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#1 Re: Euler Avenue » ζ(2n). » 2007-05-11 03:31:27

Zhylliolom wrote:
/*But this is no time for sightseeing, we have an equation to derive. Let us consider the known identity(whose proof is left to the reader as an exercise wink)

*/
I give up, would you give me a hint?

#2 Re: Euler Avenue » ζ(2n). » 2007-05-11 03:30:07

Zhylliolom wrote:
/*But this is no time for sightseeing, we have an equation to derive. Let us consider the known identity(whose proof is left to the reader as an exercise wink)

*/
I give up, would you give me a hint?

#3 Help Me ! » Limits and Bernoulli Numbers » 2007-05-11 03:27:26

nefqu
Replies: 0

Hi, this is my first post.  I know that:

Sorry I don't know how to do derivatives in LaTeX.
Can someone help me prove the above statement?

#4 Re: Help Me ! » Calculus Question » 2007-05-11 03:25:53

These are two coupled equations, to solve it differentiate both sides, to get:
y''=x'=y
x''=y'=x
The general solution to this, where C and D are constants, is C sinh(t) and D cosh(t).  Using your initial conditions:
x(0)=1
y(0)=0

x=cosh(t)
y=sinh(t).

Does this help?