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#1 Re: Help Me ! » help please! » 2019-07-30 03:20:39
Hi Bob!
If you could post the one using geometry that would be great.
Thanks for the help!
#2 Help Me ! » help please! » 2019-07-29 12:11:43
- Vedanti
- Replies: 3
The solution to the following problem confused me a little:
Problem: Points P and Q are on sides CB and CD, respectively, of square ABCD such that CP=CQ=AB/4. Find tan(angle PAQ).
Solution: We have tan(angle PAQ) = (tan(angle QAB - angle PAB) = tan(angle QAB) - tan(angle PAB))/(1 + (tan(angle QAB))(tan(angle PAB)).
The solution continues from here but I don't understand the part where it says (tan(angle QAB - angle PAB) = tan(angle QAB) - tan(angle PAB))/(1 + (tan(angle QAB))(tan(angle PAB)). How do you get this equation?
Thanks in advance for the help!
#3 Help Me ! » Homework Problems - Please Help! » 2018-01-17 09:14:27
- Vedanti
- Replies: 1
1) Let F, G, and H be collinear points on the Cartesian plane such that FG/GH = 1. If F = (a, b) and H = (7a, c), then what is the x-coordinate of G?
2) The points (0,4) and (1,3) lie on a circle whose center is on the x-axis. What is the radius of the circle?
I'm really stuck on these...Can someone help? Thanks in advance!
#4 Re: Help Me ! » Help Again Please... » 2017-12-20 10:36:02
Thanks Bob!
#5 Help Me ! » Help Again Please... » 2017-12-20 03:21:43
- Vedanti
- Replies: 3
I’m really stuck on this problem:
Suppose f(x) is a function defined for all real x, and suppose f is invertible (that is the inverse of f(x) exists for all x in the range of f).
If the graphs of y=f(x^2) and y=f(x^4) are drawn, at how many points do they intersect?
Thanks in advance!
#6 Re: Help Me ! » Please Help! » 2017-12-20 03:15:05
Thanks a lot! I get it now!
#7 Help Me ! » Please Help! » 2017-12-19 13:11:37
- Vedanti
- Replies: 3
I'm really stuck on this math problem...does anyone get it?
Given that f(3)=5 and f(3x)=f(x)+2 for all x, find the inverse of f(11).
Thanks in advance! 
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