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Mike wrote:

Hey there, just stumbled across your forum. I run the web site www.calculus-help.com and am happy to post a solution. Just follow this link:

http://www.calculus-help.com/answers/2006_0131.gif

Do note that you shouldn't leave

yin your answer; instead substitutey= 2x^(2x) back in for it at the end

I just went ahead and registered after I posted the above solution, so you can direct comments and questions to me at this username.

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