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Well I figured out that one, id show what I came up with but I dont have the slightest clue how to show a graph like that on the computer.

New problem now: 2x² - 3xy - 2y² + 10 = 0

a = 2, b = 3, c = -2

plugging it in, tan2θ = -3/(2 -(-2)) -3/4

using the reference angle from tan-¹ 3/4 I get 2θ = 143.2 so the angle of rotation would be 71.6°

Plugging that into the other forumlas im gonna get a big mess of decimals....

Wonder if there is any way to keep it rationalized????

I simplified them into x = (√(3)x' - y')/ 2 and y = (x' + √(3)y')/2. Plugged them both back into

7x² - 6√(3)xy + 13y² - 16 = 0. And got this for the standard form (x')²/ 4 + (y')²/1 = 1. Im hopeing that is right. How would I go about graphing that, im not sure where to start?

The equation given is 7x² - 6√(3)xy + 13y² - 16 = 0. Its an ellipse that is rotated, but im not sure how to find that degree of rotation

**im really bored**- Replies: 11

I dont think im really understanding this topic. For the problem xy - 1 = 0, how do you get the angle of the rotation out of that?

Ive got another one too, what is a synonym for paris(no idea what it had to do with chemistry), 12 letters, and there is a "d" as the seventh letter from the top, unless a carnelian relative isnt sard. I was thinking cityoflights. It fits but no d. Mabye it isnt sard...

**im really bored**- Replies: 7

What is the Greek letter to symbolize angular velocity?

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