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Ricky wrote:

I completely understand what you are saying. But each element of A is two elements.

You have a function: f(x, y). You can't just plug one number into that. You have to plug two in. Because of these, the elements in set A become (n, m), where n and m are from 0-255.

OHHHHHHHH..hurreehhhh I got it.......................

shooo do u know Ricky how i was thinking.....?I was thinking that if the two numbers comes in the same as (x,y) form there will only be 256 numbers.....sheyy.......It was a small mistake right?

GOT it now.....understud the pigeon hole principle also....

WAS A NICE HELP REALLY>>>RICKY>>>THANK U VERY MUCH>>>>

But again on emore thinggg..U told that THERE IS NO SUCH FUNCTION...SO CAN SUCH A FUNCTION COME???I FELT LIKE U HAVING SOME DOUBT IN THAT CASE>>WHAT WAS IT?

Any way let me know some personal thing about u???Are u a student??What do u do??

I completely understand what you are saying. But each element of A is two elements.

You have a function: f(x, y). You can't just plug one number into that. You have to plug two in. Because of these, the elements in set A become (n, m), where n and m are from 0-255.

Where is Ricky???RICKY please help me....

what has happened to every onee???no on ehere?

Ricky wrote:

You are correct, f(x, y) is different than f(x) and f(y), but so is the explanation.

Remember, I never named the sets I was talking about in my explanation. This is because it applies to every set and every function between those sets.

Let A = {(x, y) | x ∈ [0,255], y ∈ [0,255]}, the domain. A is a set of ordered points, just like those in your function. How many elements are in A? 255*255.

Let B = {z | z ∈ [0, 256]}, the range.

.

This one i understood.But not hat i asked.let A be the set above and B too.The connection between the domain and the range is through the function aplied on the domain set know?

This functions like onto etc etc(i have studied it earlier dnt remember) comes when the FUNCTION is applied to each indiviual member on domain.Here what is being done is the function is applied to two members of the set A.

so how can it be?? Dnt kow if i am wrong..

Hey Ricky,ur way of explanation is very nice.....realy...u can be a good teacher .....

Let me ask some thing...here my funtion is f(x,y) and not individually f(x) and f(y) know?.i dont know really..i am asking...if we are looking that way ,i feel like something problem in the explanaion..dnt know if it is really...

so i think all the explantion has to be changed because there will be change in the number of elements in the domain and range all.am i coorect?

Ricky wrote:

No soorejmg, that's not what I said. It will _NOT_ exist. There is _NO_ such function.

PH nice I was totally disapointed....but how can u proove there i sno such funcvtojn?

Ricky wrote:

C = A + B×256

Dnt u have any idea like in puzzles some tricks are there to find out number by special operations all....any idea like that in this case?

I can prove through the use of the pigeon hole principle, that it is not possible if the function must be onto (valid for every value of C). Once you prove something impossible, there are no such tricks.

please proove it

MathsIsFun wrote:

Well, we have had fun with this one!

I now want to see soorejmg's solution

HEy,,,u know something....i have been looking for some solution but i couldnt find one..So i asked u people....No one could...

BUt how com Ricky said such functiondnt exist or will come in future?!!!!!!!!How is he so sure??

SOmetimes if it comes?!!!

Is there any method by doing some combination of different AND OR operations or any such operations on the two numbers and later then doing some other steps to obtain the two numbers from the single number??

TRY it its very interseting..............

**soorejmg**- Replies: 33

U have two numbers ..u must find a method to find a third number from this two numbers such that afterwards only the 3rd number is provided u should get back the first two number..One more thing to easy the work...the two numbers is in limit 0 to 255 .CAN ANY ONE????? eek

Thje third number shuld be a integer and it should be less than or equal to 256

Hey It was nice....but how was it developed??????How was it used to find area,etc.....

**soorejmg**- Replies: 3

How did the use of of differentiation and integration all came into use????how was the differnt formulas of dy/dx and integrations formed..who formed it???whats use..all this i want to knoe....why did it came to use??

MathdIsFun .....are u getting any idea about it/????

HI..It was nice...But would u mind me putting one more constrain??

The NEW NUMBER FORMED C SHOULD NOT BE GREATER THAN 255.CAN U?

TRY IT.Best of LUCK...

**soorejmg**- Replies: 13

U have two numbers ..u must find a method to find a third number from this two numbers such that afterwards only the 3rd number is provided u should get back the first two number..One more thing to easy the work...the two numbers is in limit 0 to 255 .CAN ANY ONE?????

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