Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 Re: Help Me ! » Help with Mean Value Theorem Problem » 2016-11-30 11:56:13

Thanks zetafunc!

One question: in order to use MVT again on f' to get an expression for f", what value do I use for f'(1/2)?  Do I use the f'(c) value that I found? [setting up MVT using f'(0) and f'(1/2)?]

Thanks!

#2 Help Me ! » Help with Mean Value Theorem Problem » 2016-11-30 08:09:28

mathattack
Replies: 2

Hello!

I've been trying to solve this proof, but only can provide examples, (e.g. y=2x^2).  Could someone help me with the proof?  Thanks!


Suppose f is a twice-differentiable function with f(0) = 0, f(1/2) = 1/2 and f ' (0) = 0. Prove that |f '' (x)| > or = 4 for some x in the interval [0,1/2].

#4 Help Me ! » Functions and Continuity » 2016-10-18 18:00:43

mathattack
Replies: 2

I'm having a little bit of difficulty with this question.  Could someone give some advice?

Consider the function:

f(x) = 1/b if x is rational and x = a/b in lowest terms and b>0
and f(x) = 0 if x is irrational.

Show that f(x) is continuous exactly at irrational points.



My thoughts so far: If a/b is in lowest terms, I'm guessing it means that and a and b are relatively prime?  So b would equal a/x, when x is a rational number?  I'm then getting that f(x) = x/a, when x is a rational number, but why would this not be continuous for any intervals?  Shouldn't the interval of a from (0,1] work at least? 

Any help would be much appreciated!

#5 Re: Help Me ! » Vector Geometry Proof » 2016-10-18 17:48:20

Hi Thickhead,

Sorry for the slow response.  Your response was awesome and super helpful!  Thank you so much smile

#6 Help Me ! » Vector Geometry Proof » 2016-09-28 08:08:31

mathattack
Replies: 3

Hello! 

I've been working out the following question with vectors, but am having a little bit of problems with two things:

1. deriving the position vector of the various centroids
2. deriving the line through the centroid perpendicular to the other side.

Any help would be great!


Pentagon ABCDE is inscribed in a circle. For any edge of ABCDE, we can draw the line perpendicular to that edge that contains the centroid of the remaining three vertices. Show that these 5 lines are concurrent.

#7 Re: Help Me ! » Vector Geometry » 2016-09-28 07:53:01

Thank you both!  I was able to work out both solutions.  I hadn't realized before that once I got my equations for both vectors, after setting them equal to each other I could separate each variable and solve for when they equaled zero!  I didn't expect that to work but it did.  Thank you both for your insight and help.

#8 Re: Help Me ! » Vector Geometry » 2016-09-21 07:13:41

One more, with similar issues.  Any help would be great, thanks!


Let G denote the centroid of triangle ABC. Let M and N be points on sides AB and AC, respectively, so that M, G, and N are collinear, and AM/MB = 5/2. Find AN/NC.

#9 Help Me ! » Vector Geometry » 2016-09-21 07:12:11

mathattack
Replies: 5

I've been working on this problem using vectors, but can't quite finish it.  I wrote out two equations, one from A to S, the other from B to T, and set them equal to each other.  I just can't figure out what the two parameters would be.  Can someone help?  Thanks!


In triangle ABC, S is a point on side BC such that BS:SC = 1:2, and T is a point on side AC such that AT:TC = 4:3. Let U be the intersection of AS and BT. Find AU:US.

#11 Help Me ! » Geometry, Polygon, Unit Circle, Roots of Unity proof » 2016-07-13 11:36:44

mathattack
Replies: 2

Hello!

I'm having some trouble with the following question, could anyone help please?

1.  A regular polygon P is inscribed in a circle ΓΓ. Let A, B, and C, be three consecutive vertices on the polygon P, and let M be a point on the arc AC of ΓΓ that does not contain B. Prove that

MA⋅MC=MB2−AB2

- I tried using law of cosines and substituting, but I got stuck here:

(MB)^2 - (AB)^2 = (MA)^2 + 2(AB)(MA)Cos(<BCM) = (MC)^2 - 2(BC)(MC)Cos(<BCM)

Any help would be great, thanks!

#12 Help Me ! » Trig and Sequences » 2016-05-26 08:35:03

mathattack
Replies: 8

Hi!  I'm having quite a bit of trouble with this problem, could someone help?  I really want to know how to solve it.  I set up the triangle, but can't figure how to use the tan and cot to form geometric or arithmetic progressions.  Thanks!


In triangle ABC, AB = BC, and BD is an altitude. Point E is on the extension of AC such that BE = 10. The values of tan CBE, tan DBE, and tan ABE form a geometric progression, and the values of cot DBE, cot CBE, and cot DBC form an arithmetic progression. What is the area of triangle ABC?

#13 Re: Help Me ! » Cool geometry » 2016-03-23 04:29:06

Thanks for your help Bobbym and Bob! 

Both suggestions got me going and helped me to confirm my answer too.  I was able to get it with similar triangles in the end, a la power of a point:

If you label the point where CP crosses AB and call it D, then

6x5⍻2 = CDxDP = BD(10-BD), also 5⍻2xCD = 8xBD

I ended up with BD=30/7, CD = 24⍻2/7 & DP = 25⍻2/7, which matched Bobbym's 7⍻2 for CP.

You both are great by the way.  I've been following the forum for a while now, but only recently thought to add some posts of my own.  Till next time.

#14 Help Me ! » Cool geometry » 2016-03-22 08:17:05

mathattack
Replies: 4

Hi! This problem looks cool but it's giving me a little trouble.  Could someone help?

Thanks!!


In triangle ABC, AB = 10, AC = 8, and BC = 6. Let P be the point on the circumcircle of triangle ABC so that angle PCA = 45. Find CP.

#16 Re: Help Me ! » Square & Triangle question » 2016-03-08 09:28:40

Thanks for the answer!  How did you get it?

#17 Help Me ! » Square & Triangle question » 2016-03-07 15:25:37

mathattack
Replies: 11

In rectangle ABCD, we have AD = 3 and AB = 4. Let M be the midpoint of AB, and let X be the point such that MD = MX, angle MDX = 77, and A and X lie on opposite sides of DM. Find angle XCD, in degrees.

I'm trying to find out how to solve this question without using trig.  Could someone help?

Board footer

Powered by FluxBB