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#1 Re: Help Me ! » Limits » 2006-09-23 03:12:22
Hey,
I think that for #1 the concept is that the higher the power is, the smaller the number becomes. It eventually becomes so small, it can be considered to be 0. Whether X is -1 < X < 0 -or- 0 < X < 1.
The same thing goes for #2. Try putting some large values for n. You'll find the larger you go, the smaller the number becomes. Like 2^99 / 99! = 6.79150329946 x 10^-127 This is VERY small. So small, it can be considered zero.
Hope this helps
#2 Re: Help Me ! » Binomial Theorem question » 2006-09-21 12:14:08
I'm sorry, but I don't see how the square root of dL/L gives you (1/2)(dL/L)......?????
Perhaps if you told us the original question, along with how you got to your answer, we could help you out a bit more...
Perhaps...I thought my original question was sufficient enough, though.
I got as far as they did (the same way) up to the part where:
Eab = (1 + (dL/L))^(1/2) - 1
Take a look at the image (link). That's everything.
#3 Help Me ! » Binomial Theorem question » 2006-09-21 08:18:28
- Malik641
- Replies: 2
Hey guys,
my question is how do you apply the binomial theorem when the quantity is raised to a non-integer value?
Specifically, (a+b)^(1/2)
I had a homework problem for my mechanics of materials class, and I got "x" far. I checked the answer, and they went further with it, calling out the Binomial Theorem as the reason for taking it a step further.
my answer was:
[1+(dL/L)]^(1/2) - 1
then their answer was (same as mine, then one step further):
1 + (1/2)(dL/L) ... - 1 "Binomial Theorem"
= (0.5*dL)/L
I don't know why this is racking my brain so hard...I think it's because of the 3 dots "..."
Thanks in Advanced 
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