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#2 Help Me ! » Expectation Questions (Probability) » 2016-03-06 11:32:54

jubadedo
Replies: 3

1. If E[X] = 2 and var(X) = 3, what is E[(X + 1)2]?

2. If E[X] = 2 and var(X) = 3, what is var(3X + 2)?

3. Let X be a Bernoulli random variable with p=.25.  Find E[4X5-1].

Hi guys, thank you so much for helping me out throughout this year. I really appreciate it! I am confused with how to solve these problems. If anyone could provide assistance, I would really appreciate it. Thanks so much!

#3 Re: Help Me ! » More Probability Help » 2016-02-15 21:37:12

Okay so here's what I think are the answers, thanks again guys you're awesome for helping me out!

1. 0.7 * 0.02 + 0.3 * 0.05 = 0.029

2. .(0.7 * 0.02 + 0.3 * 0.05) /.7 I think

3. (0.7 * 0.02 + 0.3 * 0.05 ) * (0.7 * 0.02 + 0.3 * 0.05 ) = 0.000841

#4 Help Me ! » More Probability Help » 2016-02-15 05:11:11

jubadedo
Replies: 7

Thanks guys, I really appreciated your help on the last questions. I need help though now. I don't understand how you approach and solve these problems...

An auto store has two suppliers for a given part. The store orders from Supplier A 70% of the time, and supplier B 30% of the time. Supplier A's parts are defective with probability 0.02, and supplier B's parts are defective with probability 0.05.


1. If I buy a part, what is the probability that it is defective?


2. I buy a part and it is defective. What is the probability that it comes from Supplier A?


3. Let's assume that the parts arrive from the factory in boxes of 10; if I pick two parts from the same box then I know they are from the same factory (but I don't know which factory they are from). If I buy two parts from the same box, what is the probability that they are both defective? Hint: What is the probability that two parts from supplier A are both defective? How about two parts from supplier B?

#5 Re: Help Me ! » Probability Help » 2016-02-08 15:59:51

Thank you so much Relentless big_smile

I appreciate the help a lot!!!!!

#6 Re: Help Me ! » Probability Help » 2016-02-08 15:52:59

Hi Bobbym,

Okay I think I've made progress

1. Okay we have six donuts

4 of them have already been decided, so we need to pick 2. So there are 9 flavors to choose from and order doesn't matter and I think there's no replacement? Either way, it's C(2+9-1,2) = C(10,2) = 45.

2. I have three vowels that I can place vowels in 7 different ways, then I can have 6! constant order and 3! vowel  after that, so that's 7 x 6! x 3! = 30240

3. I forget how to do it but I have an idea I think...

4. I have no idea :*(

#7 Help Me ! » Probability Help » 2016-02-08 12:09:50

jubadedo
Replies: 6

Hi guys,
I hope everyone's been well.

Could someone explain how they figure out these 4 problems? I would truly appreciate it.

1. How many ways are there to choose one-half dozen donuts from 9 varieties so that there are exactly 4 glazed?


2. How many distinct ways are there for arranging the letters in “arranging” so that the vowels are together in 
any order?


3. A box of 10 RAM chips contains three defective and seven good chips. Three chips are chosen at random without replacement from this box and tested. What is the probability that exactly one of the chips is defective?

4. On a given day, there is a 0.7 probability that it is sunny. Jane walks past an ice cream stand every day. When it is sunny, the probability that she buys an ice cream is 0.8. When it isn't sunny, the probability that she buys an ice cream is 0.1.
What is the probability that Jane buys an ice cream?

#8 Help Me ! » Is this the correct result for this formula? » 2016-01-22 09:25:55

jubadedo
Replies: 2

Screen_Shot_2016_01_22_at_3_16_12_PM.png


This is a way (I think) to convert binary strings to floating point using upper and lower bounds. I keep getting the answer 1.61225 and I literally type in the my calculator the numbers from the picture. For context the formula, takes the binary string (00110) representation of the value 6 with an upper bound of 7.3 and a lower bound of 1.5 with a binary string length of 5 and computes that value using the actual value 6 in the formula. Can someone explain what I'm doing wrong?

