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#1 Re: Help Me ! » Comparison Theorem » 2006-03-05 18:23:45

Alk

I don't think I understand the actual process of determining this solution. So far I have
f(x) >= g(x) >= 0

f(x) = dx/(x + e^2x)


Would someone be willing to explain the steps in solving this?

#2 Help Me ! » Comparison Theorem » 2006-03-05 16:51:50

Alk
Replies: 3

The problem I am working on is:

Use the comparison theorem to determine whether the integral is convergent of divergent. The integral is dx/(x + e^2x) from 1 to infinite.


My question is why does this not work.
For x >= 1, 1/(x+ e^2x)   <    1/x, therefore 1/x+e^2x is divergent.

But the correct answer is

For x >= 1, 1/(x+e^2x)   <   1/e^2x, therefore 1/x+e^2x is convergent.

Why doesnt mine work?

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