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#1 Re: Help Me ! » Permutations » 2015-01-12 05:58:14

So 24 x 13 x 60 x 13 x 30 = 7,300,800 possible codes? Sounds about right.. thanks.

#2 Re: Help Me ! » Permutations » 2015-01-11 21:53:47

Hi Maths Boffins! I have a permutation / combination problem and it's giving me headaches!

I have to work out how many unique codes I can get given the following restrictions..

An eight digit code must look like this:
07H15Y10

First two digits: Only possible from 00 to 23
Third digit: Only possible from A to M
Fourth and fifth digits: Only possible from 00 to 59
Sixth digit: Only possible from N to Z
Last two digits: Only possible from 01 to 30

Any help with this would be much appreciated... Thanks

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