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#1 Re: This is Cool » 0.9999....(recurring) = 1? » 2008-04-30 12:49:13

first we should know that 0.999...... is not a number.
Note


[math0.99\1-\frac{1}{10^2}math]
so

Let

when we say that 0.999......=1,we just mean that

Here is a intitutive proof:




we can see that as n goes bigger and bigger,0.999...... goes more and more close to 1,but it's not accurate in mathematics.I will give a precise proof.
obviously 0.999......<1,if 0.999...=A where A between 0 and 1,then we can easily find some N such that

a contridition derived.

#2 Re: Exercises » Evaluate Integral » 2008-04-30 11:51:58

let sinx=t for all x in [0,pi/2],then we got cosx=sqrt(1-x^2).so,(sinx)^25/[(sinx)^25+(cosx)^25]=t^25/[t^25+(\sqrt (1-x^2))]25=f(t).we can get the extreme values of f(t) as follows:
1.find f'(t);
2.find t such that f'(t)=0;for example t1,t2;
3.f(t1),f(t2) is the maxium and inum
4.estimate the integral by the extreme value.

#3 Re: Help Me ! » easy logarithm that i can't solve! :P » 2008-04-21 01:19:14

we call logarithm function with base 10 common logarithm and it was denoted by lgx. TheDude had gave you the right answer.

#4 Re: Help Me ! » limits » 2008-04-21 01:13:52

since sin(1/x) is bounded so there exist a number M such that |sin1/x|<M,then |x*sin(1/x)|<M|x|
so it approaches 0 as x approaches 0. in fact we can let M=2.

#5 Re: Help Me ! » Area between functions » 2008-04-21 00:25:15

to calcute area between some functions. please follow these steps:
step1: give their graphs togher.
step2: describe the area,remember we have two type of describtions called x-type and y-type.
step3: transffer the area to integration.
step4: calcute the integration.

#6 Re: Help Me ! » Undefined? » 2008-04-21 00:17:39

∞ is not a number,so 0*∞ is undefined.if it is defined,what the result will be?since 0 is pulling the result to 0 while ∞ pulling the result to ∞,who will win at last? no one knows. but there is a type of limit who is "0*∞" for example (x-1)/(x^2-4*x+3) where x approaches 1.

#7 Introductions » find friends in mathematic funs » 2008-04-21 00:05:57

moxiuming
Replies: 6

Hi,everybody,I am new here.
I have learned mathematics for many years and I admit I love them. I'm here to share my problems and pleasure in mathematics with you.
thanks,good luck for everyone.:P

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