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#2 Re: Help Me ! » Trigonometric Identities Problem » 2015-01-11 04:36:28

How about from the RHS:

RHS=Sin^2xSin^2xSec^x

(1-Cos^2x)Sin^2x(1/Cos^2x)

(Sin^2x/Cos^2x)-(Cos^2xSin^2x/Cos^2x)

Tan^2x-Sin^2x

Correct?

I Used the RHS because I still didn't manage from the LHS.

#3 Help Me ! » Trigonometric Identities Problem » 2015-01-09 09:24:37

BonaviaFx
Replies: 4

I'm Stuck on this one:

tan^2x-sin^2x ≡ sin^4x*sec^2x

Need some help hmm

#5 Re: Help Me ! » Logarithm Problem » 2014-12-19 05:39:23

Here is the link to the picture smile http://prntscr.com/5in3ie

#6 Help Me ! » Logarithm Problem » 2014-12-19 03:24:21

BonaviaFx
Replies: 5

If log (base y) x = a and log (base z) x = b where x ≠ 1 , express the following in terms of a and b

a) log (base y) yz

b) log (base x) y/z

If y + z =1 show that 1/a = log (base x) 1-x^1/b

I found this hard, if question is unclear and can take a picture of it.

#7 Re: Help Me ! » Factor & Remainder Theorem » 2014-12-16 07:19:28

Also bob with your reasoning you helped me solve an even harder question thanks in advance. I'm guessing you helped me find the way big_smile

#8 Re: Help Me ! » Factor & Remainder Theorem » 2014-12-16 07:07:28

I got it, thanks and yes its does = to 0. smile

#9 Help Me ! » Factor & Remainder Theorem » 2014-12-16 06:26:19

BonaviaFx
Replies: 3

If the expressions x^2+ax+b and 3x^2 +b have (x-c) as a common factor, where a, b and c are non zero show that 3a^2 + 4b=0.

I have a load of questions, I'm only posting the ones I can't solve. Thanks!

#10 Re: Help Me ! » Factor Theorem » 2014-12-15 05:17:37

Hi Bob smile

I uploaded a pdf file of the syllabus here:
http://www.filedropper.com/am27

#11 Re: Help Me ! » Factor Theorem » 2014-12-15 00:32:35

Sorry, but it doesn't matter which to use. The title is misleading and your working is correct. Thanks again and I'm new to the forums, I will be posting frequent questions. This is because I am doing pure mathematics on my own and will sit for the exam.

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