#9 Help Me ! » Double Integrals Using Polar Coordinates » 2015-12-08 16:25:45

jubadedo
Replies: 1

If someone could, I just don't understand how you set up these double integrals. I know it involves using r and such, but I keep messing up the final computation. If someone could just go steo-by-step through each problem and explain how you set them up, I think I can compute the actual double integral. I just need to understand how to start off the equations. I had to split up the pages by screenshots, so I apologize if one or two of them seem cut off. All pages should continue to the next page. I just really, really could use some help in understanding these problems. Thank you so much!

https://screencloud.net/v/6oMd
https://screencloud.net/v/Fp3y
https://screencloud.net/v/iaT3

#11 Help Me ! » Simplifying this function for partial differentiation » 2015-12-07 21:34:13

jubadedo
Replies: 3

Hi guys,
I'm studying for this upcoming test. In one of the examples when they find f(x,y) for the function


They differentiate with respect to x first and get

then they simplify it to

Can someone please explain how they reached this step? I'm utterly confused over how to simplify it to that form. I know the y in the numerator comes from the y in the original function, so I guess my question is how they simplified the denominator so elegantly. Thank you very much!

#12 Re: Help Me ! » Differential Equation » 2015-10-28 15:50:40

Thank you so much for the help! big_smile

#13 Help Me ! » Differential Equation » 2015-10-20 17:26:27

jubadedo
Replies: 2

Hi guys I'm trying to understand these multiple differential equations and their solutions for an exam. If it's okay, I posted the solution to the example and I have a question: "In the example it says "Thus, 

  ,
, and so
and
How did he use the two equations to reach the conclusion that
  ? I feel like I'm missing something obvious, and I feel so dumb. Anyways, thanks guys so much for your help, any input would be appreciated.

Here's the problem (sorry it cut off text in one of the pictures, luckily I'm only concerned with the solution)

Screen_Shot_2015_10_21_at_12_11_10_AM_2.png

Screen_Shot_2015_10_21_at_12_11_19_AM_2.png

Screen_Shot_2015_10_21_at_12_11_39_AM_2.png

#14 Help Me ! » Explanation of this integration » 2015-09-25 19:58:14

jubadedo
Replies: 2

Hello everyone again,

I just wanted to ask if anyone could explain the solution of this integral

to me.

My instructor's notes say to use the fact that

But isn't the expression in the original integral

? If someone could explain the reasoning behind this or provide step-by-step solution of the problem it would be greatly appreciated. Thank you!

#15 Help Me ! » Integration by Parts with natural logs » 2015-08-29 02:35:32

jubadedo
Replies: 3

Hi guys, so I'm working on this problem, and I think I'm (hopefully) close to a solution and I'm just messing up when it comes to simplifying everything. Of course, since this is my own homework, I'm not asking for an answer, just simply a hint or telling me what I'm doing wrong smile. The problem is this:

   

(I don't know if it will show or not but the problem is the integral from 1 to 2 of 5ln(4x)dx)
So I used


then I said

And when I integrated I got the answer

I factored out a 5x for to get

Then I plugged in the bounds and got

The ones cancelled out and then I factored out a 5 to get

I forget how but I thought I could reduce it to

but it was wrong  hmm

Could someone please guide me to the correct answer? Am I integrating wrong or condensing the logarithms incorrectly or something else?

#16 Help Me ! » Probability Questions » 2015-04-05 13:45:05

jubadedo
Replies: 3

Hello guys, sorry to keep pelting you with questions. Again, these questions also keep stumping me.
Jill has a stack of 8 cards consisting of Jack of Spades, Jack of Hearts, Jack of Diamonds, Jack of Clubs, Queen of Spades, Queen of Hearts, Queen of Diamonds, and Queen of Clubs. Jill shuffles the stack then deals out the top 3 cards. What is the probability that two of the cards dealt were Jacks and one was a Queen?

My teacher tells me the answer is 3/7, but I still can't comprehend how he gets to that solution. I keep doing

, but that is not the correct set-up for the problem. I would love it if someone pleased explained how you derive that answer. 

Ellen enters a convenience store. The probability that she buys bread is 60%, the probability that she buys milk is 50%, and the probability that she buys both bread and milk is 30%. What is the probability that she will buy either bread or milk or both? (nearest percent).

I am completely stumped on this one. :*(

#17 Re: Help Me ! » Rate Problems » 2015-04-05 13:20:43

Thanks a lot Bob for explaining it so clearly big_smile. I understand what the questions means now.
I got 15 windows for the first question and 21 crates for the second question. Is that correct?

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