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NVM I re-read it and understand. May I also elaberate on this as well.
Any way you can repeat in newbie terms. I some what under stand the concept, but im still a little confused.
I am a computer programmer and have a question reguarding probability.
If a player is sitting at a table of 10 people and has of 48% chance of winning. What would his chance of winning be if there were 7 people at the table, instead of 10.
Any forumals and or links to other sites reguarding calculations simular to this would be greatly appriciated.
Thanks!
My understanding:
I know it isn't as easy as doing 10/.48 = 7/x
I was thinking that there are 9 other players who combined have a 52%, or 5.78% per player, chance of beating me. If 3 players leave, at 5.78% per player, then do I have a 17.34% (3 * 5.78%) more of a chance of winning... equaling 65.34%?
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