35.

#14 Help Me ! » Cross Product understanding for newbie » 2016-10-03 03:01:28

SuperLynx
Replies: 1

Anyone here understand how a cross product works in relation to 3D ? I understand the core of what it does which is the third vector from the other two vectors but relating that to 3D space has been the issue.  Here is my theory of how it works, suppose you have a sphere and a plane in a scene, the sphere is traveling on the Y axis, that is one vector, the plane is static, which is another vector, the X axis.  When the sphere touches or hits the plane, the cross product would be the axis or vector to the right of the sphere and plane, suppose that is behind the sphere, when the sphere touches the plane, it will create a red mark which is the cross product of the sphere and the plane ?

Is my theory somewhat correct, or completely wrong ?

#15 Re: Help Me ! » Latex Help » 2016-07-10 02:37:50

Maybe this will help; see how the B for Beta is between the two rows I want it only in the upper row ?

p\left ( R \right )= 1-2\mathbb\epsilon \left \begin{pmatrix}
e-e\\\
e-1
\end{pmatrix}\beta

#16 Re: Help Me ! » Latex Help » 2016-07-09 14:27:28

thickhead wrote:

But I want to know why \mathbb is used?

I removed that part.  How can I get the beta symbol near the top row ?

#17 Re: Help Me ! » Latex Help » 2016-07-08 23:57:43

Yes, how did you do that, in the editor I linked too ?

#18 Re: Help Me ! » Latex Help » 2016-07-08 23:31:37

I want to create a small beta symbol at the top near the e-e, currently the Beta symbol is between, as mentioned, the two rows when inserted.

p\left ( R \right )= 1-2\mathbb\epsilon \left \begin{pmatrix}
e-e\\\
e-1

\end{pmatrix}\beta

#19 Help Me ! » Latex Help » 2016-07-08 15:32:56

SuperLynx
Replies: 9

Hi, I'm using this editor and I want to create the B small in the top row, current it's between the rows ?

p\left ( R \right )= 1-2\mathbb\epsilon \left \begin{pmatrix}
e-e\\\
e-1

\end{pmatrix}\mathbb\beta

#20 Re: Help Me ! » complex numbers » 2016-05-17 16:54:49

thickhead wrote:

We represent a complex number in XY plane. real part is along  or parallel to X axis and imaginary part is along or parallel to Y axis.e.g. Let us say you represent a land map as complex plane.say village B is x+jy distance from village A. x is distance along east ( displacement to west considered -ve)and y along north. You can cover the distance by 3 sessions of drive say. a+jb, c+jd, e+jf Then
x+jy=a+jb+c+jd+e+jf
        =(a+c+e)+j(b+d+f)
Real and imaginary parts must separately balance on both sides.
i.e. x=a+c+e  and y=b+d+f  If both are not satisfied you will not reach B.
If there is a village C such that AC=j(x+jy) ,C will be located such that

at the same distance.

You're going to have to give a simpler example, until I can wrap my head around it ? smile

#21 Re: Help Me ! » complex numbers » 2016-05-17 01:51:08

thickhead wrote:

34j is an imaginary number whose magnitude is 34. In an Argand diagram it is represented by a vertical line segment of magnitude 34. You can say j is a unit vector in y direction.

Why is it only in the Y direction, or it doesn't matter ?

#22 Re: Help Me ! » complex numbers » 2016-05-16 16:34:31

thickhead wrote:

Hi Superlinx,
usually mathematicians use i and engineers use j . Both mean the same thing. 4+5i is represented by distance 4 along x axis and distance 5 parallel to y axis.You can say an "i" attached with a number rotates the vector by 90^0.
interestingly  4 i^2 means vector 4 along x axis is rotated by 180^0 and becomes -4 . this tallies with the concept that i^2=-1.

What if I write a formula 34j, what is that, literally, besides the number 34 ?

#23 Re: Help Me ! » complex numbers » 2016-05-15 16:30:19

When do you use complex numbers ?

#24 Help Me ! » complex numbers » 2016-05-15 15:47:51

SuperLynx
Replies: 12

I'm trying to understand complex numbers for example 3j or 4i.  I've been reading some sites on complex numbers but still can't wrap my ahead around it's purpose if I have the following formula;

45j + 4 = 49 and so what is the point of j ?

#25 Re: Help Me ! » Base16 to HEX » 2015-11-15 18:10:21

bobbym wrote:

Each base requires an equal number of symbols to represent any number. Base 2 has 2 numbers 0 and 1. Base 3 has 3 numbers, 0, 1, 2. Base 10 the one that we use requires 10 and base 16 requires 16.

I don't understand ?

Why must there be letters ?

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