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#1 Re: Help Me ! » Tricky Coin Flipping Probability Problem » 2011-08-18 21:33:02
Now the hard work has been done 
I wonder if we can expand to a general formula:
If we have a number of events, n, with each event having a probability of success p, and the maximum deviation we want is d. What would our formula look like (I've had a go but not so sure)?
#2 Re: Help Me ! » Tricky Coin Flipping Probability Problem » 2011-08-18 05:22:28
Hi gAr;
I think you found another way to do it.
Possibly he means this:
Left out any simplification that might hide his method. This is what I was looking for, for two days. A formula! No one had it.
I think I understand it, but I am not sure what you are doing here:
How do I calculate this in Excel?
#3 Re: Help Me ! » Tricky Coin Flipping Probability Problem » 2011-08-18 04:58:25
I'm here!! I'm trying to digest all your formulae and get it into some programme code to run the calcs.
#4 Re: Help Me ! » Tricky Coin Flipping Probability Problem » 2011-08-14 05:48:39
Hi bobbym, what I am interested is the probability I can be down 15 at any point during the 100 flips. I'm sure this must be possible, it's just a case of how many times it's possible.
e.g. if I lost the first 15 games, I would not be able to continue.
#5 Re: Help Me ! » Tricky Coin Flipping Probability Problem » 2011-08-13 21:04:16
Is it possible to expand on your answer? I'd like to know how it's worked out.
#6 Help Me ! » Tricky Coin Flipping Probability Problem » 2011-08-13 11:40:28
- russellhq
- Replies: 69
Say I'm offered to play a game where a coin is flipped 100 times, and after each flip if it's heads I win a dollar and if it's tails I lose a dollar. And if I make it to the end without losing all my money , I win 50 dollars.
I only have 15 dollars, should I play the game?
Ie what is the probability I will go broke?
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