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#1 Re: Help Me ! » Probability with multiple variables » 2013-12-22 23:15:41

qDOS

Hm, so P(no tens) would be (9/10)^3. And 1 - (9/10)^3 makes 27.1%

That seems reasonable smile I expected it to be something just short of 30%

Thanks a lot!

#2 Help Me ! » Probability with multiple variables » 2013-12-22 21:30:35

qDOS
Replies: 3

Greetings,

I'm wondering how I might calculate the probability of rolling at least one '10' when rolling three ten-sided dice. I know it cant simply be (3x10)% chance since rolling ten dice wont give me a 100% chance of rolling at least one 10.

Can you help me? I'd like to understand how to do problems like this.

Happy holidays!

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