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#1 Re: Help Me ! » needed: formula for curved trajectory to hit specific target » 2013-02-19 18:19:54

helllo

velocity is 10 m/s

at 10 m/s it travels approximately 489 m before touching the ground, and this is quite a large distance (non practical )

I think there is no drag , that is why the length of projectile is so long.

Could you help me inserting drag in this formula
x = vt cos ?
y = vt sin ? - ½ g t²

here you can find some formula for drag, http://en.wikipedia.org/wiki/Drag_%28physics%29

and let me tell you i am little dumb in mathematics big_smile
Thanks

EDIT : I want to draw the path of projectile.

#2 Re: Help Me ! » needed: formula for curved trajectory to hit specific target » 2013-02-19 01:22:01

sorry for reviving this thread again smile

here in this formula
x = vt cos ?
y = vt sin ? - ½ g t²

v (velocity) is the initial velocity or a constant velocity ? will velocity changes with time ? or it remains constant ?

In my last post i ask this.
here is the projectile i get using this formula http://imgur.com/axCKwsP

Don't you guys think for 60* angle this is Quite a large projectile ?
with a initial velocity of 10 and 60* angle it goes to 489 m, let me tell you i am decreasing the initial velocity and increasing time by 0.1 at each step.
I dont know i am doing it in right way or not big_smile
can any one suggest me any thing ?

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