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#1 Re: Help Me ! » Quadratic equations (1-x-x^2) » 2018-01-21 08:06:13

Thanks but I can't understand how is( x ) multiplyed by( r)?

#2 Help Me ! » Quadratic equations (1-x-x^2) » 2018-01-20 18:14:23

Replies: 3

I thought that you can help me with this. I've seen this in some textbook and I don't know how do thay measured the product of equation ;

#3 Re: Help Me ! » Problem around modular arithmatic » 2018-01-03 00:56:52

Thanks again but another question: how can we find the group order because in the answer above,you mentioned it's 58 but how did you measured it before finding the answer?((sorry for asking a lot wink ))

#4 Re: Help Me ! » Problem around modular arithmatic » 2018-01-01 02:58:15

If you have multiplied 10^29 by 10^29 than ok. But how we should know to find 10^29 and than result its congruent to -1 in mod 59 and THEN multiply it by it-self to find out this answer?

#5 Re: Help Me ! » Problem around modular arithmatic » 2018-01-01 02:48:55

I still can't understand how you've found n+1=58 in step 3 and 4

#6 Re: Help Me ! » Problem around modular arithmatic » 2018-01-01 02:37:06

Thanks but what was fermat's little theorem and how you conclude n+1=58 by that?

#8 Help Me ! » Problem around modular arithmatic » 2018-01-01 01:43:01

Replies: 9

Solve for x ;
10^n+10^n-1+10^n-2+...+10^1+1 congruent to 0 (mod 59)

#9 Re: Help Me ! » Recurrence in division » 2017-12-31 00:09:52

Thanks for answering and efforts.but I meant that if we don't know how much is the length of recurring then we are not able to directly measure amount of nines  and know how many digits recurring. Something you've said is totally true but it's just about the time we know about recurrence.

#10 Help Me ! » Recurrence in division » 2017-12-30 06:08:08

Replies: 4

Is there any way to find out the length of recurrence in a division without actually dividing?
Like: 1/3= zero point 3 recurring -->( how to calculate that there's one digit recurring)

#11 Re: Help Me ! » Prime numbers importance » 2017-11-24 06:58:43

But a question. How do thay encrypt something with public key?

#13 Help Me ! » Prime numbers importance » 2017-11-22 06:33:04

Replies: 3

Can somebody tell me that why there's so much fuss about prime numbers?

#15 Help Me ! » AH^2=CH*BH in right angle triangle » 2017-11-21 05:35:10

Replies: 2

Assume you have right angle triangle called ABC that A=90.draw a perpendicular line to BC from A angle and label the point it met , H . Then we have AH^2=BH*CH. I will prove by pythagorean theorem BUT I don't know where is the mistake!

#17 Re: Help Me ! » Represent sqrt{2}+sqrt{3} on a number line » 2017-11-01 01:22:30

Thank you for answering. I'm saying that the second start point((suppose you've drawn sqrt{2} and this point is the second start point)) would not be exact. then, as you know we can't use pythagorean theorem because we can't say that we draw a line with size of A from a certain origin and then we can't have a triangle with a horizontal line in length of something wanted and therefore there would not be a hypotenuse in length of like sqrt{3} or something else.

#18 Help Me ! » Represent sqrt{2}+sqrt{3} on a number line » 2017-10-31 02:53:04

Replies: 4

I searched a lot about it but I haven't found a thing! I were assuming that you guys can help me. The question is just what I wrote in title ((Represent sqrt{2}+sqrt{3} on a number line)).what that make this diffrent is that it's not like adding an rational to irrational because there you had a certain start point and you draw a triangle and it would be done but in the problem that I mentioned when you draw first triangle you will have a point that doesn't exist((it's value is not accurate))! And therefore it's stupidness to draw another triangle from that point.Then, what to do?

#19 Re: Help Me ! » Probabilty of a family's children » 2017-10-13 06:14:37

THANK YOU SO MUCH!! I were struggling to understand this (binomial page really worked)

#20 Help Me ! » Probabilty of a family's children » 2017-10-12 05:25:09

Replies: 2

You have 3 children in a family . What is the probability of having 2 girls ?
I've confuesd . I've tryed this method but I don't know why it is not working!
First for n(s) we can say 2*2*2 (every child have two possibility)so it equals 8 then for n(a) we can say because we want 2 girls so 2 children would have just one possibility namely , 1*1*2 then it would equal to 2. But if you write down every possibilty it would be 3! My approach is the same thing for calculating sub sets of some (X) set that is n(s), and for n(A) as I've mentioned . So if ANYONE knows what's wrong or know a better way than write down all possibilties you can make me delighted by leaving it in the comment! THANK YOU;-)

#21 Help Me ! » adding vectors to each other » 2017-09-15 18:19:29

Replies: 1

I red somewhere about adding vectors would result in zero or nothing if they have these rules applied on them :
if there's a collection of vectors that all of them have the same length and any vector have equivalent degree between it-self and its adjacent one and sum of all degrees are 360 degrees then resultant vector would zero .
how's that possible ? please if anyone knows a proof write it below. thank you

#23 Re: Help Me ! » Polynomial » 2017-08-02 16:49:33

So ,,, we don't include negative exponents or a variable in denominator a part of polynomial just because we do not want to make polynomials hard to understand or a difficult thing . Is it just right for square root of a variable?

#24 Help Me ! » Polynomial » 2017-07-31 18:45:56

Replies: 6

Why something with negative exponent or a variable at denominator is not allowed to be called polynomial?(I know the rules of polynomial but I don't know why )

#25 Re: Help Me ! » Algorithms » 2017-03-20 23:24:34

Thanks for your answering.

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