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#1 Re: Exercises » Differential Calculus Ex.1 » 2007-04-21 05:00:54

In the second problem :
s=2t³-15t²+36t-70

ds/dt = 6t²-30t+36

Initial velocity is when t = 0;
Initial velocity = 36

Time when velocity is zero is :
t = 30±√(900-864)/12 = 30 ± 6/12
t=3 or 2

acceleration = dv/dt = 12t-30
Time when acceleration is zero is : 2.5

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